Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Reconsider Prob. 7-67E. Using EES (or other) software, investigate the effects of air temperature and wind velocity on the rate of heat loss from the arm. Let the air temperature vary from \(20^{\circ} \mathrm{F}\) to \(80^{\circ} \mathrm{F}\) and the wind velocity from \(10 \mathrm{mph}\) to \(40 \mathrm{mph}\). Plot the rate of heat loss as a function of air temperature and of wind velocity, and discuss the results.

Short Answer

Expert verified
Answer: The rate of heat loss from an arm increases as air temperature decreases and wind velocity increases. This is because the temperature difference between the arm's surface and the surrounding air and the convective heat transfer coefficient both increase, leading to a higher rate of heat transfer.

Step by step solution

01

Understand the problem context

In this problem, we are trying to find the rate of heat loss from an arm. The heat loss will depend on air temperature and wind velocity. The goal is to generate a plot displaying the relationship between these variables and the heat loss rate.
02

Choose an appropriate heat transfer model

We can use the convective heat transfer model to estimate the rate of heat loss from the arm to the surrounding air. The convective heat transfer equation is given by: \(Q = hA(T_{s} - T_{a})\) where \(Q\) is the heat transfer rate, \(h\) is the convective heat transfer coefficient, \(A\) is the surface area of the arm, \(T_{s}\) is the surface temperature of the arm, and \(T_{a}\) is the air temperature.
03

Account for the effect of wind velocity

Wind velocity affects the convective heat transfer coefficient (\(h\)). To include the effect of wind velocity, we can use the following expression for the heat transfer coefficient: \(h = f(V)\) where \(f\) is a function that relates wind velocity (\(V\)) to the heat transfer coefficient.
04

Generate the necessary plots

With the appropriate equations and functions in place, we can use software (e.g., EES, MATLAB, or Python) to generate the required plots. In this step, we will evaluate the heat transfer rate and create two plots: 1. Rate of heat loss as a function of air temperature (varying air temperature from \(20^{\circ}\mathrm{F}\) to \(80^{\circ}\mathrm{F}\) while keeping wind velocity constant) 2. Rate of heat loss as a function of wind velocity (varying wind velocity from \(10\mathrm{mph}\) to \(40\mathrm{mph}\) while keeping air temperature constant)
05

Discuss the results

Analyze the graphs generated in Step 4. Typically, the following observations can be made: 1. The rate of heat loss increases as the air temperature decreases. This is because the temperature difference between the arm's surface and the surrounding air increases, resulting in a higher rate of heat transfer. 2. The rate of heat loss increases as the wind velocity increases. This is because the convective heat transfer coefficient increases with wind velocity, leading to a higher rate of heat transfer. In conclusion, air temperature and wind velocity significantly influence the rate of heat loss from an arm. These findings can be used to inform activities and clothing choices in different environmental conditions as well as designing heating systems for outdoor spaces.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Heat Loss
The rate of heat loss is a measure of how quickly heat energy is transferred from one body to another. Specifically, in our exercise, we're looking at how heat moves away from an arm into the surrounding air. This process is heavily influenced by various factors, most notably through convection, which is the transfer of heat by the movement of fluids such as air or water. When investigating this rate, we use the equation: \[ Q = hA(T_{s} - T_{a}) \] where
  • \( Q \) represents the heat transfer rate in BTU/hr or watts,
  • \( h \) is the convective heat transfer coefficient, indicating how well heat is transferred,
  • \( A \) stands for the surface area of the arm being analyzed,
  • \( T_{s} \) denotes the surface temperature of the arm,
  • \( T_{a} \) is the ambient air temperature.
The larger the difference between the arm temperature and the air temperature, \( T_{s} - T_{a} \), the greater the potential for heat loss. As the convective heat transfer coefficient \( h \) increases, typically influenced by wind, the rate of heat loss \( Q \) also increases. This understanding is vital in many practical scenarios, such as designing clothing or building heating systems to minimize energy loss.
Air Temperature
Air temperature plays a key role in determining the rate of heat loss. In simple terms, the colder the air surrounding the arm, the greater the heat loss. This is due to the enhanced temperature difference between the arm's surface temperature and the ambient air temperature \( T_{a} \). As outlined in the heat transfer equation, the rate of heat loss \( Q \) depends on this difference:\[ Q = hA(T_{s} - T_{a}) \]When the air is significantly colder than the body part in question, the disparity \( T_{s} - T_{a} \) becomes larger, accelerating heat loss to the environment. This concept is essential for understanding how protective clothing is designed to keep people warm in varying temperatures.
  • For a range from \(20^{\circ}\mathrm{F}\) to \(80^{\circ}\mathrm{F}\), as the temperature increases, heat loss generally diminishes.
  • This trend is why environments with frigid temperatures pose more of a challenge for retaining body heat.
  • Consequently, this understanding allows for informed clothing decisions or heating adjustments relevant to outdoor activities or occupations.
Wind Velocity
Wind velocity impacts the rate of heat loss predominantly by influencing the convective heat transfer coefficient \( h \). Essentially, wind increases air movement, enhancing the convective heat transfer and thus accelerating the rate at which heat is carried away from the body. This effect is often felt very quickly as a more pronounced chill on a windy day. The relationship between wind velocity and the heat transfer coefficient can be expressed by a functional relationship \( h = f(V) \) where \( V \) is the wind speed. Generally, the main effects of increasing wind velocity include:
  • Increased air circulation over surfaces, which enhances convective heat transfer.
  • A rise in \( h \), leading to greater overall heat loss at a faster pace.
  • Even at constant temperatures, wind amplifies the sensation of cold, emphasizing the need for wind-resistant clothing.
In practical terms, understanding wind's role in heat loss ensures that outdoor clothing, structures, and activities are designed with adequate protection to moderate or counteract the increased heat dispersion caused by high wind speeds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

During a plant visit, it was noticed that a 12-m-long section of a \(10-\mathrm{cm}\)-diameter steam pipe is completely exposed to the ambient air. The temperature measurements indicate that the average temperature of the outer surface of the steam pipe is \(75^{\circ} \mathrm{C}\) when the ambient temperature is \(5^{\circ} \mathrm{C}\). There are also light winds in the area at \(10 \mathrm{~km} / \mathrm{h}\). The emissivity of the outer surface of the pipe is \(0.8\), and the average temperature of the surfaces surrounding the pipe, including the sky, is estimated to be \(0^{\circ} \mathrm{C}\). Determine the amount of heat lost from the steam during a 10 -h-long work day. Steam is supplied by a gas-fired steam generator that has an efficiency of 80 percent, and the plant pays \(\$ 1.05 /\) therm of natural gas. If the pipe is insulated and 90 percent of the heat loss is saved, determine the amount of money this facility will save a year as a result of insulating the steam pipes. Assume the plant operates every day of the year for \(10 \mathrm{~h}\). State your assumptions.

Air at \(15^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) flows over a \(0.3\)-m-wide plate at \(65^{\circ} \mathrm{C}\) at a velocity of \(3.0 \mathrm{~m} / \mathrm{s}\). Compute the following quantities at \(x=0.3 \mathrm{~m}\) : (a) Hydrodynamic boundary layer thickness, \(\mathrm{m}\) (b) Local friction coefficient (c) Average friction coefficient (d) Total drag force due to friction, \(\mathrm{N}\) (e) Local convection heat transfer coefficient, W/m² \(\mathbf{K}\) (f) Average convection heat transfer coefficient, W/m² \(\mathrm{K}\) (g) Rate of convective heat transfer, W

Ambient air at \(20^{\circ} \mathrm{C}\) flows over a 30-cm-diameter hot spherical object with a velocity of \(2.5 \mathrm{~m} / \mathrm{s}\). If the average surface temperature of the object is \(200^{\circ} \mathrm{C}\), the average convection heat transfer coefficient during this process is \(\begin{array}{ll}\text { (a) } 5.0 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K} & \text { (b) } 6.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\end{array}\) (c) \(7.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) (d) \(9.3 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) (e) \(11.7 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) (For air, use \(k=0.2514 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \mathrm{Pr}=0.7309, v=1.516 \times\) \(\left.10^{-5} \mathrm{~m}^{2} / \mathrm{s}, \mu_{s}=1.825 \times 10^{-5} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, \mu_{s}=2.577 \times 10^{-5} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\right)\)

Exposure to high concentration of gaseous ammonia can cause lung damage. To prevent gaseous ammonia from leaking out, ammonia is transported in its liquid state through a pipe \(\left(k=25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, D_{i, \text { pipe }}=2.5 \mathrm{~cm}\right.\), \(D_{o, \text { pipe }}=4 \mathrm{~cm}\), and \(\left.L=10 \mathrm{~m}\right)\). Since liquid ammonia has a normal boiling point of \(-33.3^{\circ} \mathrm{C}\), the pipe needs to be properly insulated to prevent the surrounding heat from causing the ammonia to boil. The pipe is situated in a laboratory, where air at \(20^{\circ} \mathrm{C}\) is blowing across it with a velocity of \(7 \mathrm{~m} / \mathrm{s}\). The convection heat transfer coefficient of the liquid ammonia is \(100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Calculate the minimum insulation thickness for the pipe using a material with \(k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) to keep the liquid ammonia flowing at an average temperature of \(-35^{\circ} \mathrm{C}\), while maintaining the insulated pipe outer surface temperature at \(10^{\circ} \mathrm{C}\).

The local atmospheric pressure in Denver, Colorado (elevation \(1610 \mathrm{~m}\) ), is \(83.4 \mathrm{kPa}\). Air at this pressure and \(20^{\circ} \mathrm{C}\) flows with a velocity of \(8 \mathrm{~m} / \mathrm{s}\) over a \(1.5 \mathrm{~m} \times 6 \mathrm{~m}\) flat plate whose temperature is \(140^{\circ} \mathrm{C}\). Determine the rate of heat transfer from the plate if the air flows parallel to the \((a)\)-m-long side and \((b)\) the \(1.5 \mathrm{~m}\) side.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free