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What is asymmetric thermal radiation? How does it cause thermal discomfort in the occupants of a room?

Short Answer

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Answer: Asymmetric thermal radiation is a type of radiant heat that comes from different directions, resulting in a non-uniform distribution of heat due to varying temperatures of surfaces in a room. It can cause thermal discomfort in room occupants, leading to inadequate thermal balance, decreased productivity, and potential health concerns. Factors such as large temperature differences between surfaces, uneven distribution of heat sources and insulation, direct sunlight, and the presence of large cold surfaces contribute to asymmetric thermal radiation.

Step by step solution

01

Definition of Asymmetric Thermal Radiation

Asymmetric thermal radiation is a type of radiant heat that comes from different directions, which results in a non-uniform distribution of heat. This occurs when surfaces in a room, such as walls, ceilings, or windows, have varying temperatures, causing the radiant heat to be emitted unevenly.
02

Causes of Asymmetric Thermal Radiation

Asymmetric thermal radiation can be caused by factors such as: - Large temperature differences between the surfaces in a room. - Uneven distribution of heat sources and insulation. - Direct sunlight or external heat sources irradiating one side of the room. - Presence of large, cold surfaces, such as windows in winter.
03

Impact of Asymmetric Thermal Radiation on Occupants

The impact of asymmetric thermal radiation on the occupants of a room can be observed through the following: 1. Thermal discomfort: As the heat is not distributed evenly, some parts of the body may feel warmer or colder than others, leading to discomfort. 2. Inadequate thermal balance: With uneven heat distribution, maintaining a comfortable indoor temperature becomes challenging, leading to frequent temperature adjustments. 3. Decreased productivity: Thermal discomfort can affect the productivity and well-being of the occupants, as it may cause distractions and fatigue. 4. Health concerns: Prolonged exposure to asymmetric thermal radiation can lead to health issues like circulatory system problems and cold-related illnesses.
04

Mitigating Asymmetric Thermal Radiation

To reduce asymmetric thermal radiation and its impact on occupants, the following strategies can be implemented: 1. Proper placement of heat sources: Distribute heat sources more uniformly throughout the room to ensure a more balanced thermal environment. 2. Adequate insulation: Ensure that walls, ceilings, and windows are well-insulated to prevent large temperature differences between surfaces. 3. Use of shading devices: Utilize blinds, curtains, or shades on windows to control the amount of sunlight entering the room and maintain a more consistent indoor temperature. 4. Regular maintenance: Periodically check and maintain heating and cooling systems to ensure optimal performance and even heat distribution.

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Most popular questions from this chapter

A \(4-\mathrm{m} \times 5-\mathrm{m} \times 6-\mathrm{m}\) room is to be heated by one ton \((1000 \mathrm{~kg})\) of liquid water contained in a tank placed in the room. The room is losing heat to the outside at an average rate of $10,000 \mathrm{~kJ} / \mathrm{h}\(. The room is initially at \)20^{\circ} \mathrm{C}$ and \(100 \mathrm{kPa}\) and is maintained at an average temperature of \(20^{\circ} \mathrm{C}\) at all times. If the hot water is to meet the heating requirements of this room for a \(24-\mathrm{h}\) period, determine the minimum temperature of the water when it is first brought into the room. Assume constant specific heats for both air and water at room temperature. Answer: 77.4 \(\mathrm{C}\)

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Consider a house in Atlanta, Georgia, that is maintained at $22^{\circ} \mathrm{C}\( and has a total of \)20 \mathrm{~m}^{2}$ of window area. The windows are double-door type with wood frames and metal spacers and have a \(U\)-factor of \(2.5 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (see Prob. 1-120 for the definition of \(U\)-factor). The winter average temperature of Atlanta is \(11.3^{\circ} \mathrm{C}\). Determine the average rate of heat loss through the windows in winter.

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