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Someone claims that turning the thermostat of the central air conditioning of a warm house to the lowest level will cool the house a lot faster. Is there any truth to this claim?

Short Answer

Expert verified
Answer: No, turning the thermostat to the lowest level does not cool the house faster. The cooling system cools the room at a constant rate, and lowering the thermostat setting only makes the system work longer, not faster.

Step by step solution

01

Understand how a thermostat works

A thermostat is a device that controls the heating or cooling system in a house or building. It does so by maintaining a set temperature by regulating the flow of warm or cool air. When the ambient temperature creeps above or falls below the set temperature, the thermostat signals the heating or cooling system to turn on until the desired temperature is achieved. Once the set temperature is reached, the system turns off.
02

Realize that air conditioning systems only have one speed

Contrary to popular belief, most air conditioning systems only have one speed - they are either on or off. The thermostat setting determines when the system turns on and off but not how fast it cools down the room. When the system is on, it cools the room at a constant rate.
03

Consider how lowering the thermostat setting affects cooling

When you turn the thermostat to a lower setting, you are setting a lower target temperature for the cooling system. The system will work harder, staying on for a longer time to achieve the new lower target. However, the rate at which the house cools remains the same because the cooling system's speed remains unchanged.
04

Discuss energy consumption

Setting the thermostat to the lowest level will consume more energy and keep the air conditioning system running longer. This results in higher electricity bills and potentially shorter system lifespan due to wear and tear from overuse.
05

Conclusion: Debunk the claim

There is no truth to the claim that turning the thermostat of the central air conditioning of a warm house to the lowest level will cool the house a lot faster. While lowering the thermostat setting may make the air conditioning system work longer, the speed at which the house cools down remains constant. Therefore, it's more efficient to set the thermostat to a comfortable temperature that is not too extreme.

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Most popular questions from this chapter

A thin metal plate is insulated on the back and exposed to solar radiation on the front surface. The exposed surface of the plate has an absorptivity of \(0.7\) for solar radiation. If solar radiation is incident on the plate at a rate of \(550 \mathrm{~W} / \mathrm{m}^{2}\) and the surrounding air temperature is \(10^{\circ} \mathrm{C}\), determine the surface temperature of the plate when the heat loss by convection equals the solar energy absorbed by the plate. Take the convection heat transfer coefficient to be $25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}$, and disregard any heat loss by radiation.

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The deep human body temperature of a healthy person remains constant at \(37^{\circ} \mathrm{C}\) while the temperature and the humidity of the environment change with time. Discuss the heat transfer mechanisms between the human body and the environment in both summer and winter, and explain how a person can keep cooler in summer and warmer in winter.

Eggs with a mass of \(0.15 \mathrm{~kg}\) per egg and a specific heat of $3.32 \mathrm{~kJ} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}$ are cooled from \(32^{\circ} \mathrm{C}\) to \(10^{\circ} \mathrm{C}\) at a rate of 300 eggs per minute. The rate of heat removal from the eggs is (a) \(11 \mathrm{~kW}\) (b) \(80 \mathrm{~kW}\) (c) \(25 \mathrm{~kW}\) (d) \(657 \mathrm{~kW}\) (e) \(55 \mathrm{~kW}\)

Conduct this experiment to determine the combined heat transfer coefficient between an incandescent lightbulb and the surrounding air and surfaces using a 60 -W lightbulb. You will need a thermometer, which can be purchased in a hardware store, and metal glue. You will also need a piece of string and a ruler to calculate the surface area of the lightbulb. First, measure the air temperature in the room, and then glue the tip of the thermocouple wire of the thermometer to the glass of the lightbulb. Turn the light on and wait until the temperature reading stabilizes. The temperature reading will give the surface temperature of the lightbulb. Assuming 10 percent of the rated power of the bulb is converted to light and is transmitted by the glass, calculate the heat transfer coefficient from Newton's law of cooling.

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