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At a distance \(x\) down a vertical, isothermal flat plate on which a saturated vapor is condensing in a continuous film, the thickness of the liquid condensate layer is \(\delta\). The heat transfer coefficient at this location on the plate is given by (a) \(k_{l} / \delta\) (b) \(\delta h_{f}\) (c) \(\delta h_{f g}\) (d) \(\delta h_{\mathrm{s}}\) (e) none of them

Short Answer

Expert verified
Answer: The correct expression for the heat transfer coefficient is given by the quotient of the thermal conductivity of the liquid (\(k_{l}\)) and the thickness of the liquid condensate layer (\(\delta\)): $$h = \frac{k_{l}}{\delta}$$.

Step by step solution

01

Identify the conceptual components

Since the problem concerns a vertical flat plate with condensing vapor, it is a film condensation problem. Additionally, we know that the plate is isothermal, which simplifies the problem. We need to find the heat transfer coefficient of the specified location on the plate, so let's recall the definition of the heat transfer coefficient and the variables needed: Heat transfer coefficient (h): It represents the heat transfer by convection between a surface and a fluid (in this case, the condensate layer), and is given by: $$h = \frac{q}{\Delta T}$$, where q is the heat transfer per unit area and \(\Delta T\) is the temperature difference between the surface and the fluid. Now let's review the given options: (a) \(k_{l} / \delta\): This term presents the quotient of the thermal conductivity of the liquid, represented by \(k_{l}\), and the thickness of the liquid layer, \(\delta\). Since it connects the ease of heat transfer (thermal conductivity) and the thickness of the condensate, it's a possible answer. (b) \(\delta h_{f}\): This term combines the thickness of the liquid layer (\(\delta\)) and the specific enthalpy of fusion (\(h_{f}\)). It doesn't relate to heat transfer or temperature, so we can rule this one out. (c) \(\delta h_{f g}\): This term consists of the thickness of the liquid layer (\(\delta\)) and the specific enthalpy of vaporization (\(h_{f g}\)). It also doesn't relate to heat transfer or temperature, so we can rule this one out as well. (d) \(\delta h_{\mathrm{s}}\): This term combines the thickness of the liquid layer (\(\delta\)) with the specific enthalpy of sublimation (\(h_{\mathrm{s}}\)). It also deals with enthalpy instead of heat transfer or temperature, so we rule this answer out. (e) None of them: This option is incorrect, as we identified in option (a) a potential relation between heat transfer and the quantities given.
02

Identify the correct expression

Based on the analysis in Step 1, we can now conclude that option (a) provides the correct expression for the heat transfer coefficient at the specified location on the isothermal flat plate. It is given by the quotient of the thermal conductivity of the liquid (\(k_{l}\)) and the thickness of the liquid condensate layer (\(\delta\)): $$h = \frac{k_{l}}{\delta}$$

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Most popular questions from this chapter

How does the presence of a noncondensable gas in a vapor influence the condensation heat transfer?

Saturated steam at \(100^{\circ} \mathrm{C}\) condenses on a $2-\mathrm{m} \times 2-\mathrm{m}\( plate that is tilted \)30^{\circ}$ from the vertical. The plate is maintained at \(80^{\circ} \mathrm{C}\) by cooling it from the other side. Determine (a) the average heat transfer coefficient over the entire plate and (b) the rate at which the condensate drips off the plate at the bottom. Assume wavy-laminar flow. Is this a good assumption?

Consider a two-phase flow of air-water in a vertical upward stainless steel pipe with an inside diameter of \(0.0254\) \(\mathrm{m}\). The two-phase mixture enters the pipe at \(25^{\circ} \mathrm{C}\) at a system pressure of $201 \mathrm{kPa}\(. The superficial velocities of the water and air are \)0.3 \mathrm{~m} / \mathrm{s}\( and \)23 \mathrm{~m} / \mathrm{s}$, respectively. The differential pressure transducer connected across the pressure taps set $1 \mathrm{~m}\( apart records a pressure drop of \)2700 \mathrm{~Pa}$, and the measured value of the void fraction is \(0.86\). Using the concept of the Reynolds analogy, determine the two-phase convective heat transfer coefficient. Use the following thermophysical properties for water and air: $\rho_{l}=997.1 \mathrm{~kg} / \mathrm{m}^{3}, \mu_{l}=8.9 \times 10^{-4} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, \mu_{s}=4.66 \times\( \)10^{-4} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, \operatorname{Pr}_{l}=6.26, k_{l}=0.595 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \sigma=0.0719 \mathrm{~N} / \mathrm{m}\(, \)\rho_{g}=2.35 \mathrm{~kg} / \mathrm{m}^{3}$, and \(\mu_{g}=1.84 \times 10^{-5} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\).

Heat transfer coefficients for a vapor condensing on a surface can be increased by promoting (a) film condensation (b) dropwise condensation (c) rolling action (d) none of them

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