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What is the difference between an ordinary differential equation and a partial differential equation?

Short Answer

Expert verified
Answer: The main difference between ODEs and PDEs is that ODEs involve ordinary derivatives with respect to one independent variable, while PDEs involve partial derivatives with respect to two or more independent variables.

Step by step solution

01

Define ordinary differential equation (ODE)

An ordinary differential equation is an equation that contains one or more unknown functions and their derivatives but only with respect to one independent variable. In other words, an ODE only involves ordinary derivatives. An example of an ODE is given by: dy/dx = x^2 + y^2 Here, y is the unknown function, x is the independent variable, and dy/dx is the first derivative of y with respect to x.
02

Define partial differential equation (PDE)

A partial differential equation is an equation involving one ormore unknown functions and their partial derivatives with respect to two or more independent variables. A PDE involves partial derivatives because there are multiple independent variables. An example of a PDE is given by: ∂u/∂x + ∂u/∂y = 0 Here, u is the unknown function, x and y are the independent variables, and ∂u/∂x and ∂u/∂y are the first partial derivatives of u with respect to x and y, respectively.
03

Highlight the differences

The main differences between an ordinary differential equation and a partial differential equation are: 1. ODEs involve ordinary derivatives, while PDEs involve partial derivatives. 2. ODEs have one independent variable, while PDEs have two or more independent variables. 3. The unknown functions in ODEs depend on one variable (e.g., y(x)), while the unknown functions in PDEs depend on multiple variables (e.g., u(x, y)).
04

Wrap up

In summary, ordinary differential equations and partial differential equations are both equations relating unknown functions and their derivatives, but they differ in the type of derivatives involved (ordinary vs. partial) and the number of independent variables. ODEs have one independent variable and involve ordinary derivatives, while PDEs have multiple independent variables and involve partial derivatives.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ordinary Differential Equation (ODE)
An Ordinary Differential Equation (ODE) is a fundamental concept in mathematics that deals with functions and the change in these functions with respect to one independent variable. It is defined by the relationship between an unknown function and its derivatives. For instance, consider the ODE given by \(\frac{dy}{dx} = x^2 + y^2\). Here, \(y\) represents the unknown function we're trying to find, and \(x\) is the independent variable that \(y\) depends on. The expression \(\frac{dy}{dx}\) signifies the rate of change of \(y\) with respect to \(x\), which is also known as the first derivative of \(y\). ODEs are essential in various fields such as physics, engineering, and biology for modeling the behavior of systems that change over time or space.

When solving an ODE, the goal is to find an explicit function or set of functions that satisfy the equation. This could mean finding a general solution that includes arbitrary constants or a particular solution that satisfies initial or boundary conditions. The solutions to ODEs can take many forms, including polynomial, exponential, or trigonometric functions, and these solutions provide insights into the nature of the phenomena being studied.
Partial Differential Equation (PDE)
A Partial Differential Equation (PDE) is much like an Ordinary Differential Equation, but with a notable difference - it involves multiple independent variables and their partial derivatives. PDEs are represented by equations such as \(\frac{\partial u}{\partial x} + \frac{\partial u}{\partial y} = 0\), where \(u\) is the unknown function dependent on at least two independent variables, in this case, \(x\) and \(y\). The partial derivatives \(\frac{\partial u}{\partial x}\) and \(\frac{\partial u}{\partial y}\) indicate the rate of change of \(u\) with respect to each independent variable individually.

PDEs are crucial for describing various phenomena such as heat distribution, sound waves, and fluid dynamics, where the state of the system depends on multiple variables. Solving a PDE often involves finding a function that can take on different shapes and represents a broad spectrum of possible solutions, heavily influenced by the boundary and initial conditions of the problem. Due to the complexity of PDEs, solutions are sometimes only possible through numerical methods and computer simulations.
Derivatives in Mathematics
Derivatives in mathematics are a measure of how a function changes as its input changes. In other words, a derivative represents an instantaneous rate of change, akin to the way speed represents the instantaneous rate of change of distance over time. A simple derivative is denoted as \(\frac{dy}{dx}\), which measures the rate at which \(y\) changes with respect to \(x\). Partial derivatives, on the other hand, such as \(\frac{\partial u}{\partial x}\), measure the rate of change of a function with multiple variables, like \(u\), with respect to a single variable, \(x\), keeping other variables constant.

Understanding derivatives is vital for studying and modeling systems that change. It allows mathematicians, economists, scientists, and engineers to predict and understand behavior in a wide range of contexts, from the growth rate of investments to the motion of celestial bodies. Mastery of derivatives is not only foundational for calculus and higher mathematics but is also a critical tool for applied sciences.
Independent Variables
In the context of differential equations, independent variables are the inputs of the functions we are studying; they can change freely without being affected by other variables in the equation. For an ODE such as \(\frac{dy}{dx} = x^2 + y^2\), \(x\) is the independent variable, whereas in a PDE like \(\frac{\partial u}{\partial x} + \frac{\partial u}{\partial y} = 0\), both \(x\) and \(y\) are considered independent variables. The distinction is critical, as the number and nature of independent variables can significantly influence the complexity of the relationship being modeled by the differential equation.

Independent variables form the basis for the exploration and description of dependent variables, which are the outcomes that depend on the values of these independent variables. In any study or mathematical model, defining and understanding the independent variables is a crucial step in the analysis. It sets the stage for how we approach the problem, what methods we use to solve it, and how we interpret the solutions we receive.

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Most popular questions from this chapter

Consider a spherical reactor of \(5-\mathrm{cm}\) diameter operating at steady condition has a temperature variation that can be expressed in the form of \(T(r)=a-b r^{2}\), where \(a=850^{\circ} \mathrm{C}\) and \(b=5 \times 10^{5} \mathrm{~K} / \mathrm{m}^{2}\). The reactor is made of material with \(c=\) \(200 \mathrm{~J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}, k=40 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \rho=9000 \mathrm{~kg} / \mathrm{m}^{3}\). If the heat generation of reactor is suddenly set to \(9 \mathrm{MW} / \mathrm{m}^{3}\), determine the time rate of temperature change in the reactor. Is the heat generation of reactor suddenly increased or decreased to \(9 \mathrm{MW} / \mathrm{m}^{3}\) from its steady operating condition?

What kind of differential equations can be solved by direct integration?

A pipe is used for transporting boiling water in which the inner surface is at \(100^{\circ} \mathrm{C}\). The pipe is situated in a surrounding where the ambient temperature is \(20^{\circ} \mathrm{C}\) and the convection heat transfer coefficient is \(50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The pipe has a wall thickness of \(3 \mathrm{~mm}\) and an inner diameter of \(25 \mathrm{~mm}\), and it has a variable thermal conductivity given as \(k(T)=k_{0}(1+\beta T)\), where \(k_{0}=1.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \beta=0.003 \mathrm{~K}^{-1}\) and \(T\) is in \(\mathrm{K}\). Determine the outer surface temperature of the pipe.

A solar heat flux \(\dot{q}_{s}\) is incident on a sidewalk whose thermal conductivity is \(k\), solar absorptivity is \(\alpha_{s}\), and convective heat transfer coefficient is \(h\). Taking the positive \(x\) direction to be towards the sky and disregarding radiation exchange with the surroundings surfaces, the correct boundary condition for this sidewalk surface is (a) \(-k \frac{d T}{d x}=\alpha_{s} \dot{q}_{s}\) (b) \(-k \frac{d T}{d x}=h\left(T-T_{\infty}\right)\) (c) \(-k \frac{d T}{d x}=h\left(T-T_{\infty}\right)-\alpha_{s} \dot{q}_{s}\) (d) \(h\left(T-T_{\infty}\right)=\alpha_{s} \dot{q}_{s}\) (e) None of them

Heat is generated in a long \(0.3-\mathrm{cm}\)-diameter cylindrical electric heater at a rate of \(180 \mathrm{~W} / \mathrm{cm}^{3}\). The heat flux at the surface of the heater in steady operation is (a) \(12.7 \mathrm{~W} / \mathrm{cm}^{2}\) (b) \(13.5 \mathrm{~W} / \mathrm{cm}^{2}\) (c) \(64.7 \mathrm{~W} / \mathrm{cm}^{2}\) (d) \(180 \mathrm{~W} / \mathrm{cm}^{2}\) (e) \(191 \mathrm{~W} / \mathrm{cm}^{2}\)

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