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Can we define the convection resistance for a unit surface area as the inverse of the convection heat transfer coefficient?

Short Answer

Expert verified
Answer: Yes, the convection resistance for a unit surface area can be defined as the inverse of the convection heat transfer coefficient. This relationship is derived from the equations of convection heat transfer coefficient (h) and convection resistance (R_conv), where h = 1 / R_conv.

Step by step solution

01

Understand the concepts involved

In order to answer this question, we need to comprehend two main topics: 1. Convection Resistance: In heat transfer, resistance represents the opposition to heat transfer. For convection, this opposition occurs due to the fluid flow over a surface. 2. Convection Heat Transfer Coefficient (h): This is a measure of the efficiency at which energy is transferred due to convection per unit area. It depends on the nature of the fluid and its flow properties.
02

Define the equations related to convection resistance and heat transfer coefficient

The convection heat transfer coefficient is typically represented as: h = Q / (A * ∆T) Where: - Q is the convective heat transfer (in Watts or W) - A is the surface area over which convection is occurring (in square meters or m^2) - ∆T is the temperature difference between the solid surface and the fluid (in Kelvin or K) Now, the convection resistance (R_conv) can be defined as the opposition to heat transfer per unit area. Mathematically, R_conv = ∆T / (Q/A)
03

Manipulate the heat transfer coefficient equation to establish the inverse relationship

Now, we will manipulate the equation we obtained for the convection heat transfer coefficient (h): h = Q / (A * ∆T) And, we will also rewrite the convection resistance equation: R_conv = ∆T / (Q/A) Notice that: Q / (A * ∆T) = 1 / (R_conv) Comparing these equations, we can see that: h = 1 / R_conv
04

Conclude the relationship between convection resistance and heat transfer coefficient

Based on the derived relationship h = 1 / R_conv, we can conclude that the convection resistance for a unit surface area can indeed be defined as the inverse of the convection heat transfer coefficient.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection Resistance
Convection resistance is a concept used in heat transfer to describe how much a fluid opposes the transfer of heat as it flows over a surface. When you think of resistance, consider it as a barrier that makes heat transfer harder. This resistance affects how quickly energy moves from a hot surface to a cooler fluid.
To understand convection resistance, first, imagine a warm surface that wants to transfer its heat to a fluid (like air or water) flowing over it. The convection resistance, often given the symbol \( R_{\text{conv}} \), represents how difficult it is for this heat transfer to occur.
Lower convection resistance means easier heat transfer and vice versa. It's a key player in determining how efficiently thermal energy is transferred between surfaces and fluids.
Convection Heat Transfer Coefficient
The convection heat transfer coefficient, denoted as \( h \), is a measure of how effectively heat is transferred due to convection per unit surface area.
Think of it as the rate of heat flow per unit area per degree of temperature difference between a surface and a fluid.
The equation representing the convection heat transfer coefficient is \( h = \frac{Q}{A \cdot \Delta T} \), where:
  • \( Q \) is the heat transferred in watts (W)
  • \( A \) is the surface area in square meters (m²)
  • \( \Delta T \) is the temperature difference in Kelvin (K)
This coefficient depends on the properties of the fluid, like its viscosity and temperature, as well as the nature of the flow, whether it's turbulent or laminar.
In general, higher \( h \) values signify more efficient heat transfer from the surface to the fluid.
Thermal Resistance Concepts
The concept of thermal resistance is crucial when studying heat transfer. It helps us understand how different materials and situations oppose the flow of heat.
In essence, thermal resistance is like a roadblock to heat flow.
When dealing with convection, thermal resistance gives us insight into how "tough" it is for a surface to pass its heat to a fluid moving over it.
In technical terms, for convective heat transfer, thermal resistance \( R_{\text{conv}} \) is the inverse of the convection heat transfer coefficient \( h \).
The magic formula is \( R_{\text{conv}} = \frac{1}{h} \).
  • Lower thermal resistance means better heat transfer.
  • Higher thermal resistance indicates more hindrance to heat transfer.
By analyzing thermal resistance, engineers can predict and manage the performance of heat transfer systems effectively.

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Most popular questions from this chapter

Heat is lost at a rate of \(275 \mathrm{~W}\) per \(\mathrm{m}^{2}\) area of a \(15-\mathrm{cm}-\) thick wall with a thermal conductivity of \(k=1.1 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The temperature drop across the wall is (a) \(37.5^{\circ} \mathrm{C}\) (b) \(27.5^{\circ} \mathrm{C}\) (c) \(16.0^{\circ} \mathrm{C}\) (d) \(8.0^{\circ} \mathrm{C}\) (e) \(4.0^{\circ} \mathrm{C}\)

What is a conduction shape factor? How is it related to the thermal resistance?

Two 3-m-long and \(0.4-\mathrm{cm}\)-thick cast iron \((k=\) \(52 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) steam pipes of outer diameter \(10 \mathrm{~cm}\) are connected to each other through two 1 -cm-thick flanges of outer diameter \(20 \mathrm{~cm}\). The steam flows inside the pipe at an average temperature of \(200^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(180 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The outer surface of the pipe is exposed to an ambient at \(12^{\circ} \mathrm{C}\), with a heat transfer coefficient of \(25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (a) Disregarding the flanges, determine the average outer surface temperature of the pipe. (b) Using this temperature for the base of the flange and treating the flanges as the fins, determine the fin efficiency and the rate of heat transfer from the flanges. (c) What length of pipe is the flange section equivalent to for heat transfer purposes?

Hot- and cold-water pipes \(8 \mathrm{~m}\) long run parallel to each other in a thick concrete layer. The diameters of both pipes are \(5 \mathrm{~cm}\), and the distance between the centerlines of the pipes is \(40 \mathrm{~cm}\). The surface temperatures of the hot and cold pipes are \(60^{\circ} \mathrm{C}\) and \(15^{\circ} \mathrm{C}\), respectively. Taking the thermal conductivity of the concrete to be \(k=0.75 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), determine the rate of heat transfer between the pipes.

A row of 3 -ft-long and 1-in-diameter used uranium fuel rods that are still radioactive are buried in the ground parallel to each other with a center-to- center distance of 8 in at a depth of \(15 \mathrm{ft}\) from the ground surface at a location where the thermal conductivity of the soil is \(0.6 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft} \cdot{ }^{\circ} \mathrm{F}\). If the surface temperature of the rods and the ground are \(350^{\circ} \mathrm{F}\) and \(60^{\circ} \mathrm{F}\), respectively, determine the rate of heat transfer from the fuel rods to the atmosphere through the soil.

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