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The heat transfer surface area of a fin is equal to the sum of all surfaces of the fin exposed to the surrounding medium, including the surface area of the fin tip. Under what conditions can we neglect heat transfer from the fin tip?

Short Answer

Expert verified
Answer: The heat transfer from the fin tip can be considered negligible under the following conditions: 1. If the heat transfer coefficient (h) is small, making convection from the fin tip insignificant. 2. If the surface area of the fin tip (A_tip) is very small compared to the overall surface area of the fin exposed to the surrounding medium. 3. If the temperature difference between the fin tip (T_tip) and the surrounding medium (T_infinity) is small, causing a minor contribution of the fin tip to the overall heat transfer.

Step by step solution

01

Understanding the heat transfer from a fin

A fin is a surface that extends from an object to increase the rate of heat transfer to or from the environment by increasing the surface area. The temperature of the object and the surrounding air may vary along the fin length, and this temperature difference causes heat to transfer by conduction along the fin and by convection from the fin's surfaces into the surrounding medium.
02

Calculating heat transfer from the fin tip

The heat transfer from the fin tip is a result of convection from the surface of the tip to the surrounding medium. This can be expressed mathematically using Newton's law of cooling, which states that the rate of heat transfer, Q, is proportional to the temperature difference between the surface and the surrounding medium and the surface area: Q_tip = h * A_tip * (T_tip - T_infinity), where h is the convection heat transfer coefficient, A_tip is the surface area of the fin tip, T_tip is the temperature of the fin tip, and T_infinity is the temperature of the surrounding medium.
03

Comparing heat transfer from the fin tip to the overall heat transfer

To know whether the heat transfer from the fin tip can be neglected, we need to compare it with the overall heat transfer from the entire fin. Generally, if the heat transfer from the fin tip is significantly smaller than the overall heat transfer from the fin, it can be neglected. To do this, we can use the following relationship: Q_total = Q_conductive + Q_convective, where Q_total is the total heat transfer, Q_conductive is the heat transfer through conduction along the fin, and Q_convective is the heat transfer due to convection from the fin's surfaces. If Q_tip << Q_total, then the heat transfer from the fin tip can be neglected.
04

Identifying the conditions for negligible heat transfer from the fin tip

There are several conditions where the heat transfer from the fin tip can be considered negligible: 1. If the heat transfer coefficient h is small, making convection from the fin tip insignificant. 2. If the surface area of the fin tip A_tip is very small compared to the overall surface area of the fin exposed to the surrounding medium. 3. If the temperature difference between the fin tip (T_tip) and the surrounding medium (T_infinity) is small, causing a minor contribution of the fin tip to the overall heat transfer. Under any of these conditions, the heat transfer from the fin tip can be neglected in the analysis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conduction and Convection
To fully understand how heat transfer works in objects like fins, we need to delve into the concepts of conduction and convection. Imagine a metal rod with one end heated up. The heat travels down the rod to the cooler end; this process is known as conduction. In conduction, heat is transferred through the material without the material itself moving. It occurs due to the energy exchange between adjacent atoms and molecules.

Now, picture that same rod in the air. The heat travels from the rod to the surrounding air. This movement of heat from the rod to the air is convection, which requires a fluid, such as air or water, to carry away the heat. Unlike conduction, convection involves the bulk movement of molecules within fluids (gases and liquids), taking heat away from the object.

In the context of a fin, conduction occurs along the length of the fin, transferring heat from the base where it's attached to an object (like an engine or a heat sink) to the tip. Once the heat reaches the surface of the fin, it's then transferred to the surrounding fluid through convection. The efficiency of a fin in transferring heat to the environment depends on this seamless interplay between conduction along the fin and convection away from its surfaces.
Newton's Law of Cooling
Newton's law of cooling describes the rate at which an object changes temperature through radiation or convection as a function of the difference in temperature between the object and its environment. This principle can be applied to understand the heat transfer from objects, like the tip of a fin, to their surroundings. The law states that the rate of heat loss of a body is directly proportional to the difference in temperatures between the body and its surroundings.

The mathematical representation of Newton's law of cooling is given by the equation: Q=h×A×(TobjectTsurroundings), where 'Q' is the rate of heat transfer, 'h' is the convection heat transfer coefficient, 'A' is the surface area, and TobjectTsurroundings is the temperature difference. This law provides us with a fundamental understanding of how the fin tip transfers heat to the air around it. For those trying to solve heat transfer problems, Newton's law of cooling is a crucial formula to analyze how quickly a fin or any other object will cool down.
Convection Heat Transfer Coefficient
The convection heat transfer coefficient, denoted as 'h', is a parameter that represents the convection heat transfer characteristics of a fluid in contact with a solid surface. It quantifies the efficiency with which the fluid (air, water, oil, etc.) can absorb heat from the solid surface.

The units of 'h' are typically in W/m2×K (watts per square meter per kelvin), and this coefficient varies depending on the fluid's properties, the velocity of the fluid over the surface, and the temperature difference between the surface and the fluid. It plays a pivotal role in calculations involving Newton's law of cooling.

The higher the value of 'h', the more efficient the fluid is at absorbing heat from the surface. That's why in certain situations, when the convection heat transfer coefficient is low, the heat transfer from the fin tip to the surrounding environment might be so minimal that it can be neglected in thermal analysis. This is one of the scenarios where a designer may decide not to consider the heat transfer from the fin tip, simplifying the thermal management problem.

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Most popular questions from this chapter

Steam at 320C flows in a stainless steel pipe (k= 15 W/mK ) whose inner and outer diameters are 5 cm and 5.5 cm, respectively. The pipe is covered with 3cm-thick glass wool insulation (k=0.038 W/mK). Heat is lost to the surroundings at 5C by natural convection and radiation, with a combined natural convection and radiation heat transfer coefficient of 15 W/m2K. Taking the heat transfer coefficient inside the pipe to be 80 W/m2K, determine the rate of heat loss from the steam per unit length of the pipe. Also determine the temperature drops across the pipe shell and the insulation.

Consider a 1.5-m-high and 2 -m-wide triple pane window. The thickness of each glass layer (k=0.80 W/mK) is 0.5 cm, and the thickness of each air space (k=0.025 W/mK) is 1 cm. If the inner and outer surface temperatures of the window are 10C and 0C, respectively, the rate of heat loss through the window is (a) 75 W (b) 12 W (c) 46 W (d) 25 W (e) 37 W

A plane wall surface at 200C is to be cooled with aluminum pin fins of parabolic profile with blunt tips. Each fin has a length of 25 mm and a base diameter of 4 mm. The fins are exposed to an ambient air condition of 25C and the heat transfer coefficient is 45 W/m2K. If the thermal conductivity of the fins is 230 W/mK, determine the heat transfer rate from a single fin and the increase in the rate of heat transfer per m2 surface area as a result of attaching fins. Assume there are 100 fins per m2 surface area.

One wall of a refrigerated warehouse is 10.0-m-high and 5.0-m-wide. The wall is made of three layers: 1.0-cm-thick aluminum (k=200 W/mK),8.0-cm-thick fibreglass (k= 0.038 W/mK), and 3.0cm thick gypsum board (k= 0.48 W/mK). The warehouse inside and outside temperatures are 10C and 20C, respectively, and the average value of both inside and outside heat transfer coefficients is 40 W/m2K. (a) Calculate the rate of heat transfer across the warehouse wall in steady operation. (b) Suppose that 400 metal bolts (k=43 W/mK), each 2.0 cm in diameter and 12.0 cm long, are used to fasten (i.e., hold together) the three wall layers. Calculate the rate of heat transfer for the "bolted" wall. (c) What is the percent change in the rate of heat transfer across the wall due to metal bolts?

A 1.4-m-diameter spherical steel tank filled with iced water at 0C is buried underground at a location where the thermal conductivity of the soil is k=0.55 W/mK. The distance between the tank center and the ground surface is 2.4 m. For ground surface temperature of 18C, determine the rate of heat transfer to the iced water in the tank. What would your answer be if the soil temperature were 18C and the ground surface were insulated?

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