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Consider heat transfer through a windowless wall of a house on a winter day. Discuss the parameters that affect the rate of heat conduction through the wall.

Short Answer

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Answer: The four main parameters that affect the rate of heat conduction through a windowless wall on a winter day are the wall material, wall thickness, surface area, and temperature difference between the inside and outside of the house. To minimize heat conduction, one can choose materials with low thermal conductivity, increase wall thickness, minimize the surface area in contact with the cold outdoors, and maintain a small temperature difference between the inside and outside of the house.

Step by step solution

01

Understand Heat Conduction

Heat conduction is the transfer of heat energy between two objects in direct contact with each other, caused by a temperature difference. In this case, we're considering heat transfer through a wall, with one side being warmer (inside the house) and the other side being colder (outside, in winter). The rate of heat conduction depends on several factors, such as the material of the wall, the wall's thickness, and its surface area.
02

Factor 1: Wall Material

The material from which the wall is made will significantly impact the rate of heat conduction. Different materials have different thermal conductivities, which is a measure of how easily heat passes through the material. Materials with high thermal conductivity, such as metals, will conduct heat more quickly than materials with low thermal conductivity, like wood or insulation materials. So, choosing a wall material with low thermal conductivity will help to reduce the rate of heat conduction and keep the house warmer in winter.
03

Factor 2: Wall Thickness

The thickness of the wall also plays a crucial role in heat conduction. Thicker walls conduct heat more slowly than thinner walls because there is a greater distance for the heat to travel through. Increasing the thickness of the wall can be an effective way to slow down the rate of heat conduction and improve the insulation of the house.
04

Factor 3: Wall Surface Area

The surface area of the wall is another important parameter to consider, as it determines the size of the contact area between the inside and outside of the house. Larger surface areas allow for more heat transfer, while smaller surface areas result in less heat transfer. Therefore, to minimize heat conduction through the wall, it's beneficial to have a smaller surface area in contact with the cold outdoor environment.
05

Factor 4: Temperature Difference

The temperature difference between the inside and outside of the house affects the rate of heat conduction through the wall. The greater the temperature difference, the faster the heat will transfer between the inside and outside. To maintain a comfortable indoor temperature while minimizing heat conduction, it's essential to keep the temperature difference between the inside and outside of the house as small as possible. This can be achieved by heating the house efficiently and ensuring that its insulation is effective. In summary, the parameters that impact the rate of heat conduction through a windowless wall on a winter day are the wall material, wall thickness, surface area, and temperature difference between the inside and outside of the house. By choosing materials with low thermal conductivity, increasing wall thickness, minimizing surface area in contact with the cold outdoors, and maintaining a small temperature difference between the inside and outside, we can effectively minimize the rate of heat conduction through the wall.

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Most popular questions from this chapter

The inner and outer surfaces of a 25 -cm-thick wall in summer are at \(27^{\circ} \mathrm{C}\) and \(44^{\circ} \mathrm{C}\), respectively. The outer surface of the wall exchanges heat by radiation with surrounding surfaces at \(40^{\circ} \mathrm{C}\) and by convection with ambient air also at $40^{\circ} \mathrm{C}\( with a convection heat transfer coefficient of \)8 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$. Solar radiation is incident on the surface at a rate of \(150 \mathrm{~W} / \mathrm{m}^{2}\). If both the emissivity and the solar absorptivity of the outer surface are \(0.8\), determine the effective thermal conductivity of the wall.

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Which expression is used to determine the heat flux for conduction? (a) \(-k A \frac{d T}{d x}\) (b) \(-k \operatorname{grad} T\) (c) \(h\left(T_{2}-T_{1}\right)\) (d) \(\varepsilon \sigma T^{4}\) (e) None of them

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