Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The bulk or mixed temperature of a fluid flowing through a pipe or duct is defined as (a) \(T_{b}=\frac{1}{A_{c}} \int_{A_{c}} T d A_{c}\) (b) \(T_{b}=\frac{1}{\dot{m}} \int_{A_{c}} T \rho V d A_{c}\) (c) \(T_{b}=\frac{1}{\dot{m}} \int_{A_{c}} h \rho V d A_{c}\) (d) \(T_{b}=\frac{1}{A_{c}} \int_{A_{c}} h d A_{c}\) (e) \(T_{b}=\frac{1}{\dot{V}} \int_{A_{c}} T \rho V d A_{c}\)

Short Answer

Expert verified
Answer: \(T_{b}=\frac{1}{\dot{m}} \int_{A_{c}} T \rho V d A_{c}\)

Step by step solution

01

Option (a) - \(T_{b}=\frac{1}{A_{c}} \int_{A_{c}} T d A_{c}\)

This option involves integrating the temperature \(T\) over the cross-sectional area \(A_c\) and dividing the result by \(A_c\). Physically, this would mean that we're taking the average of the temperatures in different parts.cross the pipe, to calculate the bulk temperature. This equation does not account for factors such as density, velocity, or enthalpy of fluid flow.
02

Option (b) - \(T_{b}=\frac{1}{\dot{m}} \int_{A_{c}} T \rho V d A_{c}\)

This equation involves integrating the product of density (\(\rho\)), velocity (\(V\)), and temperature (\(T\)) over the cross-sectional area (\(A_c\)) and dividing the result by the mass flow rate (\(\dot{m}\)). This definition takes into account the different speeds and densities of fluid particles across the cross-section area when calculating the bulk temperature, making this equation physically meaningful.
03

Option (c) - \(T_{b}=\frac{1}{\dot{m}} \int_{A_{c}} h \rho V d A_{c}\)

In this option, the bulk temperature is represented as the integration of the product of enthalpy (\(h\)), density (\(\rho\)), and velocity (\(V\)) across the cross-sectional area (\(A_c\)), divided by the mass flow rate (\(\dot{m}\)). The presence of enthalpy instead of temperature in the equation doesn't fulfill the requirement of calculating the bulk temperature.
04

Option (d) - \(T_{b}=\frac{1}{A_{c}} \int_{A_{c}} h d A_{c}\)

This option is very similar to option (a), but with enthalpy (\(h\)) instead of temperature (\(T\)). Again, this equation does not correctly represent the definition of the bulk temperature as the formula calculates the bulk enthalpy.
05

Option (e) - \(T_{b}=\frac{1}{\dot{V}} \int_{A_{c}} T \rho V d A_{c}\)

This option integrates the product of density (\(\rho\)), velocity (\(V\)), and the temperature (\(T\)) across the cross-sectional area (\(A_c\)) and divides by the volume flow rate (\(\dot{V}\)). Dividing by the volume flow rate does not provide a meaningful representation of the bulk temperature. After analyzing all five options, option (b) provides the most accurate and meaningful definition for the bulk temperature of a fluid flowing through a pipe or duct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Mechanics
Fluid mechanics is a crucial branch of physics involved in the study of the movement of fluids, whether liquid or gas. It encompasses the behavior of these fluids under various forces and in different environmental conditions. When discussing fluid flow through a pipe or duct, an integral concept is the distribution of temperature within the fluid.

This distribution is not uniform; the fluid closer to the pipe's wall is often cooler due to heat loss, whereas the fluid in the center may be warmer. Comprehensive knowledge of fluid mechanics enables us to understand 'bulk temperature,' which refers to an average temperature that accounts for this uneven distribution. It is calculated by considering both the velocity and the cross-sectional area, ensuring that each element of the fluid's volume contributes to the final temperature estimate according to its flow speed and proximity to heat transfer surfaces.
Heat Transfer
Heat transfer in fluid mechanics pertains to how thermal energy moves within the fluid and between the fluid and its surroundings. It's a fundamental aspect when understanding the temperature distribution across different sections of the fluid's flow.

There are three modes of heat transfer: conduction, convection, and radiation, but in the context of fluid flowing through a pipe, conduction and convection are most relevant. Convection occurs as the fluid moves, carrying energy with it. When considering the temperature at any point in the fluid, we must integrate the effects of these heat transfer modes to find the bulk temperature. Unlike a straightforward average, the bulk temperature takes into account the varying flow velocities and properties of the fluid, which could affect heat convection rates and result in a more accurate representation of the fluid's thermal state.
Mass Flow Rate
The mass flow rate, denoted by \(\dot{m}\), represents the amount of mass passing through a given cross-sectional area of a pipe or duct per unit time. It is a vital parameter in fluid dynamics and thermodynamics as it characterizes the quantity of fluid moving and its potential to transport energy.

In the equation for bulk temperature, the mass flow rate becomes particularly important when integrating the temperature across the cross-sectional area. It helps in normalizing the temperature distribution by the amount of mass flow, giving a realistic and precise value that considers variations in speed and density within the flowing fluid. The accurate calculation of bulk temperature hinges on recognizing the mass flow rate, a measure that bridges fluid mechanics and thermodynamics to provide insights into the energy characteristics of the system.
Thermodynamics
Thermodynamics is another foundational concept that intersects with fluid mechanics in the analysis of bulk temperature. It involves the study of heat and temperature and their connection to energy and work. The principles of thermodynamics are crucial in understanding how energy transfer is related to the physical properties of the fluid and how these properties change as the fluid flows and undergoes temperature variations.

For fluid flow in a pipe, thermodynamics tells us that the temperature field will be affected by energy transfer processes such as work done by or on the fluid and heat exchange with the pipe's walls. The equation for bulk temperature is a thermodynamic application that aims to summarize a complex temperature landscape into a single, effective temperature value, accounting for the various dynamic energy interactions within a moving fluid.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Air at \(10^{\circ} \mathrm{C}\) enters an \(18-\mathrm{m}\)-long rectangular duct of cross section \(0.15 \mathrm{~m} \times 0.20 \mathrm{~m}\) at a velocity of \(4.5 \mathrm{~m} / \mathrm{s}\). The duct is subjected to uniform radiation heating throughout the surface at a rate of \(400 \mathrm{~W} / \mathrm{m}^{3}\). The wall temperature at the exit of the duct is (a) \(58.8^{\circ} \mathrm{C}\) (b) \(61.9^{\circ} \mathrm{C}\) (c) \(64.6^{\circ} \mathrm{C}\) (d) \(69.1^{\circ} \mathrm{C}\) (e) \(75.5^{\circ} \mathrm{C}\) (For air, use \(k=0.02551 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=0.7296, v=1.562 \times\) \(10^{-5} \mathrm{~m}^{2} / \mathrm{s}, c_{p}=1007 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \rho=1.184 \mathrm{~kg} / \mathrm{m}^{3}\).)

How is the hydrodynamic entry length defined for flow in a tube? Is the entry length longer in laminar or turbulent flow?

Water is to be heated from \(10^{\circ} \mathrm{C}\) to \(80^{\circ} \mathrm{C}\) as it flows through a 2 -cm-internal-diameter, 13 -m-long tube. The tube is equipped with an electric resistance heater, which provides uniform heating throughout the surface of the tube. The outer surface of the heater is well insulated, so that in steady operation all the heat generated in the heater is transferred to the water in the tube. If the system is to provide hot water at a rate of \(5 \mathrm{~L} / \mathrm{min}\), determine the power rating of the resistance heater. Also, estimate the inner surface temperature of the pipe at the exit.

A \(15-\mathrm{cm} \times 20\)-cm printed circuit board whose components are not allowed to come into direct contact with air for reliability reasons is to be cooled by passing cool air through a 20 -cm-long channel of rectangular cross section \(0.2 \mathrm{~cm} \times 14 \mathrm{~cm}\) drilled into the board. The heat generated by the electronic components is conducted across the thin layer of the board to the channel, where it is removed by air that enters the channel at \(15^{\circ} \mathrm{C}\). The heat flux at the top surface of the channel can be considered to be uniform, and heat transfer through other surfaces is negligible. If the velocity of the air at the inlet of the channel is not to exceed \(4 \mathrm{~m} / \mathrm{s}\) and the surface temperature of the channel is to remain under \(50^{\circ} \mathrm{C}\), determine the maximum total power of the electronic components that can safely be mounted on this circuit board. As a first approximation, assume flow is fully developed in the channel. Evaluate properties of air at a bulk mean temperature of \(25^{\circ} \mathrm{C}\). Is this a good assumption?

A 10 -m-long and 10 -mm-inner-diameter pipe made of commercial steel is used to heat a liquid in an industrial process. The liquid enters the pipe with \(T_{i}=25^{\circ} \mathrm{C}, V=0.8 \mathrm{~m} / \mathrm{s}\). A uniform heat flux is maintained by an electric resistance heater wrapped around the outer surface of the pipe, so that the fluid exits at \(75^{\circ} \mathrm{C}\). Assuming fully developed flow and taking the average fluid properties to be \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=\) \(4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=2 \times 10^{-3} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, k=0.48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(\operatorname{Pr}=10\), determine: (a) The required surface heat flux \(\dot{q}_{s}\), produced by the heater (b) The surface temperature at the exit, \(T_{s}\) (c) The pressure loss through the pipe and the minimum power required to overcome the resistance to flow.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free