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Discuss the differences between the cardiovascular countercurrent design and standard engineering countercurrent designs.

Short Answer

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Compare and contrast cardiovascular countercurrent design with standard engineering countercurrent designs, discussing their principles, mechanisms, applications, efficiency, and unique features.

Step by step solution

01

Introduction to Countercurrent Designs

Countercurrent designs are used in various systems to enhance the transfer of heat, mass, or energy between two streams, often including fluids. In a countercurrent system, the operating fluids flow in opposite directions to maximize the transfer process. There are two types of countercurrent designs to discuss: cardiovascular countercurrent design and standard engineering countercurrent designs.
02

Cardiovascular Countercurrent Design

In cardiovascular countercurrent design, blood vessels (arteries and veins) run parallel to each other, allowing the transfer of heat between warmer arterial blood and cooler venous blood in a continuous process. This type of design is commonly found in animals, particularly those in cold environments, as it helps maintain body temperature and limit heat loss. Examples include the circulatory systems of fish, birds, and mammals.
03

Standard Engineering Countercurrent Designs

Standard engineering countercurrent designs are commonly used in industrial processes such as chemical reactors, heat exchangers, distillation columns, and gas absorption systems. These designs involve fluid streams flowing in opposite directions to enhance the transfer of heat or mass between the streams. A higher concentration or temperature gradient is maintained, improving the overall process efficiency. Some examples include the shell and tube heat exchanger, packed columns in distillation, and gas-liquid absorption columns.
04

Differences in Mechanisms

Cardiovascular countercurrent design works primarily on the transfer of heat between closely arranged blood vessels carrying warm arterial blood and cooler venous blood. In contrast, standard engineering countercurrent designs aim to improve heat, mass, or energy transfer between separate fluid streams, depending on the application.
05

Differences in Applications

Cardiovascular countercurrent systems are primarily used by living organisms, particularly in temperature regulation and maintaining heat balance. In contrast, standard engineering countercurrent designs are commonly employed in various industrial and engineering applications related to chemical, thermal, and mass transfer processes.
06

Efficiency and Benefits

Both types of countercurrent designs have their unique benefits. Cardiovascular countercurrent systems help animals maintain body temperature and reduce energy consumption in thermoregulation, while standard engineering countercurrent designs enhance process efficiency in various industrial processes by managing the transfer of heat, mass, or energy effectively. In summary, the main differences between cardiovascular countercurrent design and standard engineering countercurrent designs lie in their mechanisms, applications, and the specific benefits they offer. While both designs involve the transfer of heat or mass between fluids flowing in opposite directions, they serve unique purposes in different fields.

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Most popular questions from this chapter

A crossflow air-to-water heat exchanger with an effectiveness of \(0.65\) is used to heat water \(\left(c_{p}=4180\right.\) $\mathrm{J} / \mathrm{kg} \cdot \mathrm{K})\( with hot air \)\left(c_{p}=1010 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\(. Water enters the heat exchanger at \)20^{\circ} \mathrm{C}$ at a rate of \(4 \mathrm{~kg} / \mathrm{s}\), while air enters at $100^{\circ} \mathrm{C}\( at a rate of \)9 \mathrm{~kg} / \mathrm{s}$. If the overall heat transfer coefficient based on the water side is $260 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, determine the heat transfer surface area of the heat exchanger on the water side. Assume both fluids are unmixed. Answer: \(52.4 \mathrm{~m}^{2}\)

Write an essay on the static and dynamic types of regenerative heat exchangers, and compile information about the manufacturers of such heat exchangers. Choose a few models by different manufacturers and compare their costs and performance.

Water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) is to be heated by solarheated hot air $\left(c_{p}=1010 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)$ in a double-pipe counterflow heat exchanger. Air enters the heat exchanger at \(90^{\circ} \mathrm{C}\) at a rate of \(0.3 \mathrm{~kg} / \mathrm{s}\), while water enters at $22^{\circ} \mathrm{C}\( at a rate of \)0.1 \mathrm{~kg} / \mathrm{s}$. The overall heat transfer coefficient based on the inner side of the tube is given to be $80 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\(. The length of the tube is \)12 \mathrm{~m}\(, and the internal diameter of the tube is \)1.2 \mathrm{~cm}$. Determine the outlet temperatures of the water and the air.

An air handler is a large unmixed heat exchanger used for comfort control in large buildings. In one such application, chilled water $\left(c_{p}=4.2 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)$ enters an air handler at \(5^{\circ} \mathrm{C}\) and leaves at \(12^{\circ} \mathrm{C}\) with a flow rate of \(1000 \mathrm{~kg} / \mathrm{h}\). This cold water cools air \(\left(c_{p}=1.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) from \(25^{\circ} \mathrm{C}\) to \(15^{\circ} \mathrm{C}\). The rate of heat transfer between the two streams is (a) \(8.2 \mathrm{~kW}\) (b) \(23.7 \mathrm{~kW}\) (c) \(33.8 \mathrm{~kW}\) (d) \(44.8 \mathrm{~kW}\) (e) \(52.8 \mathrm{~kW}\)

Hot water coming from the engine is to be cooled by ambient air in a car radiator. The aluminum tubes in which the water flows have a diameter of $4 \mathrm{~cm}$ and negligible thickness. Fins are attached on the outer surface of the tubes in order to increase the heat transfer surface area on the air side. The heat transfer coefficients on the inner and outer surfaces are 2000 and \(150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. If the effective surface area on the finned side is 12 times the inner surface area, the overall heat transfer coefficient of this heat exchanger based on the inner surface area is (a) \(760 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (b) \(832 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (c) \(947 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (d) \(1075 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (e) \(1210 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\)

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