Chapter 11: Problem 148
Discuss the differences between the cardiovascular countercurrent design and standard engineering countercurrent designs.
Chapter 11: Problem 148
Discuss the differences between the cardiovascular countercurrent design and standard engineering countercurrent designs.
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Get started for freeA crossflow air-to-water heat exchanger with an effectiveness of \(0.65\) is used to heat water \(\left(c_{p}=4180\right.\) $\mathrm{J} / \mathrm{kg} \cdot \mathrm{K})\( with hot air \)\left(c_{p}=1010 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\(. Water enters the heat exchanger at \)20^{\circ} \mathrm{C}$ at a rate of \(4 \mathrm{~kg} / \mathrm{s}\), while air enters at $100^{\circ} \mathrm{C}\( at a rate of \)9 \mathrm{~kg} / \mathrm{s}$. If the overall heat transfer coefficient based on the water side is $260 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, determine the heat transfer surface area of the heat exchanger on the water side. Assume both fluids are unmixed. Answer: \(52.4 \mathrm{~m}^{2}\)
Write an essay on the static and dynamic types of regenerative heat exchangers, and compile information about the manufacturers of such heat exchangers. Choose a few models by different manufacturers and compare their costs and performance.
Water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) is to be heated by solarheated hot air $\left(c_{p}=1010 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)$ in a double-pipe counterflow heat exchanger. Air enters the heat exchanger at \(90^{\circ} \mathrm{C}\) at a rate of \(0.3 \mathrm{~kg} / \mathrm{s}\), while water enters at $22^{\circ} \mathrm{C}\( at a rate of \)0.1 \mathrm{~kg} / \mathrm{s}$. The overall heat transfer coefficient based on the inner side of the tube is given to be $80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The length of the tube is \)12 \mathrm{~m}\(, and the internal diameter of the tube is \)1.2 \mathrm{~cm}$. Determine the outlet temperatures of the water and the air.
An air handler is a large unmixed heat exchanger used for comfort control in large buildings. In one such application, chilled water $\left(c_{p}=4.2 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)$ enters an air handler at \(5^{\circ} \mathrm{C}\) and leaves at \(12^{\circ} \mathrm{C}\) with a flow rate of \(1000 \mathrm{~kg} / \mathrm{h}\). This cold water cools air \(\left(c_{p}=1.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) from \(25^{\circ} \mathrm{C}\) to \(15^{\circ} \mathrm{C}\). The rate of heat transfer between the two streams is (a) \(8.2 \mathrm{~kW}\) (b) \(23.7 \mathrm{~kW}\) (c) \(33.8 \mathrm{~kW}\) (d) \(44.8 \mathrm{~kW}\) (e) \(52.8 \mathrm{~kW}\)
Hot water coming from the engine is to be cooled by ambient air in a car radiator. The aluminum tubes in which the water flows have a diameter of $4 \mathrm{~cm}$ and negligible thickness. Fins are attached on the outer surface of the tubes in order to increase the heat transfer surface area on the air side. The heat transfer coefficients on the inner and outer surfaces are 2000 and \(150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. If the effective surface area on the finned side is 12 times the inner surface area, the overall heat transfer coefficient of this heat exchanger based on the inner surface area is (a) \(760 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (b) \(832 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (c) \(947 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (d) \(1075 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (e) \(1210 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\)
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