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A 10 -m-long and 10 -mm-inner-diameter pipe made of commercial steel is used to heat a liquid in an industrial process. The liquid enters the pipe with \(T_{i}=25^{\circ} \mathrm{C}, V=0.8 \mathrm{~m} / \mathrm{s}\). A uniform heat flux is maintained by an electric resistance heater wrapped around the outer surface of the pipe, so that the fluid exits at \(75^{\circ} \mathrm{C}\). Assuming fully developed flow and taking the average fluid properties to be \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=\) \(4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=2 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, k=0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\operatorname{Pr}=10\), determine: (a) The required surface heat flux \(\dot{q}_{s}\), produced by the heater (b) The surface temperature at the exit, \(T_{s}\) (c) The pressure loss through the pipe and the minimum power required to overcome the resistance to flow.

Short Answer

Expert verified
Question: Determine the required surface heat flux, the surface temperature at the exit, the pressure loss through the pipe, and the minimum power required to overcome the resistance to flow in a 10-meter long and 10-mm-inner diameter pipe with an inlet temperature of 25°C and an outlet temperature of 75°C. Answer: 1. Calculate the mass flow rate and Reynolds number: Mass flow rate, \(\dot{m}= \rho AV\) Reynolds number, \(\text{Re}= \frac{\rho V d}{\mu}\) 2. Calculate the Nusselt number and heat transfer coefficient: Nusselt number, \(\text{Nu}= 0.023\; \text{Re}^{0.8}\; \operatorname{Pr}^{n}\) Heat transfer coefficient, \(h= \frac{\text{Nu}\cdot k}{d}\) 3. Calculate the required surface heat flux: Required surface heat flux, \(\dot{q}_{s}= \frac{\dot{m}c_{p}(T_{o}-T_{i})}{L}\) 4. Calculate the surface temperature at the exit: Surface temperature at the exit, \(T_{s}= T_{o}+ \frac{\dot{q}_{s}}{h A_{s}}\) 5. Determine the pressure loss through the pipe and the minimum power required to overcome the resistance to flow: Pressure loss, \(\Delta P= f \frac{L \rho V^{2}}{2 d}\) Friction factor, \(f= 0.079\; \text{Re}^{-0.25}\) Minimum power required, \(P_{\text{min}}= \frac{\Delta P \dot{V}}{\rho}\)

Step by step solution

01

Calculate the mass flow rate and Reynolds number

First, let's find the mass flow rate of the liquid (\(\dot{m}\)). The mass flow rate can be calculated using the formula: $$\dot{m}=\rho A V$$ where \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}\) is the density, \(A\) is the cross-sectional area, and \(V=0.8 \mathrm{~m} / \mathrm{s}\) is the velocity. The cross-sectional area can be found using the formula: $$A=\pi r^{2}$$ where \(r\) is the pipe radius, which can be found from the inner diameter of the pipe (10mm). Now find the Reynolds number (\(\text{Re}\)): $$\text{Re}=\frac{\rho V d}{\mu}$$ where \(d\) = diameter and \(\mu=2 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\) is the dynamic viscosity.
02

Calculate the Nusselt number and heat transfer coefficient

For fully developed flow in a circular pipe, we can use Dittus-Boelter correlation to find the Nusselt number: $$\text{Nu}=0.023\; \text{Re}^{0.8}\; \operatorname{Pr}^{n}$$ where \(\operatorname{Pr}=10\) is the Prandtl number, and \(n\) = 0.3 for heating case. The heat transfer coefficient, \(h\), can be calculated from the Nusselt number: $$h=\frac{\text{Nu}\cdot k}{d}$$ where \(k=0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is the thermal conductivity.
03

Calculate the required surface heat flux

According to the conservation of energy principle, the energy added to the fluid by the heater is equal to the energy increase of the fluid, which can be represented as: $$\dot{q}_{s}=h A_{s}(T_{s} - T_{o})$$ and using the mass flow rate, we have: $$\dot{m}c_{p}(T_{o}-T_{i})=\dot{q}_{s}L$$ Solving for \(\dot{q}_{s}\), we get: $$\dot{q}_{s}=\frac{\dot{m}c_{p}(T_{o}-T_{i})}{L}$$ where \(c_{p}=4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) is the specific heat capacity, \(T_{i}=25^{\circ} \mathrm{C}\), and \(T_{o}=75^{\circ} \mathrm{C}\) are the inlet and outlet temperatures, and \(L=10\;\mathrm{m}\) is the pipe length.
04

Calculate the surface temperature at the exit

From the heat transfer equation in step 3, find the surface temperature at the exit (\(T_{s}\)) by rearranging the equation: $$T_{s}=T_{o}+\frac{\dot{q}_{s}}{h A_{s}}$$
05

Determine the pressure loss through the pipe and the minimum power required to overcome the resistance to flow

To calculate the pressure loss, we can use the Darcy-Weisbach equation for fully developed flow in a pipe: $$\Delta P=f \frac{L \rho V^{2}}{2 d}$$ We can estimate the friction factor \(f\) using the Blasius correlation for turbulent flow: $$f=0.079\; \text{Re}^{-0.25}$$ From the pressure loss, the minimum power required to overcome the resistance to flow can be calculated as: $$P_{\text{min}}=\frac{\Delta P \dot{V}}{\rho}$$ where \(\dot{V}=AV\) is the volume flow rate. Calculate the values using the found formulas and parameters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Flow Rate
The mass flow rate in a pipe system is a crucial measure in many engineering applications, determining how much mass is transported through the pipe per unit of time. It is represented by \(\dot{m}\) and is calculated using the formula:\[ \dot{m} = \rho A V \]where:
  • \(\rho\) is the fluid density
  • \(A\) is the cross-sectional area of the pipe
  • \(V\) is the fluid velocity
To find the cross-sectional area \(A\), you use the diameter of the pipe (in this case, provided in millimeters). Conversion to meters, as seen in this example, is crucial:\[ A = \pi r^2 = \pi \left(\frac{d}{2}\right)^2 \]This calculation provides insight into how the mass of fluid flows through the pipe, influencing the heating and pressure conditions within the system.
Nusselt Number
The Nusselt number plays a significant role in understanding heat transfer within pipe systems. It is a dimensionless number that characterizes how effectively heat is transferred in fluid flow, comparing convective to conductive heat transfer.For calculations in a fully developed flow, we use the Dittus-Boelter equation:\[ \text{Nu} = 0.023 \text{Re}^{0.8} \text{Pr}^{n} \]Here, the values are:
  • \(\text{Re}\) for Reynolds number, indicative of flow regime
  • \(\text{Pr}\), the Prandtl number, is a material property
  • \(n\), a factor (0.3 for heating case)
The Nusselt number helps calculate the convective heat transfer coefficient \(h\) by:\[ h = \frac{\text{Nu} \cdot k}{d} \]where \(k\) is the thermal conductivity of the fluid, and \(d\) is the pipe diameter. This coefficient \(h\) tells us how efficiently the heat energy from the heater is transferred to the liquid, allowing us to further understand and calculate the energy dynamics in the system.
Pressure Loss
Pressure loss refers to the reduction in pressure as fluid flows through the pipe due to frictional forces. It's essential to determine this loss since it directly affects the pumping requirements of the system.Using the Darcy-Weisbach equation, we can calculate pressure loss \(\Delta P\) as follows:\[ \Delta P = f \frac{L \rho V^2}{2 d} \]Key components of this formula:
  • \(f\), the friction factor, accounts for the effects of pipe roughness and fluid turbulence.
  • \(L\), the pipe length, influences the total resistance encountered by the fluid.
  • \(\rho\), \(V\), and \(d\) are previously defined parameters.
Estimating \(f\) typically involves the Blasius correlation for turbulent flow:\[ f = 0.079 \text{Re}^{-0.25} \]Understanding pressure loss helps design piping systems to ensure efficient operation while minimizing energy expenditure.
Darcy-Weisbach Equation
The Darcy-Weisbach equation is fundamental in fluid dynamics for evaluating pressure drops in pipe systems. It illustrates how various factors like fluid velocity, pipe diameter, and flow length influence pressure changes.The equation is:\[ \Delta P = f \frac{L \rho V^2}{2 d} \],connecting:
  • Pressure drop \(\Delta P\)
  • Friction factor \(f\)
  • Parameters \(L\), \(\rho\), \(V\), and \(d\)
The friction factor \(f\), central to this equation, requires proper estimation based on the flow regime, often guided by empirical correlations like Blasius for turbulent conditions.The Darcy-Weisbach equation is indispensable for understanding how energy is dissipated due to friction, enabling engineers to design efficient systems that balance pressure requirements against other operational constraints, such as energy input and desired fluid velocity.

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Most popular questions from this chapter

Air ( \(1 \mathrm{~atm})\) enters into a 5 -cm-diameter circular tube at \(20^{\circ} \mathrm{C}\) with an average velocity of \(5 \mathrm{~m} / \mathrm{s}\). The tube wall is maintained at a constant surface temperature of \(160^{\circ} \mathrm{C}\), and the outlet mean temperature is \(80^{\circ} \mathrm{C}\). Estimate the length of the tube.

Consider fully developed flow in a circular pipe with negligible entrance effects. If the length of the pipe is doubled, the pressure drop will \((a\) ) double, \((b)\) more than double, \((c)\) less than double, \((d)\) reduce by half, or \((e)\) remain constant.

In the effort to find the best way to cool a smooth thin-walled copper tube, an engineer decided to flow air either through the tube or across the outer tube surface. The tube has a diameter of \(5 \mathrm{~cm}\), and the surface temperature is maintained constant. Determine \((a)\) the convection heat transfer coefficient when air is flowing through its inside at \(25 \mathrm{~m} / \mathrm{s}\) with bulk mean temperature of \(50^{\circ} \mathrm{C}\) and \((b)\) the convection heat transfer coefficient when air is flowing across its outer surface at \(25 \mathrm{~m} / \mathrm{s}\) with film temperature of \(50^{\circ} \mathrm{C}\).

A \(15-\mathrm{cm} \times 20\)-cm printed circuit board whose components are not allowed to come into direct contact with air for reliability reasons is to be cooled by passing cool air through a 20 -cm-long channel of rectangular cross section \(0.2 \mathrm{~cm} \times 14 \mathrm{~cm}\) drilled into the board. The heat generated by the electronic components is conducted across the thin layer of the board to the channel, where it is removed by air that enters the channel at \(15^{\circ} \mathrm{C}\). The heat flux at the top surface of the channel can be considered to be uniform, and heat transfer through other surfaces is negligible. If the velocity of the air at the inlet of the channel is not to exceed \(4 \mathrm{~m} / \mathrm{s}\) and the surface temperature of the channel is to remain under \(50^{\circ} \mathrm{C}\), determine the maximum total power of the electronic components that can safely be mounted on this circuit board. As a first approximation, assume flow is fully developed in the channel. Evaluate properties of air at a bulk mean temperature of \(25^{\circ} \mathrm{C}\). Is this a good assumption?

Water is flowing in fully developed conditions through a 3 -cm-diameter smooth tube with a mass flow rate of \(0.02 \mathrm{~kg} / \mathrm{s}\) at \(15^{\circ} \mathrm{C}\). Determine \((a)\) the maximum velocity of the flow in the tube and \((b)\) the pressure gradient for the flow.

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