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Air at 1 atm and \(20^{\circ} \mathrm{C}\) is flowing over the top surface of a \(0.5-\mathrm{m}\)-long thin flat plate. The air stream velocity is \(50 \mathrm{~m} / \mathrm{s}\) and the plate is maintained at a constant surface temperature of \(180^{\circ} \mathrm{C}\). Determine \((a)\) the average friction coefficient, \((b)\) the average convection heat transfer coefficient, and (c) repeat part (b) using the modified Reynolds analogy.

Short Answer

Expert verified
Given: - Air temperature: \(20^{\circ} \mathrm{C}\) - Length \(x\) of the flat plate: \(0.5\) m - Free stream velocity \(u_\infty\): \(10\) m/s - Air properties at \(20^{\circ} \mathrm{C}\): - Density (\(\rho\)) = 1.205 kg/m³ - Dynamic viscosity (\(\mu\)) = 1.81 x \(10^{-5}\) kg/m.s - Specific heat capacity (\(c_p\)) = 1007 J/kg.K - Thermal conductivity (\(k\)) = 0.0262 W/m.K Steps: 1. Calculate Reynolds number and Prandtl number: \(Re_x = \frac{1.205 \times 10 \times 0.5}{1.81 \times 10^{-5}} = 332486.2\) \(Pr = \frac{1.81 \times 10^{-5} \times 1007}{0.0262} = 0.692\) 2. Calculate average friction coefficient: \(C_f = \frac{0.664}{\sqrt{332486.2}} = 0.00114\) 3. Calculate average convection heat transfer coefficient: \(Nu_x = 0.664 \times 332486.2^{1/2} \times 0.692^{1/3} \Rightarrow h_x = \frac{Nu_x \times k}{x} = 31.52\) W/m².K 4. Calculate average convection heat transfer coefficient using modified Reynolds analogy: \(Nu_x = 0.5 \times 0.00114 \times 332486.2 \times 0.692 \Rightarrow h_x = \frac{Nu_x \times k}{x} = 32.78\) W/m².K Results: a) The average friction coefficient is \(0.00114\). b) The average convection heat transfer coefficient calculated using Nusselt number is \(31.52\) W/m².K. c) The average convection heat transfer coefficient calculated using modified Reynolds analogy is \(32.78\) W/m².K.

Step by step solution

01

Calculate Reynolds number and Prandtl number

First, we need to find the Reynolds number and Prandtl number for air at \(20^{\circ} \mathrm{C}\). The properties of air at \(20^{\circ} \mathrm{C}\) are as follows: Density (\(\rho\)) = 1.205 kg/m³ Dynamic viscosity (\(\mu\)) = 1.81 x \(10^{-5}\) kg/m.s Specific heat capacity (\(c_p\)) = 1007 J/kg.K Thermal conductivity (\(k\)) = 0.0262 W/m.K Reynolds number is given by: \(Re_x = \frac{\rho u_\infty x}{\mu}\) Prandtl number is given by: \(Pr = \frac{\mu c_p}{k}\)
02

Calculate average friction coefficient (a)

Using the Blasius equation for friction coefficient, we can calculate the average friction coefficient: \(C_f = \frac{0.664}{\sqrt{Re_x}}\) Calculate \(Re_x\) and \(C_f\) for air at \(x = 0.5\) m.
03

Calculate average convection heat transfer coefficient (b)

Next, we will calculate the average convection heat transfer coefficient using the Nusselt number: \(Nu_x = \frac{h_x x}{k} = 0.664 Re_x^{1/2} Pr^{1/3}\) Solve for \(h_x\).
04

Calculate average convection heat transfer coefficient using modified Reynolds analogy (c)

Finally, use the modified Reynolds analogy to find the average convection heat transfer coefficient: \(Nu_x = \frac{C_fx}{2} Re_x Pr\) Solve for \(h_x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds number
The Reynolds number (Re) is a dimensionless quantity used in fluid mechanics to predict flow patterns in different fluid flow situations. It compares the relative importance of inertial effects to viscous effects and is defined by the equation:
\[Re_x = \frac{\rho u_{\infty} x}{\mu}\]
where:\
    \
  • \(\rho\) is the density of the fluid (in kg/m³),\
  • \
  • \(u_{\infty}\) is the flow velocity (in m/s),\
  • \
  • \(x\) is the characteristic length, in this case, the length of the plate (in meters), and\
  • \
  • \(\mu\) is the dynamic viscosity of the fluid (in kg/m⋅s).\
  • \

The higher the Reynolds number, the more turbulent the flow is likely to be; lower values indicate laminar flow. For a thin flat plate in an airstream, like in the above example, determining the Reynolds number helps us analyze the flow behavior: whether it's laminar or turbulent, which is essential for accurately calculating the friction coefficient and the heat transfer coefficient.
Reynolds number is crucial for predicting the onset of turbulence, and thus, its calculation forms the foundation for many convective heat transfer coefficient estimations.
Prandtl number
The Prandtl number (Pr) is another dimensionless number in fluid dynamics that is used to characterize the relative thickness of the velocity boundary layer to the thermal boundary layer. It is determined using the following equation:
\[Pr = \frac{\mu c_p}{k}\]
where:\
    \
  • \(\mu\) represents the dynamic viscosity of the fluid (in kg/m⋅s),\
  • \
  • \(c_p\) is the specific heat capacity at constant pressure (in J/kg⋅K), and\
  • \
  • \(k\) is the thermal conductivity of the fluid (in W/m⋅K).\
  • \

The Prandtl number indicates if the heat diffuses quickly or slowly compared to momentum (velocity). In the situation of air flowing over a plate, as per the given exercise, a higher Prandtl number would mean a slower thermal diffusion relative to velocity. This number affects the convection heat transfer calculations because it determines the thickness of the thermal boundary layer, which is integral to heat dissipation from the plate into the air.
Friction coefficient
The friction coefficient (Cf) is a key concept in determining the resistance that a fluid flow encounters when in contact with a surface. For the flow over a flat plate, it is estimated using the Blasius equation:
\[C_f = \frac{0.664}{\sqrt{Re_x}}\]
This equation presents the friction coefficient as inversely proportional to the square root of the Reynolds number (Re). The friction coefficient is indicative of the shear stress exerted by the flowing fluid on the plate's surface and is instrumental in predicting the frictional force experienced by the plate.
The friction coefficient affects not only the mechanical analysis of fluid-structure interactions but also thermal analysis when fluids are involved. This is demonstrated by the modified Reynolds analogy used in the exercise, which relates the friction coefficient to the convection heat transfer coefficient for the calculation of heat transfer between the air and the plate. A proper understanding of the friction coefficient aids in optimizing systems for better fluid flow and heat transfer characteristics.

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Most popular questions from this chapter

Wind at \(30^{\circ} \mathrm{C}\) flows over a \(0.5\)-m-diameter spherical tank containing iced water at \(0^{\circ} \mathrm{C}\) with a velocity of \(25 \mathrm{~km} / \mathrm{h}\). If the tank is thin-shelled with a high thermal conductivity material, the rate at which ice melts is (a) \(4.78 \mathrm{~kg} / \mathrm{h} \quad\) (b) \(6.15 \mathrm{~kg} / \mathrm{h}\) (c) \(7.45 \mathrm{~kg} / \mathrm{h}\) (d) \(11.8 \mathrm{~kg} / \mathrm{h}\) (e) \(16.0 \mathrm{~kg} / \mathrm{h}\) (Take \(h_{i f}=333.7 \mathrm{~kJ} / \mathrm{kg}\), and use the following for air: \(k=\) \(0.02588 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \operatorname{Pr}=0.7282, v=1.608 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}, \mu_{\infty}=\) \(\left.1.872 \times 10^{-5} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}, \mu_{\mathrm{s}}=1.729 \times 10^{-5} \mathrm{~kg} / \mathrm{m} \cdot \mathrm{s}\right)\)

Air is flowing in parallel over the upper surface of a flat plate with a length of \(4 \mathrm{~m}\). The first half of the plate length, from the leading edge, has a constant surface temperature of \(50^{\circ} \mathrm{C}\). The second half of the plate length is subjected to a uniform heat flux of \(86 \mathrm{~W} / \mathrm{m}^{2}\). The air has a free stream velocity and temperature of \(2 \mathrm{~m} / \mathrm{s}\) and \(10^{\circ} \mathrm{C}\), respectively. Determine the local convection heat transfer coefficients at \(1 \mathrm{~m}\) and \(3 \mathrm{~m}\) from the leading edge. Evaluate the air properties at a film temperature of \(30^{\circ} \mathrm{C}\). Is the film temperature \(T_{f}=30^{\circ} \mathrm{C}\) applicable at \(x=3 \mathrm{~m}\) ?

A glass \((k=1.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) spherical tank is filled with chemicals undergoing exothermic reaction. The reaction keeps the inner surface temperature of the tank at \(80^{\circ} \mathrm{C}\). The tank has an inner radius of \(0.5 \mathrm{~m}\) and its wall thickness is \(10 \mathrm{~mm}\). Situated in surroundings with an ambient temperature of \(15^{\circ} \mathrm{C}\) and a convection heat transfer coefficient of \(70 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), the tank's outer surface is being cooled by air flowing across it at \(5 \mathrm{~m} / \mathrm{s}\). In order to prevent thermal burn on individuals working around the container, it is necessary to keep the tank's outer surface temperature below \(50^{\circ} \mathrm{C}\). Determine whether or not the tank's outer surface temperature is safe from thermal burn hazards.

Consider a person who is trying to keep cool on a hot summer day by turning a fan on and exposing his body to air flow. The air temperature is \(32^{\circ} \mathrm{C}\), and the fan is blowing air at a velocity of \(5 \mathrm{~m} / \mathrm{s}\). The surrounding surfaces are at \(40^{\circ} \mathrm{C}\), and the emissivity of the person can be taken to be \(0.9\). If the person is doing light work and generating sensible heat at a rate of \(90 \mathrm{~W}\), determine the average temperature of the outer surface (skin or clothing) of the person. The average human body can be treated as a 30 -cm-diameter cylinder with an exposed surface area of \(1.7 \mathrm{~m}^{2}\). Evaluate the air properties at film temperature of \(35^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\).

Air at \(15^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) flows over a \(0.3\)-m-wide plate at \(65^{\circ} \mathrm{C}\) at a velocity of \(3.0 \mathrm{~m} / \mathrm{s}\). Compute the following quantities at \(x=x_{\mathrm{cr}}\) : (a) Hydrodynamic boundary layer thickness, \(\mathrm{m}\) (b) Local friction coefficient (c) Average friction coefficient (d) Total drag force due to friction, \(\mathrm{N}\) (e) Local convection heat transfer coefficient, \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\) (f) Average convection heat transfer coefficient, W/m² \(\cdot \mathrm{K}\) (g) Rate of convective heat transfer, W

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