Chapter 2: Problem 105
When the thermal conductivity of a medium varies linearly with temperature, is the average thermal conductivity always equivalent to the conductivity value at the average temperature?
Short Answer
Expert verified
Answer: No, the average thermal conductivity is not always equivalent to the conductivity value at the average temperature when the thermal conductivity of a medium varies linearly with temperature. The equivalence depends on the values of T1, T2, and the slope (m).
Step by step solution
01
Write the linear relationship between thermal conductivity and temperature
Let's assume the thermal conductivity (k) varies linearly with temperature (T). The linear equation for this relationship can be given as:
k(T) = k_0 + m * T
where k_0 is the initial thermal conductivity at T=0, m is the slope of the line, and T is the temperature.
02
Find the average thermal conductivity
Let's consider an arbitrary temperature range [T1, T2]. To find the average thermal conductivity, we integrate the function k(T) over the range and divide by the width of the range:
\[\langle k \rangle = \frac{1}{T2-T1}\int_{T1}^{T2} (k_0 + mT)dT\]
Now, perform the integration:
\[\langle k \rangle = \frac{1}{T2-T1}[(k_0 T + m\frac{T^2}{2})\Big|_{T=T1}^{T=T2}] = \frac{1}{T2-T1}[(k_0 (T2-T1) + m\frac{T2^2-T1^2}{2})]\]
03
Find the value of thermal conductivity at the average temperature
To find the value of thermal conductivity at the average temperature, we first must find the average temperature:
\[\langle T \rangle = \frac{T1+T2}{2}\]
Now, plug the average temperature into the linear equation for k(T):
k(\langle T\rangle) = k_0 + m * \langle T\rangle
04
Compare the two values
We now have expressions for the average thermal conductivity (\langle k \rangle) and thermal conductivity at the average temperature (k(\langle T\rangle)). Let's compare them to see if they are equal:
\[\langle k \rangle = \frac{1}{T2-T1}[(k_0 (T2-T1) + m\frac{T2^2-T1^2}{2})]\]
\[k(\langle T\rangle) = k_0 + m * \langle T\rangle = k_0 + m * \frac{T1+T2}{2}\]
Comparing both the expressions, we can see that they are not always equivalent. The equivalence of both the expressions depends on the values of T1, T2 and the slope (m).
In conclusion, when the thermal conductivity of a medium varies linearly with temperature, the average thermal conductivity is not always equivalent to the conductivity value at the average temperature.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Temperature-Conductivity Relationship
Understanding the linear temperature-conductivity relationship is crucial when it comes to materials that change their ability to conduct heat as their temperature changes. Essentially, this relationship indicates that the thermal conductivity, often denoted as \( k(T) \), increases or decreases directly in proportion to the temperature. The mathematical expression for this linear relationship is given by:
\[ k(T) = k_0 + m \times T \]
where \( k_0 \) represents the thermal conductivity at a baseline temperature of zero, \( m \) is the constant rate of change of conductivity with temperature, and \( T \) is the actual temperature. In practical terms, this means that if you know the rate at which a material's conductivity changes with temperature, you can predict its conductivity at any temperature within the range where the linear relationship holds true.
When dealing with engineering problems or scientific experiments, assuming a linear relationship simplifies calculations and models. However, it is essential to remember that not all materials exhibit a perfectly linear relationship between thermal conductivity and temperature across all temperatures. This linearity often is a good approximation within a certain range relevant to the application at hand.
\[ k(T) = k_0 + m \times T \]
where \( k_0 \) represents the thermal conductivity at a baseline temperature of zero, \( m \) is the constant rate of change of conductivity with temperature, and \( T \) is the actual temperature. In practical terms, this means that if you know the rate at which a material's conductivity changes with temperature, you can predict its conductivity at any temperature within the range where the linear relationship holds true.
When dealing with engineering problems or scientific experiments, assuming a linear relationship simplifies calculations and models. However, it is essential to remember that not all materials exhibit a perfectly linear relationship between thermal conductivity and temperature across all temperatures. This linearity often is a good approximation within a certain range relevant to the application at hand.
Average Thermal Conductivity
The concept of average thermal conductivity comes into play when there's a need to estimate a single value of conductivity for a material over a range of temperatures. This is particularly useful in heat transfer calculations where exact values at every point are cumbersome to work with. Average thermal conductivity, represented by \( \langle k \rangle \), is determined by integrating the thermal conductivity over the desired temperature range and then dividing by that range.
The equation to calculate the average thermal conductivity between two temperatures \( T1 \) and \( T2 \) is:
\[ \langle k \rangle = \frac{1}{T2 - T1} \int_{T1}^{T2} (k_0 + mT) dT \]
After performing the integration, you will have a single value representing the thermal conductivity 'averaged out' across that range. This value is not the same as the thermal conductivity at the midpoint temperature, which is a common misconception. Instead, it accounts for how the conductivity varies across the entire interval, providing a more holistic and applicable value for engineering analyses and designs.
The equation to calculate the average thermal conductivity between two temperatures \( T1 \) and \( T2 \) is:
\[ \langle k \rangle = \frac{1}{T2 - T1} \int_{T1}^{T2} (k_0 + mT) dT \]
After performing the integration, you will have a single value representing the thermal conductivity 'averaged out' across that range. This value is not the same as the thermal conductivity at the midpoint temperature, which is a common misconception. Instead, it accounts for how the conductivity varies across the entire interval, providing a more holistic and applicable value for engineering analyses and designs.
Integration in Heat Transfer
Integration is a powerful mathematical tool often used in heat transfer to deal with variables that change over a domain, such as time, space, or temperature. When calculating average thermal conductivity, integration allows us to consider the continuous variation of material properties across a temperature range. By integrating the function that describes the thermal conductivity over the desired temperature interval, we can obtain a representative value for the entire range.
The process involves calculating the area under the curve of the conductivity-temperature graph between two specified temperatures. This integral can often be visualized as the physical area under the line representing the linear temperature-conductivity relationship on a graph.
Applying integration in heat transfer problems simplifies the complex reality into workable solutions, making it a staple in thermal analysis. Proper use of integration harmonizes the varying conductivity into an effective average value that can be used predictively in designs and applications where temperature gradients are present.
The process involves calculating the area under the curve of the conductivity-temperature graph between two specified temperatures. This integral can often be visualized as the physical area under the line representing the linear temperature-conductivity relationship on a graph.
Applying integration in heat transfer problems simplifies the complex reality into workable solutions, making it a staple in thermal analysis. Proper use of integration harmonizes the varying conductivity into an effective average value that can be used predictively in designs and applications where temperature gradients are present.