Chapter 11: Problem 147
Describe the cardiovascular countercurrent mechanism in the human body.
Chapter 11: Problem 147
Describe the cardiovascular countercurrent mechanism in the human body.
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Get started for freeOil in an engine is being cooled by air in a crossflow heat exchanger, where both fluids are unmixed. Oil $\left(c_{p k}=2047 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( flowing with a flow rate of \)0.026 \mathrm{~kg} / \mathrm{s}\( enters the heat exchanger at \)75^{\circ} \mathrm{C}$, while air \(\left(c_{p c}=1007 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters at \(30^{\circ} \mathrm{C}\) with a flow rate of $0.21 \mathrm{~kg} / \mathrm{s}$. The overall heat transfer coefficient of the heat exchanger is \(53 \mathrm{~W} / \mathrm{m}^{2}, \mathrm{~K}\) and the total surface area is \(1 \mathrm{~m}^{2}\). Determine \((a)\) the heat transfer effectiveness and \((b)\) the outlet temperature of the oil.
A one-shell and two-tube-type heat exchanger has an overall heat transfer coefficient of $300 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2}{ }^{\circ} \mathrm{F}\(. The shell-side fluid has a heat capacity rate of \)20,000 \mathrm{Btu} / \mathrm{h} \cdot{ }^{\circ} \mathrm{F}$, while the tube-side fluid has a heat capacity rate of 40,000 $\mathrm{Btu} / \mathrm{h} \cdot{ }^{\circ} \mathrm{F}$. The inlet temperatures on the shell side and tube side are \(200^{\circ} \mathrm{F}\) and \(90^{\circ} \mathrm{F}\), respectively. If the total heat transfer area is \(100 \mathrm{ft}^{2}\), determine \((a)\) the heat transfer effectiveness and \((b)\) the actual heat transfer rate in the heat exchanger.
A shell-and-tube heat exchanger with two shell passes and four tube passes is used for cooling oil $\left(c_{p}=2.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\( from \)125^{\circ} \mathrm{C}\( to \)55^{\circ} \mathrm{C}$. The coolant is water, which enters the shell side at \(25^{\circ} \mathrm{C}\) and leaves at \(46^{\circ} \mathrm{C}\). The overall heat transfer coefficient is \(900 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). For an oil flow rate of \(10 \mathrm{~kg} / \mathrm{s}\), calculate the cooling water flow rate and the heat transfer area.
Glycerin \(\left(c_{p}=2400 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) at \(20^{\circ} \mathrm{C}\) and \(0.5 \mathrm{~kg} / \mathrm{s}\) is to be heated by ethylene glycol $\left(c_{p}=2500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( at \)60^{\circ} \mathrm{C}$ in a thin-walled double-pipe parallel-flow heat exchanger. The temperature difference between the two fluids is \(15^{\circ} \mathrm{C}\) at the outlet of the heat exchanger. If the overall heat transfer coefficient is $240 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\( and the heat transfer surface area is \)3.2 \mathrm{~m}^{2}$, determine \((a)\) the rate of heat transfer, \((b)\) the outlet temperature of the glycerin, and \((c)\) the mass flow rate of the ethylene glycol.
A crossflow heat exchanger with both fluids unmixed has an overall heat transfer coefficient of \(200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and a heat transfer surface area of \(400 \mathrm{~m}^{2}\). The hot fluid has a heat capacity of \(40,000 \mathrm{~W} / \mathrm{K}\), while the cold fluid has a heat capacity of \(80,000 \mathrm{~W} / \mathrm{K}\). If the inlet temperatures of both hot and cold fluids are \(80^{\circ} \mathrm{C}\) and $20^{\circ} \mathrm{C}$, respectively, determine the exit temperature of the cold fluid.
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