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What are the restrictions on the relation \(U A_{s}=\) \(U_{i} A_{i}=U_{o} A_{o}\) for a heat exchanger? Here \(A_{s}\) is the heat transfer surface area and \(U\) is the overall heat transfer coefficient.

Short Answer

Expert verified
Answer: The main restrictions on the relation \(U A_{s}= U_{i} A_{i}=U_{o} A_{o}\) in a heat exchanger are: 1. The total heat transfer surface area must be equal to the sum of the inner and outer heat transfer surface areas (\(A_{s} = A_{i} + A_{o}\)). 2. The heat transfer capacity between the fluids must be equal (\(U_{i}A_{i} = U_{o}A_{o}\)). These restrictions ensure that the heat exchanger operates without any temperature imbalances and with optimal heat transfer between the fluids.

Step by step solution

01

Understand the Variables

In a heat exchanger, the following variables are given: - \(U\): overall heat transfer coefficient - \(A_{s}\): heat transfer surface area - \(U_{i}\): overall heat transfer coefficient on the inner side (fluid side) - \(A_{i}\): heat transfer surface area on the inner side (fluid side) - \(U_{o}\): overall heat transfer coefficient on the outer side (shell side) - \(A_{o}\): heat transfer surface area on the outer side (shell side) The relation we are given is \(U A_{s}= U_{i} A_{i}=U_{o} A_{o}\), which describes the balance of heat transfer rates between the two fluids in the heat exchanger.
02

Consider the Constraint on Surface Areas

Firstly, we know the total heat transfer surface area depends on the inner surface area and the outer surface area: \(A_{s} = A_{i} + A_{o}\) This means that \(A_{s}\) is restricted by the sum of \(A_i\) and \(A_o\).
03

Consider the Constraint on Fluid Capacities

Another constraint we have to consider is that the heat transfer capacity of the fluids within the heat exchanger must be equal. If not, we would not have an effective heat exchanger as there would be a temperature imbalance. This constraint can be expressed as: \(U_{i}A_{i} = U_{o}A_{o}\)
04

Analyzing Constraints and Restrictions

By analyzing steps 2 and 3, we can see that there are two main restrictions on the relation \(U A_{s}= U_{i} A_{i}=U_{o} A_{o}\): 1. The total heat transfer surface area must be equal to the sum of the inner and outer heat transfer surface areas (\(A_{s} = A_{i} + A_{o}\)). 2. The heat transfer capacity between the fluids must be equal (\(U_{i}A_{i} = U_{o}A_{o}\)). These restrictions ensure that the heat exchanger operates without any temperature imbalances and with optimal heat transfer between the fluids.

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Most popular questions from this chapter

A double-pipe heat exchanger is used to cool a hot fluid before it flows into a system of pipes. The inner surface of the pipes is primarily coated with polypropylene lining. The maximum use temperature for polypropylene lining is $107^{\circ} \mathrm{C}$ (ASME Code for Process Piping, ASME B31.32014, Table A323.4.3). The double-pipe heat exchanger has a thin-walled inner tube, with convection heat transfer coefficients inside and outside of the inner tube estimated to be \(1400 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and $1100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, respectively. The heat exchanger has a heat transfer surface area of \(2.5 \mathrm{~m}^{2}\), and the estimated fouling factor caused by the accumulation of deposit on the surface is \(0.0002\) \(\mathrm{m}^{2} \cdot \mathrm{K} / \mathrm{W}\). The hot fluid \(\left(c_{p}=3800 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters the heat exchanger at \(200^{\circ} \mathrm{C}\) with a flow rate of $0.4 \mathrm{~kg} / \mathrm{s}\(. In the cold side, cooling fluid \)\left(c_{p}=4200 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)$ enters the heat exchanger at \(10^{\circ} \mathrm{C}\) with a mass flow rate of $0.5 \mathrm{~kg} / \mathrm{s}$.

A shell-and-tube heat exchanger with two shell passes and eight tube passes is used to heat ethyl alcohol \(\left(c_{p}=2670\right.\) $\mathrm{J} / \mathrm{kg} \cdot \mathrm{K})\( in the tubes from \)25^{\circ} \mathrm{C}\( to \)70^{\circ} \mathrm{C}\( at a rate of \)2.1 \mathrm{~kg} / \mathrm{s}$. The heating is to be done by water $\left(c_{p}=4190 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( that enters the shell side at \)95^{\circ} \mathrm{C}$ and leaves at \(45^{\circ} \mathrm{C}\). If the overall heat transfer coefficient is \(950 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the heat transfer surface area of the heat exchanger.

Consider a heat exchanger that has an NTU of \(0.1\). Someone proposes to triple the size of the heat exchanger and thus triple the NTU to \(0.3\) in order to increase the effectiveness of the heat exchanger and thus save energy. Would you support this proposal?

A single-pass crossflow heat exchanger with both fluids unmixed has water entering at \(16^{\circ} \mathrm{C}\) and exiting at \(33^{\circ} \mathrm{C}\), while oil $\left(c_{p}=1.93 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right.\( and \)\left.\rho=870 \mathrm{~kg} / \mathrm{m}^{3}\right)$ flowing at \(0.19 \mathrm{~m}^{3} / \mathrm{min}\) enters at $38^{\circ} \mathrm{C}\( and exits at \)29^{\circ} \mathrm{C}$. If the surface area of the heat exchanger is \(20 \mathrm{~m}^{2}\), determine \((a)\) the NTU value and \((b)\) the value of the overall heat transfer coefficient.

Geothermal water $\left(c_{p}=4250 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( at \)75^{\circ} \mathrm{C}$ is to be used to heat fresh water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) at \(17^{\circ} \mathrm{C}\) at a rate of \(1.2 \mathrm{~kg} / \mathrm{s}\) in a double-pipe counterflow heat exchanger. The heat transfer surface area is $25 \mathrm{~m}^{2}\(, the overall heat transfer coefficient is \)480 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, and the mass flow rate of geothermal water is larger than that of fresh water. If the effectiveness of the heat exchanger must be \(0.823\), determine the mass flow rate of geothermal water and the outlet temperatures of both fluids.

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