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Consider one-dimensional mass transfer in a moving medium that consists of species A and B with ρ=ρA+ρB= constant. Mark these statements as being True or False. (a) The rates of mass diffusion of species A and B are equal in magnitude and opposite in direction. (b) DAB=DBA. (c) During equimolar counterdiffusion through a tube, equal numbers of moles of A and B move in opposite directions, and thus a velocity measurement device placed in the tube will read zero. (d) The lid of a tank containing propane gas (which is heavier than air) is left open. If the surrounding air and the propane in the tank are at the same temperature and pressure, no propane will escape the tank and no air will enter.

Short Answer

Expert verified
Identify whether each statement is True or False and provide an explanation: (a) The rates of mass diffusion of species A and B are equal in magnitude and opposite in direction. Answer: True Explanation: Since the system has a constant density, any mass that diffuses from species A would mean a corresponding mass loss in species B, and vice versa. Hence, their rates of mass diffusion have the same magnitude but opposite directions. (b) DAB=DBA. Answer: True Explanation: The diffusivity coefficients (DAB and DBA) are a measure of how fast species A diffuses into species B and vice versa. As per Fick's law of diffusion, these coefficients are equal under identical conditions. (c) During equimolar counterdiffusion through a tube, equal numbers of moles of A and B move in opposite directions, and thus a velocity measurement device placed in the tube will read zero. Answer: True Explanation: In the case of equimolar counterdiffusion, the number of moles moving in each direction is equal, leading to zero net mass velocity. Therefore, any velocity measurement device placed in the tube would read zero. (d) The lid of a tank containing propane gas (which is heavier than air) is left open. If the surrounding air and the propane in the tank are at the same temperature and pressure, no propane will escape the tank and no air will enter. Answer: False Explanation: Propane, being heavier than air, will tend to diffuse downwards due to gravity. At the same time, air will be able to enter the tank from the open lid. Thus, there will be a gas exchange between propane and air, regardless of the same temperature and pressure conditions.

Step by step solution

01

Statement (a)

The rates of mass diffusion of species A and B are equal in magnitude and opposite in direction. This statement is True. Since the system has a constant density, any mass that diffuses from species A would mean a corresponding mass loss in species B, and vice versa. Hence, their rates of mass diffusion have the same magnitude but opposite directions.
02

Statement (b)

The statement DAB=DBA is True. The diffusivity coefficients (DAB and DBA) are a measure of how fast species A diffuses into species B and vice versa. As per Fick's law of diffusion, these coefficients are equal under identical conditions.
03

Statement (c)

During equimolar counterdiffusion through a tube, equal numbers of moles of A and B move in opposite directions, and thus a velocity measurement device placed in the tube will read zero. This statement is True. In the case of equimolar counterdiffusion, the number of moles moving in each direction is equal, leading to zero net mass velocity. Therefore, any velocity measurement device placed in the tube would read zero.
04

Statement (d)

The lid of a tank containing propane gas (which is heavier than air) is left open. If the surrounding air and the propane in the tank are at the same temperature and pressure, no propane will escape the tank and no air will enter. This statement is False. Propane, being heavier than air, will tend to diffuse downwards due to gravity. At the same time, air will be able to enter the tank from the open lid. Thus, there will be a gas exchange between propane and air, regardless of the same temperature and pressure conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Diffusion
Mass diffusion is a fundamental phenomenon where particles, such as atoms, ions, or molecules, spread from regions of higher concentration to regions of lower concentration. This natural process is driven by the concentration gradient, propelling species towards a uniform distribution. Imagine pouring a drop of food coloring into a glass of water. Initially, the color is most intense where the drop enters the water, but over time, the color spreads throughout the glass until it's even, which is an everyday example of mass diffusion.

Understanding mass diffusion is crucial in various disciplines, including environmental sciences, engineering, and material science, as it helps us predict how pollutants spread in the environment, how different substances interact in industrial processes, and how to design better batteries and fuel cells, where diffusion plays a key role in the effectiveness of these devices.
Fick's Law of Diffusion
where J is the diffusion flux (amount of substance per unit area per unit time), D is the diffusivity or diffusion coefficient, and dρdx is the concentration gradient. The direction of mass transfer is from higher to lower concentration, which is why there is a negative sign. This law is crucial for engineers and scientists to calculate the rate of diffusion under various conditions and to design systems where controlled diffusion is necessary, such as in drug delivery systems.

An understanding of Fick's law also implies that factors such as the medium's temperature and porosity can significantly affect diffusion rates. For instance, increasing the temperature typically increases the rate of diffusion, as particles move more quickly and spread out faster.
Equimolar Counterdiffusion
Equimolar counterdiffusion occurs when two species diffuse through a stationary medium at equal rates but in opposite directions, without any overall change in molar concentration. This is a special case of diffusion that often occurs in gas mixtures when no bulk flow is present, for example, in a closed container where two different gases are allowed to mix.

A classic example to visualize equimolar counterdiffusion is a tube with hydrogen on one end and nitrogen on the other. If allowed to diffuse, the lighter hydrogen will move faster; however, due to the stoichiometry of the counterdiffusion, an equal number of nitrogen atoms will diffuse towards the hydrogen. There's no net movement of mass or change in pressure because the molar flow of each gas is balanced. Devices measuring flow or velocity in the tube during this process would indicate no movement, corroborating the 'zero net mass velocity' characteristic of equimolar counterdiffusion.
Diffusivity Coefficients
Diffusivity coefficients, often represented with the symbol D, are values that quantify the ease with which different species can diffuse through a particular medium. These coefficients are determined experimentally or estimated using predictive models and are fundamental parameters in Fick's law. Factors such as temperature, pressure, and the nature of the medium affect these coefficients.

For instance, in a binary system consisting of species A and B, the diffusivity DAB measures how quickly A diffuses into B, and vice versa for DBA. Under the same conditions, DAB and DBA are equal due to the reciprocal nature of diffusion forces and collision frequencies. Understanding and calculating the correct diffusivity coefficients is crucial for engineers and scientists when predicting how a substance will behave under specific conditions, such as in air purification processes, industrial mixing, or environmental modeling of contaminant spread.

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Most popular questions from this chapter

A researcher is using a 5 -cm-diameter Stefan tube to measure the mass diffusivity of chloroform in air at 25C and 1 atm. Initially, the liquid chloroform surface was 7.00 cm from the top of the tube; and after 10 hours have elapsed, the liquid chloroform surface was 7.44 cm from the top of the tube, which corresponds to 222 g of chloroform being diffused. At 25C, the chloroform vapor pressure is 0.263 atm, and the concentration of chloroform is zero at the top of the tube. If the molar mass of chloroform is 119.39 kg/kmol, determine the mass diffusivity of chloroform in air.

Hydrogen gas at 750kPa and 85C is stored in a spherical nickel vessel. The vessel is situated in a surrounding of atmospheric air at 1 atm. Determine the molar and mass concentrations of hydrogen in the nickel at the inner and outer surfaces of the vessel.

Determine the mole fraction of the water vapor at the surface of a lake whose temperature is 15C and compare it to the mole fraction of water in the lake. Take the atmospheric pressure at lake level to be 92kPa.

When handling corrosive and toxic substances, chemical resistant gloves should be worn. When selecting gloves to handle a substance, the suitability of the gloves should be considered. Depending on the material of the gloves, they could be easily permeable by some substances. An employee is handling tetrachloroethylene solution for a metal-cleaning process. Dermal exposure to tetrachloroethylene can cause skin irritation, and long-term exposure to it can have adverse neurological effects on humans. As a protective measure, the employee wears rubber-blend gloves while handling the tetrachloroethylene solution. The average thickness of the gloves is 0.67 mm, and the mass diffusivity of tetrachloroethylene in the gloves is 3×108 m2/s. Estimate how long can the employee's hand be in contact with the tetrachloroethylene solution before the concentration of the solution at the inner glove surface reaches 1% of the concentration at the outer surface. Is this type of glove suitable for handling tetrachloroethylene solution?

Saturated water vapor at 25C(Psat =3.17kPa) flows in a pipe that passes through air at 25C with a relative humidity of 40 percent. The vapor is vented to the atmosphere through a 7mm internal-diameter tube that extends 10 m into the air. The diffusion coefficient of vapor through air is 2.5×105 m2/s. The amount of water vapor lost to the atmosphere through this individual tube by diffusion is (a) 1.02×106 kg (b) 1.37×106 kg (c) 2.28×106 kg (d) 4.13×106 kg (e) 6.07×106 kg

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