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What does the thermal resistance of a medium represent?

Short Answer

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Answer: The thermal resistance of a medium represents its ability to resist the flow of heat through it. It is an essential parameter in understanding and analyzing heat transfer through materials and systems, primarily in construction, electronics, and heat exchange applications. A higher thermal resistance indicates that the medium offers more resistance to heat flow, whereas a lower thermal resistance implies that heat can flow through it more quickly.

Step by step solution

01

Definition of Thermal Resistance

The thermal resistance of a medium represents its ability to resist the flow of heat through it. It is a crucial factor in analyzing and understanding heat transfer through materials or systems. A higher thermal resistance indicates that the medium offers more resistance to heat flow, whereas a lower thermal resistance implies that heat can flow through it more quickly.
02

Importance of Thermal Resistance in Heat Transfer

Thermal resistance is essential in several practical applications involving heat transfer through materials and systems. Some of the primary areas where it plays a significant role include: 1. Construction and building design for temperature regulation and energy efficiency. 2. Thermal insulation in electronic devices to prevent overheating. 3. Design of heat exchangers and heat sinks for efficient heat dissipation.
03

Units and Calculation of Thermal Resistance

The unit of thermal resistance is kelvin per watt (K/W) or degree Celsius per watt (°C/W). It is calculated as: Thermal Resistance (R) = Temperature difference (∆T) / Heat transfer rate (Q) Mathematically, the thermal resistance of a homogeneous material can be calculated as follows: R = \frac{L}{kA} Where: R = Thermal Resistance (K/W or °C/W) L = Thickness or length of the medium through which heat is being transferred (m) k = Thermal conductivity of the medium (W/m·K) A = Cross-sectional area of the medium that is perpendicular to the direction of heat flow (m²)
04

Factors Influencing Thermal Resistance

Several factors can affect the thermal resistance of a medium, such as: 1. Material and its composition: Different materials have varying thermal conductivities, which directly influence their thermal resistance. 2. Thickness or length of the medium: A thicker or longer medium will offer more resistance to heat transfer compared to a thinner or shorter one. 3. Cross-sectional area: The larger the area, the lower the thermal resistance, as heat can flow through a more significant portion of the medium. In summary, the thermal resistance of a medium represents how effectively it can resist heat flow. It is an essential parameter in understanding and analyzing heat transfer through materials and systems, mainly in construction, electronics, and heat exchange applications.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is a fundamental concept in physics, which refers to the movement of thermal energy from one object or medium to another. This process occurs in order to equalize the temperature between the two bodies involved. Heat transfer can happen in several ways, with conduction, convection, and radiation being the most common methods.

In **conduction**, heat moves through a solid material. It's like when a spoon gets hot from being placed in a cup of hot coffee. The spoon conducts heat from the hot liquid to the cooler end of the spoon.
  • Convection involves the movement of heat through fluids, such as liquids or gases, usually with the aid of fluid movement. For instance, warm air rising and cool air sinking creates a convection current.
  • Radiation involves the transfer of heat through electromagnetic waves, like the warmth feeling from the sun.
Understanding how heat transfer works is crucial in many applications, from designing buildings to ensuring the safety of electronic components. Efficient heat transfer can help reduce energy costs and protect sensitive systems.
Thermal Conductivity
Thermal conductivity is a property of a material that indicates its ability to conduct heat. It's like measuring how fast or slow heat can travel through a material. High thermal conductivity materials allow heat to flow quickly, while low thermal conductivity materials slow down the heat flow.

Consider metals such as copper and aluminum; they are known for having high thermal conductivity. That's why they are often used in cookware and electronics, where quick heat dissipation is vital.
  • The formula to express thermal conductivity is:
    \[ k = rac{Q imes L}{A imes ∆T} \]
    Where:
    \( k \) is the thermal conductivity
    \( Q \) is the heat transfer rate
    \( L \) is the thickness or length of the medium
    \( A \) is the cross-sectional area
    \( ∆T \) is the temperature difference.
  • Materials like wool, fiberglass, and other insulators have low thermal conductivity, making them ideal for reducing heat loss in buildings.
Understanding thermal conductivity helps in choosing the right materials for a variety of applications, whether it's keeping a house warm or cooling down a smartphone.
Heat Exchangers
Heat exchangers are devices designed to efficiently transfer heat between two or more fluids without mixing them. They are essential in industries such as power generation, refrigeration, air conditioning, and automobile manufacturing.

Common types of heat exchangers include:
  • **Shell and Tube** - Consists of a series of tubes, one set carrying the hot fluid while a second set transfers the heat out.
  • **Plate** - Uses metal plates to transfer heat between two fluids. This design allows for a large surface area, making heat transfer more efficient.
  • **Air Cooled** - Instead of using a fluid, heat is transferred to the air.
The efficiency of a heat exchanger depends on factors like the type of fluids involved, flow rates, and the temperature difference between the fluids. They are designed to maximize the surface area of the walls between the fluids, which facilitates improved heat transfer.

By understanding the workings of heat exchangers, engineers can design systems that improve energy efficiency and save costs in industrial processes.

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Most popular questions from this chapter

Consider two walls, \(A\) and \(B\), with the same surface areas and the same temperature drops across their thicknesses. The ratio of thermal conductivities is \(k_{A} / k_{B}=4\) and the ratio of the wall thicknesses is \(L_{A} / L_{B}=2\). The ratio of heat transfer rates through the walls \(\dot{Q}_{A} / \dot{Q}_{B}\) is (a) \(0.5\) (b) 1 (c) \(2 \quad(d) 4\) (e) 8

A cylindrical pin fin of diameter \(0.6 \mathrm{~cm}\) and length of \(3 \mathrm{~cm}\) with negligible heat loss from the tip has an efficiency of 0.7. The effectiveness of this fin is (a) \(0.3\) (b) \(0.7\) (c) 2 (d) 8 (e) 14

A plane wall surface at \(200^{\circ} \mathrm{C}\) is to be cooled with aluminum pin fins of parabolic profile with blunt tips. Each fin has a length of \(25 \mathrm{~mm}\) and a base diameter of \(4 \mathrm{~mm}\). The fins are exposed to an ambient air condition of \(25^{\circ} \mathrm{C}\) and the heat transfer coefficient is \(45 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the thermal conductivity of the fins is \(230 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), determine the heat transfer rate from a single fin and the increase in the rate of heat transfer per \(\mathrm{m}^{2}\) surface area as a result of attaching fins. Assume there are 100 fins per \(\mathrm{m}^{2}\) surface area.

A 1-cm-diameter, 30-cm-long fin made of aluminum \((k=237 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is attached to a surface at \(80^{\circ} \mathrm{C}\). The surface is exposed to ambient air at \(22^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(11 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the fin can be assumed to bery long, its efficiency is (a) \(0.60\) (b) \(0.67\) (c) \(0.72\) (d) \(0.77\) (e) \(0.88\)

Steam in a heating system flows through tubes whose outer diameter is \(5 \mathrm{~cm}\) and whose walls are maintained at a temperature of \(180^{\circ} \mathrm{C}\). Circular aluminum alloy 2024-T6 fins \((k=186 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) of outer diameter \(6 \mathrm{~cm}\) and constant thickness \(1 \mathrm{~mm}\) are attached to the tube. The space between the fins is \(3 \mathrm{~mm}\), and thus there are 250 fins per meter length of the tube. Heat is transferred to the surrounding air at \(T_{\infty}=25^{\circ} \mathrm{C}\), with a heat transfer coefficient of \(40 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the increase in heat transfer from the tube per meter of its length as a result of adding fins.

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