Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider steady heat conduction in a plane wall whose left surface (node 0 ) is maintained at \(30^{\circ} \mathrm{C}\) while the right surface (node 8 ) is subjected to a heat flux of \(1200 \mathrm{~W} / \mathrm{m}^{2}\). Express the finite difference formulation of the boundary nodes 0 and 8 for the case of no heat generation. Also obtain the finite difference formulation for the rate of heat transfer at the left boundary.

Short Answer

Expert verified
Answer: The finite difference formulation for the rate of heat transfer at the left boundary of the plane wall is given by: $$q''_{0} = -k \left(\frac{T_{1} - 30}{\Delta x}\right)$$

Step by step solution

01

Understand the given information and notation

We have a plane wall with left surface (node 0) at a temperature of \(30^{\circ} \mathrm{C}\) and the right surface (node 8) subjected to a heat flux of \(1200 \mathrm{~W} / \mathrm{m}^{2}\). The heat conduction is steady, and there is no heat generation.
02

Apply the Finite Difference Method to the Boundary Nodes

The finite difference method can be applied to the boundary nodes by considering the governing equation for a steady heat conduction process without heat generation, which can be given by the Laplace equation: $$\nabla^{2} T = 0$$ Applying this to Node 0 and Node 8, we have: $$\frac{T_{1}-2 T_{0}}{\Delta x^{2}} = 0$$ and $$\frac{T_{7}-2 T_{8}}{\Delta x^{2}} = 0$$ For the boundary condition at the left surface (Node 0): $$T_{0} = 30$$ For the boundary condition at the right surface (Node 8): $$q'' = -k \frac{dT}{dx}\big|_{x=L} = 1200 \mathrm{~W}/\mathrm{m}^{2}$$
03

Express the Finite Difference Formulation for Boundary Nodes 0 and 8

Using the boundary conditions and the governing equations, we arrive at the expressions for the boundary nodes 0 and 8: For Node 0: $$T_{0} = 30^{\circ}C$$ For Node 8: $$T_{7} - 2 T_{8} = -1200 \Delta x \frac{1}{k \Delta x^2}$$
04

Obtain the Finite Difference Formulation for the Rate of Heat Transfer at the Left Boundary

Using the governing equation at Node 0 and the boundary condition for the left surface: $$\frac{T_{1} - 2T_{0}}{\Delta x^2} = 0$$ Solve for the rate of heat transfer at the left boundary from Node 0: $$q''_{0} = -k \left(\frac{T_{1} - T_{0}}{\Delta x}\right)$$ Replacing the temperature values at Node 0, we have: $$q''_{0} = -k \left(\frac{T_{1} - 30}{\Delta x}\right)$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Steady Heat Conduction
In the context of heat transfer, steady heat conduction refers to the process where heat flows through a medium without any change in temperature over time. This means that after a period of time, the temperature distribution in the material reaches an equilibrium state. There is no heat accumulation in or extraction from the material, making it a static condition.
The mathematical representation of steady heat conduction in a one-dimensional plane wall can be described by the Laplace equation:\[abla^2 T = 0\]This equation indicates that there is no change in the rate of heat flowing in and out across any section of the wall. In practice, applying this concept helps in predicting the temperature gradient within the wall, allowing for the optimization of insulation effectiveness or material selection in construction and manufacturing industries.
For example, in our exercise, we've considered a plane wall that is part of a steady-state heat conduction system. The left surface is at a constant temperature, implying a boundary condition for Node 0, and the right surface is exposed to a constant heat flux. This setup ensures that throughout the wall, temperature remains relatively constant over time, exemplifying steady-state behavior.
Boundary Conditions
Boundary conditions are crucial when solving heat conduction problems as they define how the system interacts with its surroundings. Essentially, boundary conditions allow us to apply realistic constraints or inputs into the mathematical models, resulting in accurate simulations and analysis.
In our problem:
  • The left boundary, Node 0, is maintained at a fixed temperature of \(30^{\circ} \mathrm{C}\). This is known as a Dirichlet boundary condition, where the exact value at the boundary is specified.
  • The right boundary, Node 8, is subject to a constant heat flux of \(1200 \mathrm{~W} / \mathrm{m}^2\). This represents a Neumann boundary condition, where instead of a fixed temperature, the rate of heat transfer (or its gradient) is specified.
Boundary conditions like these are essential in solving partial differential equations like the Laplace equation, as they narrow down the infinite possibilities to a realistic and applicable solution.
They act as the input and output requirements for our steady heat conduction analysis. Understanding and correctly applying these conditions enable us to predict how the temperature will distribute across the material over time, thus solving the finite difference approximations effectively.
Heat Transfer Rate
The heat transfer rate describes the quantity of heat energy transferred through a surface per unit time. It is a critical factor in designing and evaluating systems for heating, cooling, or maintaining temperatures.
In our exercise, calculating the heat transfer rate at the left boundary involves using the concepts of thermal conductivity and temperature gradients. The general equation for heat transfer rate at a boundary is given by.
  • Thermal conductivity \(k\): Measures a material's ability to conduct heat.
  • Temperature difference \(\Delta T\): The driving force behind heat transfer.
  • Geometry and thickness what \(\Delta x\) represents in the equation.
By substituting the appropriate boundary conditions at Node 0, the finite difference expression becomes:\[q''_0 = -k \left(\frac{T_1 - T_0}{\Delta x}\right)\]This formula allows us to determine the exact rate of heat transfer knowing the material properties and temperature differences. In practical applications, understanding this rate aids engineers in selecting materials or modifying designs to achieve desired thermal performance.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How is an insulated boundary handled in finite difference formulation of a problem? How does a symmetry line differ from an insulated boundary in the finite difference formulation?

Consider transient heat conduction in a plane wall whose left surface (node 0 ) is maintained at \(50^{\circ} \mathrm{C}\) while the right surface (node 6) is subjected to a solar heat flux of \(600 \mathrm{~W} / \mathrm{m}^{2}\). The wall is initially at a uniform temperature of \(50^{\circ} \mathrm{C}\). Express the explicit finite difference formulation of the boundary nodes 0 and 6 for the case of no heat generation. Also, obtain the finite difference formulation for the total amount of heat transfer at the left boundary during the first three time steps.

What are the basic steps involved in solving a system of equations with Gauss- Seidel method?

Design a fire-resistant safety box whose outer dimensions are \(0.5 \mathrm{~m} \times 0.5 \mathrm{~m} \times 0.5 \mathrm{~m}\) that will protect its combustible contents from fire which may last up to \(2 \mathrm{~h}\). Assume the box will be exposed to an environment at an average temperature of \(700^{\circ} \mathrm{C}\) with a combined heat transfer coefficient of \(70 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and the temperature inside the box must be below \(150^{\circ} \mathrm{C}\) at the end of \(2 \mathrm{~h}\). The cavity of the box must be as large as possible while meeting the design constraints, and the insulation material selected must withstand the high temperatures to which it will be exposed. Cost, durability, and strength are also important considerations in the selection of insulation materials.

Consider transient heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3,4\), and 5 with a uniform nodal spacing of \(\Delta x\). The wall is initially at a specified temperature. Using the energy balance approach, obtain the explicit finite difference formulation of the boundary nodes for the case of insulation at the left boundary (node 0 ) and radiation at the right boundary (node 5) with an emissivity of \(\varepsilon\) and surrounding temperature of \(T_{\text {surr }}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free