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Why is it necessary to ventilate buildings? What is the effect of ventilation on energy consumption for heating in winter and for cooling in summer? Is it a good idea to keep the bathroom fans on all the time? Explain.

Short Answer

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Short Answer: Ventilation is crucial in buildings to maintain indoor air quality, ensuring a healthy and comfortable living environment. It can reduce heating or cooling energy consumption by managing humidity levels and indoor temperatures. However, keeping bathroom fans on all the time may not be a good idea as it can increase energy consumption, contribute to conditioned air loss through unsealed ductwork, and cause noise pollution. Instead, bathroom fans should be used as needed, particularly during or after showers or baths, to remove excess moisture and prevent mold growth.

Step by step solution

01

Importance of Ventilation in Buildings

Ventilation is necessary to maintain indoor air quality and ensure a healthy and comfortable living environment for the occupants. It helps to remove moisture, allergens, pollutants, and odors from indoor spaces. Proper ventilation also prevents the growth of mold and other indoor air contaminants that can affect the wellbeing of the building's occupants.
02

Effect of Ventilation on Energy Consumption

Ventilation can have both positive and negative effects on energy consumption, depending on the season and the method used. In winter: - Improved ventilation can reduce heating energy consumption by lowering indoor humidity levels and enabling a lower indoor temperature to feel more comfortable. - On the other hand, it can also increase heating energy consumption if fresh, cold air is continuously brought in from outside and needs to be heated. In summer: - Proper ventilation can reduce cooling energy consumption by removing hot, humid air from the inside and allowing cooler, fresh air from outside to enter. - However, if the outside air is hot and humid, bringing it in can increase energy consumption for cooling, as the air conditioner has to work harder to cool and dehumidify the incoming air.
03

Bathroom Fans: Should They Be On All the Time?

It may not be a good idea to keep bathroom fans on all the time due to the following reasons: 1. Energy Consumption: Bathroom fans consume energy when they run, and keeping them on all the time would increase a building's overall energy consumption. 2. Ductwork and Conditioned Air Loss: If the bathroom fan and ductwork are not properly sealed, they can allow conditioned air (heated or cooled) to escape the home, leading to higher energy consumption for heating or cooling. 3. Noise: Continuous use of bathroom fans can contribute to noise pollution within the building. That said, it is essential to use bathroom fans whenever it is needed, such as during or shortly after showers or baths to efficiently remove excess moisture and prevent mold growth. In conclusion, proper ventilation is crucial for maintaining a healthy and comfortable living environment in buildings. The effect on energy consumption varies based on seasonal conditions and methods used for ventilation. Bathroom fans should be used when necessary, but keeping them on continuously may not be the most practical or energy-efficient solution.

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Most popular questions from this chapter

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A concrete wall with a surface area of \(20 \mathrm{~m}^{2}\) and a thickness of \(0.30 \mathrm{~m}\) separates conditioned room air from ambient air. The temperature of the inner surface of the wall \(\left(T_{1}\right)\) is maintained at \(25^{\circ} \mathrm{C}\). (a) Determine the heat loss \(\dot{Q}(\mathrm{~W})\) through the concrete wall for three thermal conductivity values of \(0.75,1\), and $1.25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$ and outer wall surface temperatures of \(T_{2}=-15,-10,-5,0,5,10,15,20,25,30\), and \(38^{\circ} \mathrm{C}\) (a total of 11 data points for each thermal conductivity value). Tabulate the results for all three cases in one table. Also provide a computer-generated graph [Heat loss, \(\dot{Q}(\mathrm{~W})\) vs. Outside wall temperature, $\left.T_{2}\left({ }^{\circ} \mathrm{C}\right)\right]$ for the display of your results. The results for all three cases should be plotted on the same graph. (b) Discuss your results for the three cases.

Eggs with a mass of \(0.15 \mathrm{~kg}\) per egg and a specific heat of $3.32 \mathrm{~kJ} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}$ are cooled from \(32^{\circ} \mathrm{C}\) to \(10^{\circ} \mathrm{C}\) at a rate of 300 eggs per minute. The rate of heat removal from the eggs is (a) \(11 \mathrm{~kW}\) (b) \(80 \mathrm{~kW}\) (c) \(25 \mathrm{~kW}\) (d) \(657 \mathrm{~kW}\) (e) \(55 \mathrm{~kW}\)

Consider a 20-cm-thick granite wall with a thermal conductivity of $2.79 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}$. The temperature of the left surface is held constant at \(50^{\circ} \mathrm{C}\), whereas the right face is exposed to a flow of \(22^{\circ} \mathrm{C}\) air with a convection heat transfer coefficient of \(15 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Neglecting heat transfer by radiation, find the right wall surface temperature and the heat flux through the wall.

A cold bottled drink ( $\left.m=2.5 \mathrm{~kg}, c_{p}=4200 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\( at \)5^{\circ} \mathrm{C}$ is left on a table in a room. The average temperature of the drink is observed to rise to \(15^{\circ} \mathrm{C}\) in \(30 \mathrm{~min}\). The average rate of heat transfer to the drink is (a) \(23 \mathrm{~W}\) (b) \(29 \mathrm{~W}\) (c) \(58 \mathrm{~W}\) (d) \(88 \mathrm{~W}\) (e) \(122 \mathrm{~W}\)

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