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What are the common approximations made in the analysis of heat exchangers?

Short Answer

Expert verified
Answer: The common approximations made in the analysis of heat exchangers include assuming steady-state operation, constant fluid properties, negligible heat loss, laminar flow, and using the log-mean temperature difference (LMTD) method. These approximations simplify the calculations and make the design process more manageable.

Step by step solution

01

Introduction

A heat exchanger is a device used to transfer heat between two or more fluids without allowing them to mix. They are widely used in various industries such as power generation, chemical processing, and heating, ventilation, and air-conditioning (HVAC) systems. In the analysis of heat exchangers, certain simplifying approximations are made to make the calculations more manageable.
02

Steady-State Operation

One common approximation made in the analysis of heat exchangers is assuming steady-state operation. This means that all properties and flow rates within the heat exchanger remain constant with time. This simplification enables the use of basic energy and mass balance equations to describe the heat exchanger's behavior, avoiding the need to solve more complex time-dependent equations.
03

Constant Fluid Properties

Another common approximation made in heat exchanger analysis is assuming constant fluid properties. In reality, fluid properties such as density, specific heat, and thermal conductivity may vary with temperature and pressure. However, in many cases, the variations in these properties are small and can be neglected. By assuming constant properties, the calculations involved in the analysis process become more straightforward.
04

Negligible Heat Loss

In heat exchanger analysis, it is often assumed that there is negligible heat loss from the exchanger to the environment. This is because heat exchangers are typically well insulated to minimize any external heat loss. By assuming no heat loss, the thermal energy transfer between the fluids can be accurately estimated based on the temperature changes in the fluids.
05

Laminar Flow

In some cases, the analysis of heat exchangers assumes laminar flow, especially when dealing with compact or micro heat exchangers. Laminar flow is a condition wherein the fluid flows smoothly in parallel layers with no disruption or mixing. This assumption simplifies the calculation of heat transfer coefficients and pressure drop in the heat exchanger. However, it is important to note that this approximation may not be valid for larger heat exchangers where turbulent flow and mixing could occur.
06

Log-Mean Temperature Difference (LMTD)

Lastly, the log-mean temperature difference (LMTD) method is a widely used approximation for calculating the overall heat transfer rate in a heat exchanger. The LMTD method assumes that the heat transfer rate is uniform across the heat exchanger and calculates an average temperature difference to estimate heat transfer. Although this method is not applicable to all heat transfer situations, it provides a good approximation for many cases with parallel flow, counter-flow, and co-current flow configurations. In conclusion, the common approximations when analyzing heat exchangers are steady-state operation, constant fluid properties, negligible heat loss, laminar flow, and the log-mean temperature difference (LMTD) method. These approximations simplify the analysis and aid in the design process.

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Most popular questions from this chapter

Discuss the differences between the cardiovascular countercurrent design and standard engineering countercurrent designs.

In a parallel-flow, liquid-to-liquid heat exchanger, the inlet and outlet temperatures of the hot fluid are \(150^{\circ} \mathrm{C}\) and $90^{\circ} \mathrm{C}\( while those of the cold fluid are \)30^{\circ} \mathrm{C}$ and \(70^{\circ} \mathrm{C}\), respectively. For the same overall heat transfer coefficient, the percentage decrease in the surface area of the heat exchanger if counterflow arrangement is used is (a) \(3.9 \%\) (b) \(9.7 \%\) (c) \(14.5 \%\) (d) \(19.7 \%\) (e) \(24.6 \%\)

Cold water $\left(c_{p}=4.18 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\( enters a counterflow heat exchanger at \)18^{\circ} \mathrm{C}\( at a rate of \)0.7 \mathrm{~kg} / \mathrm{s}$ where it is heated by hot air \(\left(c_{p}=1.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) that enters the heat exchanger at \(50^{\circ} \mathrm{C}\) at a rate of $1.6 \mathrm{~kg} / \mathrm{s}\( and leaves at \)25^{\circ} \mathrm{C}$. The maximum possible outlet temperature of the cold water is (a) \(25.0^{\circ} \mathrm{C}\) (b) \(32.0^{\circ} \mathrm{C}\) (c) \(35.5^{\circ} \mathrm{C}\) (d) \(39.7^{\circ} \mathrm{C}\) (e) \(50.0^{\circ} \mathrm{C}\)

In a chemical plant, a certain chemical is heated by hot water supplied by a natural gas furnace. The hot water $\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( is then discharged at \)60^{\circ} \mathrm{C}$ at a rate of \(8 \mathrm{~kg} / \mathrm{min}\). The plant operates \(8 \mathrm{~h}\) a day, 5 days a week, 52 weeks a year. The furnace has an efficiency of 78 percent, and the cost of the natural gas is \(\$ 1.00\) per therm ( 1 therm \(=105,500 \mathrm{~kJ}\) ). The average temperature of the cold water entering the furnace throughout the year is \(14^{\circ} \mathrm{C}\). In order to save energy, it is proposed to install a water-to-water heat exchanger to preheat the incoming cold water with the drained hot water. Assuming that the heat exchanger will recover 72 percent of the available heat in the hot water, determine the heat transfer rating of the heat exchanger that needs to be purchased, and suggest a suitable type. Also, determine the amount of money this heat exchanger will save the company per year from natural gas savings.

A single-pass crossflow heat exchanger with both fluids unmixed has water entering at \(16^{\circ} \mathrm{C}\) and exiting at \(33^{\circ} \mathrm{C}\), while oil $\left(c_{p}=1.93 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right.\( and \)\left.\rho=870 \mathrm{~kg} / \mathrm{m}^{3}\right)$ flowing at \(0.19 \mathrm{~m}^{3} / \mathrm{min}\) enters at $38^{\circ} \mathrm{C}\( and exits at \)29^{\circ} \mathrm{C}$. If the surface area of the heat exchanger is \(20 \mathrm{~m}^{2}\), determine \((a)\) the NTU value and \((b)\) the value of the overall heat transfer coefficient.

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