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In fully developed laminar flow inside a circular pipe, the velocities at \(r=0.5 R\) (midway between the wall surface and the centerline) are measured to be 3,6 , and \(9 \mathrm{~m} / \mathrm{s}\). (a) Determine the maximum velocity for each of the measured midway velocities. (b) By varying \(r / R\) for \(-1 \leq\) \(r / R \leq 1\), plot the velocity profile for each of the measured midway velocities with \(r / R\) as the \(y\)-axis and \(V(r / R)\) as the \(x\)-axis.

Short Answer

Expert verified
Answer: The maximum velocities at the center of the pipe for each midway velocity are: (a) 2 m/s for the 3 m/s midway velocity, (b) 4 m/s for the 6 m/s midway velocity, and (c) 6 m/s for the 9 m/s midway velocity. The velocity profiles are plotted using the Hagen-Poiseuille equation for each maximum velocity with respect to r/R from -1 to 1, with r/R on the y-axis and V(r/R) on the x-axis. The resulting graphs show the velocity profiles for each measured midway velocity.

Step by step solution

01

Understanding the Hagen-Poiseuille equation

The Hagen-Poiseuille equation is given by: \[V(r) = 2V_{max}\left(1 - \frac{r^2}{R^2}\right)\] where V(r) is the velocity at a radius r, \(V_{max}\) is the maximum velocity, and R is the radius of the circular pipe.
02

Determine the maximum velocity for midway velocities

We are given three midway velocities at r = 0.5R. For each midway velocity, we can use the Hagen-Poiseuille equation to find the corresponding maximum velocity V_max. The equation for \(V(0.5R)\) is: \[V(0.5R) = 2V_{max}\left(1 - \frac{(0.5R)^2}{R^2}\right)\] Let's solve for each maximum velocity: (a) Midway velocity 3 m/s: \[3 = 2V_{max}\left(1 - \frac{1}{4}\right)\] \[V_{max1} = \frac{3}{1.5} = 2 \mathrm{~m} / \mathrm{s}\] (b) Midway velocity 6 m/s: \[6 = 2V_{max}\left(1 - \frac{1}{4}\right)\] \[V_{max2} = \frac{6}{1.5} = 4 \mathrm{~m} / \mathrm{s}\] (c) Midway velocity 9 m/s: \[9 = 2V_{max}\left(1 - \frac{1}{4}\right)\] \[V_{max3} = \frac{9}{1.5} = 6 \mathrm{~m} / \mathrm{s}\]
03

Plot the velocity profile for each measured midway velocity

We now need to plot the velocity profile V(r/R) for each of the measured midway velocities by varying r/R from -1 to 1, with r/R on the y-axis and V(r/R) on the x-axis. We will use the Hagen-Poiseuille equation with respective maximum velocities: (a) \(V_{max1} = 2 \mathrm{~m} / \mathrm{s}\): \[V(r/R) = 4\left(1 - r^2/R^2\right)\] (b) \(V_{max2} = 4 \mathrm{~m} / \mathrm{s}\): \[V(r/R) = 8\left(1 - r^2/R^2\right)\] (c) \(V_{max3} = 6 \mathrm{~m} / \mathrm{s}\): \[V(r/R) = 12\left(1 - r^2/R^2\right)\] The next step is to plot the above equations with respect to the y-axis (r/R) and the x-axis (V(r/R)) in a graphing software or calculator. The resulting graphs will show the velocity profiles for each measured midway velocity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hagen-Poiseuille Equation
The Hagen-Poiseuille equation is a fundamental principle in fluid dynamics that describes the velocity profile of laminar flow through a circular pipe. It is crucial for understanding how fluids behave under certain conditions, particularly in systems where precision matters, like in medical devices or industrial applications.

In a laminar flow through a pipe, the fluid in the center moves faster than fluid near the edges due to frictional forces. The Hagen-Poiseuille equation, expressed as \(V(r) = 2V_{max}\big(1 - ({r^2}/{R^2})\big)\), mathematically defines this velocity distribution. Here, \(V(r)\) is the fluid velocity at a distance \(r\) from the center, \(V_{max}\) is the maximum velocity at the center of the pipe, and \(R\) is the pipe's radius.

Understanding this equation helps in predicting the flow rate and designing pipes to regulate fluid flow effectively. An insightful exercise improvement advice is to encourage students to manually calculate several velocity values at different radii to improve their hands-on understanding of the equation's implications.
Maximum Velocity Determination
Determining the maximum velocity of a fluid inside a pipe is key to many engineering applications, ranging from designing water supply systems to predicting blood flow in veins. When you have a measured velocity at any point within the pipe, this value allows you to compute the maximum velocity at the center where the fluid encounters the least resistance.

In the given exercise, velocities are known at the midpoint between the wall and the centerline, allowing for the use of the Hagen-Poiseuille equation to determine the maximum velocity \(V_{max}\). For example, when a midway velocity (\(V(0.5R)\)) of 3 m/s is given, the equation modifies to \(3 = 2V_{max}(1 - {1}/{4})\), which can be rearranged to find the \(V_{max}\). This concept not only teaches students about fluid dynamics but also reinforces algebraic manipulation skills. It's advisable to perform these calculations for different midpoint velocities to build a stronger intuition of how the maximum velocity correlates with the measured velocity at other points.
Velocity Profile Plotting
Plotting the velocity profile of a fluid flow within a circular pipe is a visually engaging way to understand laminar flow characteristics. It involves using the Hagen-Poiseuille equation to calculate the velocity at various points and then graphically representing these velocities. This graphical representation helps students better visualize how the fluid's velocity decreases from the center of the pipe to its walls.

For instance, with a maximum velocity \(V_{max}\), you can calculate the corresponding velocity \(V(r/R)\) across different radial positions by graphing the equation \(V(r/R) = 2V_{max}(1 - r^2/R^2)\) for values of \(r/R\) from -1 to 1. It's beneficial to encourage students to use different tools, like graphing calculators or software, to plot these profiles, as it enhances their digital literacy and data interpretation skills.

Visualizing Fluid Dynamics

Through velocity profile plotting, students can observe the parabolic shape of the velocity distribution—a characteristic of laminar flow in pipes. This gives a tangible form to theoretical concepts, an excellent exercise improvement advice to solidify their comprehension of fluid mechanics.

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Most popular questions from this chapter

A geothermal district heating system involves the transport of geothermal water at \(110^{\circ} \mathrm{C}\) from a geothermal well to a city at about the same elevation for a distance of \(12 \mathrm{~km}\) at a rate of \(1.5 \mathrm{~m}^{3} / \mathrm{s}\) in \(60-\mathrm{cm}\)-diameter stainless steel pipes. The fluid pressures at the wellhead and the arrival point in the city are to be the same. The minor losses are negligible because of the large length-to-diameter ratio and the relatively small number of components that cause minor losses. (a) Assuming the pump-motor efficiency to be 65 percent, determine the electric power consumption of the system for pumping. \((b)\) Determine the daily cost of power consumption of the system if the unit cost of electricity is $$\$ 0.06 / \mathrm{kWh}$$. (c) The temperature of geothermal water is estimated to drop \(0.5^{\circ} \mathrm{C}\) during this long flow. Determine if the frictional heating during flow can make up for this drop in temperature.

In the fully developed region of flow in a circular tube, will the velocity profile change in the flow direction? How about the temperature profile?

Air enters a 25-cm-diameter 12 -m-long underwater duct at \(50^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) at a mean velocity of \(7 \mathrm{~m} / \mathrm{s}\), and is cooled by the water outside. If the average heat transfer coefficient is \(85 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and the tube temperature is nearly equal to the water temperature of \(10^{\circ} \mathrm{C}\), determine the exit temperature of air and the rate of heat transfer. Evaluate air properties at a bulk mean temperature of \(30^{\circ} \mathrm{C}\). Is this a good assumption?

A \(15-\mathrm{cm} \times 20\)-cm printed circuit board whose components are not allowed to come into direct contact with air for reliability reasons is to be cooled by passing cool air through a 20 -cm-long channel of rectangular cross section \(0.2 \mathrm{~cm} \times 14 \mathrm{~cm}\) drilled into the board. The heat generated by the electronic components is conducted across the thin layer of the board to the channel, where it is removed by air that enters the channel at \(15^{\circ} \mathrm{C}\). The heat flux at the top surface of the channel can be considered to be uniform, and heat transfer through other surfaces is negligible. If the velocity of the air at the inlet of the channel is not to exceed \(4 \mathrm{~m} / \mathrm{s}\) and the surface temperature of the channel is to remain under \(50^{\circ} \mathrm{C}\), determine the maximum total power of the electronic components that can safely be mounted on this circuit board. As a first approximation, assume flow is fully developed in the channel. Evaluate properties of air at a bulk mean temperature of \(25^{\circ} \mathrm{C}\). Is this a good assumption?

Consider laminar flow in a circular tube. Will the friction factor be higher near the inlet of the tube or near the exit? Why? What would your response be if the flow were turbulent?

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