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What does the logarithmic mean temperature difference represent for flow in a tube whose surface temperature is constant? Why do we use the logarithmic mean temperature instead of the arithmetic mean temperature?

Short Answer

Expert verified
Answer: The logarithmic mean temperature difference (LMTD) is significant in a tube with constant surface temperature because it accurately represents the heat transfer effectiveness, taking into account the varying temperature differences along the length of the tube. LMTD is used instead of the arithmetic mean temperature because the latter would not provide an accurate representation since the temperature difference between the hot and cold fluid streams typically varies along the length of the heat exchanger.

Step by step solution

01

Define Logarithmic Mean Temperature Difference (LMTD)

The logarithmic mean temperature difference (LMTD) is a term used in heat transfer calculations to quantify the effectiveness of heat transfer in a heat exchanger. It takes into account the temperature difference between the hot and cold fluid streams, as well as the varying temperature differences along the length of the heat exchanger. Mathematically, LMTD is expressed as: LMTD = (\(\frac{ΔT_1 - ΔT_2}{\ln(\frac{ΔT_1}{ΔT_2})}\)) Where: ΔT1 = Temperature difference between hot and cold streams at one end of the heat exchanger ΔT2 = Temperature difference between hot and cold streams at the other end of the heat exchanger
02

Understand the Significance of LMTD in a Tube with Constant Surface Temperature

When flow occurs in a tube whose surface temperature is constant, the temperature difference changes along the length of the tube as the hot fluid transfers heat to the colder fluid. In this case, using a simple arithmetic mean temperature difference would not accurately represent the heat transfer effectiveness of the tube. The LMTD is used because it considers the varying temperature differences along the length of the tube, making it a more accurate representation of the heat transfer effectiveness.
03

Explain Why LMTD is Used Instead of Arithmetic Mean Temperature

The arithmetic mean temperature difference would be an accurate representation of heat transfer effectiveness if the temperature difference between the hot and cold fluid streams remained constant along the length of the heat exchanger. However, in reality, this is rarely the case. The LMTD is used instead of the arithmetic mean temperature because it takes into account the varying temperature differences between the hot and cold fluid streams along the length of the heat exchanger. In conclusion, the logarithmic mean temperature difference (LMTD) represents the effectiveness of heat transfer in a tube whose surface temperature is constant. LMTD is used instead of the arithmetic mean temperature as it accurately accounts for the varying temperature differences along the length of the tube, providing a more precise measure of heat transfer effectiveness.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Exchanger Effectiveness
In the realm of thermal engineering, heat exchanger effectiveness is a critical measure of a heat exchanger's ability to transfer heat between two fluids. It is defined as the ratio of the actual heat transfer to the maximum possible heat transfer. This concept is not only pivotal in design but also in the evaluation of the performance of existing heat exchangers.

When talking about effectiveness, the Logarithmic Mean Temperature Difference (LMTD) plays a vital role. Imagine the heat exchanger as a thermal battleground, where two fluids with different temperatures come to exchange their thermal energy. The effectiveness is, thus, a measure of how well this exchange has been orchestrated. LMTD is preferred over the arithmetic mean because it accurately reflects the non-linear temperature profile of the fluids as they move through the exchanger. By using LMTD, engineers can ensure that the design of the heat exchanger is optimized for the most effective transfer of heat.

In practice, the LMTD is critical when determining the size of the heat exchanger. The larger the LMTD, the smaller the size of the heat exchanger needs to be to achieve a certain heat transfer rate. It is a designer's trusty compass for navigating through the complexities of heat exchanger performance.
Temperature Gradient in Heat Transfer
Heat transfer is a cornerstone in understanding how energy moves from one place to another, often manifesting itself through a temperature gradient. The temperature gradient is essentially a mathematical slope that represents how temperature changes across a distance in a substance.

In the context of heat exchangers, where two fluids with different temperatures interact, this gradient is continuously changing along the length of the exchanger. The temperature of each fluid stream gradually aligns toward an equilibrium, leading to a non-linear temperature profile. To capture this dynamic behavior, the LMTD takes the spotlight. It embodies the average temperature driving force over the length of the heat exchanger and offers a truer depiction of the actual temperature gradients at play.

To illuminate this better, we can consider the flow inside a tube with a constant surface temperature. As fluid flows through the tube, it either gains or loses heat, creating a varying temperature gradient. The LMTD compensates for these variations, allowing for a more precise analysis of the temperature differences that drive the heat transfer. Therefore, understanding the temperature gradient is indispensable for any thermal analysis or design, especially when considering the efficiency of heat transfer in any application.
Heat Transfer Calculations

Understanding LMTD

Heat transfer calculations are at the heart of designing and evaluating thermal systems. LMTD is a foundational component of these calculations. Whether you are sizing a heat exchanger or analyzing its performance, the LMTD is an indispensable tool. It bridges the gap between the theoretical maximum and the actual thermal performance.

The calculation of LMTD, as shown in the aforementioned steps, is performed using the temperature differences at both ends of the heat exchanger. This allows for an integrated approach to consider the varying temperature differences along the heat exchanger rather than just an average.

Practical Implications

Engineers use the LMTD to calculate the required surface area for the exchanger, the heat transfer rate, and to make decisions about the flow arrangement (parallel flow, counterflow, or cross-flow). In summary, LMTD and the heat transfer calculations that derive from it, guide designers and engineers through a quantifiable process, ensuring thermal systems operate with optimal efficiency and minimal material consumption.

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Most popular questions from this chapter

Water \(\left(\mu=9.0 \times 10^{-4} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, \rho=1000 \mathrm{~kg} / \mathrm{m}^{3}\right)\) enters a 2-cm- diameter and 3-m-long tube whose walls are maintained at \(100^{\circ} \mathrm{C}\). The water enters this tube with a bulk temperature of \(25^{\circ} \mathrm{C}\) and a volume flow rate of \(3 \mathrm{~m}^{3} / \mathrm{h}\). The Reynolds number for this internal flow is (a) 59,000 (b) 105,000 (d) 236,000 (e) 342,000 (c) 178,000

Air \(\left(c_{p}=1007 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters a 17 -cm-diameter and 4-m-long tube at \(65^{\circ} \mathrm{C}\) at a rate of \(0.08 \mathrm{~kg} / \mathrm{s}\) and leaves at \(15^{\circ} \mathrm{C}\). The tube is observed to be nearly isothermal at \(5^{\circ} \mathrm{C}\). The average convection heat transfer coefficient is (a) \(24.5 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (b) \(46.2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (c) \(53.9 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (d) \(67.6 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (e) \(90.7 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\)

Water enter a 5-mm-diameter and 13-m-long tube at \(45^{\circ} \mathrm{C}\) with a velocity of \(0.3 \mathrm{~m} / \mathrm{s}\). The tube is maintained at a constant temperature of \(5^{\circ} \mathrm{C}\). The required length of the tube in order for the water to exit the tube at \(25^{\circ} \mathrm{C}\) is (a) \(1.55 \mathrm{~m}\) (b) \(1.72 \mathrm{~m}\) (c) \(1.99 \mathrm{~m}\) (d) \(2.37 \mathrm{~m}\) (e) \(2.96 \mathrm{~m}\) (For water, use \(k=0.623 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=4.83, v=0.724 \times\) \(10^{-6} \mathrm{~m}^{2} / \mathrm{s}, c_{p}=4178 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \rho=994 \mathrm{~kg} / \mathrm{m}^{3}\).)

Liquid water enters a 10 - \(\mathrm{m}\)-long smooth rectangular tube with \(a=50 \mathrm{~mm}\) and \(b=25 \mathrm{~mm}\). The surface temperature is maintained constant, and water enters the tube at \(20^{\circ} \mathrm{C}\) with a mass flow rate of \(0.25 \mathrm{~kg} / \mathrm{s}\). Determine the tube surface temperature necessary to heat the water to the desired outlet temperature of \(80^{\circ} \mathrm{C}\).

Air at \(20^{\circ} \mathrm{C}(1 \mathrm{~atm})\) enters into a 5-mm-diameter and 10-cmlong circular tube at an average velocity of \(5 \mathrm{~m} / \mathrm{s}\). The tube wall is maintained at a constant surface temperature of \(160^{\circ} \mathrm{C}\). Determine the convection heat transfer coefficient and the outlet mean temperature. Evaluate the air properties at \(50^{\circ} \mathrm{C}\).

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