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The basic equation describing the diffusion of one medium through another stationary medium is (a) \(j_{A}=-C D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\) (b) \(j_{A}=-D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\) (c) \(j_{A}=-k \frac{d\left(C_{A} / C\right)}{d x}\) (d) \(j_{A}=-k \frac{d T}{d x}\) (e) none of them

Short Answer

Expert verified
a) \(j_{A} = -C D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\) b) \(j_{A} = -D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\) c) \(j_{A} = -k \frac{d\left(C_{A} / C\right)}{d x}\) d) \(j_{A} = -k \frac{d T}{d x}\) e) None of them Answer: a) \(j_{A} = -C D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\)

Step by step solution

01

Option (a)

\(j_{A} = -C D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\) In this equation, \(j_{A}\), the flux, is directly proportional to the negative gradient of the molar ratio. It takes into consideration the gradient with respect to the position '\(x\)' and a proportionality constant, \(D_{A B}\). This option seems to represent Fick's first law appropriately.
02

Option (b)

\(j_{A} = -D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\) This expression is similar to option (a) but without the term 'C', which represents a concentration. Fick's law states that the flux depends on the total concentration, so this option is incorrect.
03

Option (c)

\(j_{A} = -k \frac{d\left(C_{A} / C\right)}{d x}\) This option has the same format as option (b) but uses the proportionality constant 'k' instead of the diffusion coefficient \(D_{A B}\). Since Fick's law specifically mentions the diffusion coefficient, this option is incorrect.
04

Option (d)

\(j_{A} = -k \frac{d T}{d x}\) In this option, the gradient is of temperature with respect to position '\(x\)', rather than concentration or molar ratio. This does not represent Fick's first law of diffusion, which is based on concentration gradients.
05

Option (e)

None of them Since we have already analyzed each option, and option (a) seems to represent Fick's first law correctly, there is no need to consider this option. In conclusion, the correct equation describing the diffusion of one medium through another stationary medium is given by:
06

Answer

Option (a) \(j_{A} = -C D_{A B} \frac{d\left(C_{A} / C\right)}{d x}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffusion Coefficient
The diffusion coefficient, denoted as \(D_{AB}\), plays a crucial role in Fick's First Law of diffusion. It is indicative of how easily particles, like molecules or atoms, can spread through another medium. The higher the diffusion coefficient, the faster the diffusion process occurs. This parameter is specific to the types of substances involved; for instance, gases tend to have higher diffusion coefficients compared to liquids. Understanding this helps predict how substances will behave in various environments.

Several factors influence the diffusion coefficient:
  • Temperature: Typically, as temperature increases, so does the diffusion coefficient, because particles move more vigorously at higher temperatures.
  • Medium Viscosity: A more viscous medium slows down the diffusion, resulting in a lower diffusion coefficient.
  • Particle Size: Smaller particles tend to diffuse more quickly, influencing the diffusion coefficient.
By considering these factors, scientists and engineers can control and optimize the diffusion processes in various applications.
Concentration Gradient
The concentration gradient represents the difference in concentration of a substance between two regions. Fick's First Law of diffusion tells us that diffusion occurs down the concentration gradient—from regions of higher concentration to regions of lower concentration. This movement continues until equilibrium is reached.

Understanding the concept of a concentration gradient allows us to predict and explain how substances move in different contexts. For a solid grasp of its significance:
  • Imagine a sugar cube dissolving in water. Initially, the sugar concentration near the cube is higher than the surrounding water, forming a concentration gradient.
  • Diffusion will naturally occur as sugar molecules move from the area of higher concentration (around the cube) to the area of lower concentration (the rest of the water).
Concentration gradients are essential in fields ranging from biology, where they influence processes like oxygen diffusion in tissues, to chemical engineering, where they help in designing effective separation processes.
Flux
In the context of Fick's First Law, "flux" refers to the rate at which particles move through a unit area per unit of time. It is denoted by \(j_{A}\) and embodies the concept of movement through a medium due to a concentration gradient. The flux is directly proportional to the concentration gradient, highlighting that a steeper gradient results in a higher rate of diffusion.

The formula for flux, based on Fick's First Law, is given by:\[j_{A} = -C D_{AB} \frac{d\left(C_{A} / C\right)}{d x}\]Here, the negative sign indicates that the movement occurs from higher to lower concentration. Understanding flux and its dependence on factors such as the diffusion coefficient and concentration gradient helps in quantifying how rapidly substances will diffuse.

To visualize this:
  • Think of heat transfer as an analogy, where heat flows from a hotter area (higher energy concentration) to a cooler area.
  • The flux of particles in diffusion works similarly, moving from areas of abundance to areas of scarcity until equilibrium is reached.
In summary, flux is a critical concept in evaluating and predicting diffusion behavior.

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Most popular questions from this chapter

Consider a nickel wall separating hydrogen gas that is maintained on one side at \(5 \mathrm{~atm}\) and on the opposite at \(3 \mathrm{~atm}\). If the temperature is constant at \(85^{\circ} \mathrm{C}\), determine \((a)\) the mass densities of hydrogen gas in the nickel wall on both sides and \((b)\) the mass densities of hydrogen outside the nickel wall on both sides.

Dry air whose molar analysis is \(78.1\) percent \(\mathrm{N}_{2}\), \(20.9\) percent \(\mathrm{O}_{2}\), and 1 percent Ar flows over a water body until it is saturated. If the pressure and temperature of air remain constant at \(1 \mathrm{~atm}\) and \(25^{\circ} \mathrm{C}\) during the process, determine (a) the molar analysis of the saturated air and \((b)\) the density of air before and after the process. What do you conclude from your results?

Benzene \((M=78.11 \mathrm{~kg} / \mathrm{kmol})\) is a carcinogen, and exposure to benzene increases the risk of cancer and other illnesses in humans. A truck transporting liquid benzene was involved in an accident that spilled the liquid on a flat highway. The liquid benzene forms a pool of approximately \(10 \mathrm{~m}\) in diameter on the highway. In this particular windy day at \(25^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) with an average wind velocity of \(10 \mathrm{~m} / \mathrm{s}\), the liquid benzene surface is experiencing mass transfer to air by convection. Nearby at the downstream of the wind is a residential area that could be affected by the benzene vapor. Local health officials have assessed that if the benzene level in the air reaches \(500 \mathrm{~kg}\) within the hour of the spillage, residents should be evacuated from the area. If the benzene vapor pressure is \(10 \mathrm{kPa}\), estimate the mass transfer rate of benzene being convected to the air, and determine whether the residents should be evacuated or not.

A glass bottle washing facility uses a well agi(Es) tated hot water bath at \(50^{\circ} \mathrm{C}\) with an open top that is placed on the ground. The bathtub is \(1 \mathrm{~m}\) high, \(2 \mathrm{~m}\) wide, and \(4 \mathrm{~m}\) long and is made of sheet metal so that the outer side surfaces are also at about \(50^{\circ} \mathrm{C}\). The bottles enter at a rate of 800 per minute at ambient temperature and leave at the water temperature. Each bottle has a mass of \(150 \mathrm{~g}\) and removes \(0.6 \mathrm{~g}\) of water as it leaves the bath wet. Makeup water is supplied at \(15^{\circ} \mathrm{C}\). If the average conditions in the plant are \(1 \mathrm{~atm}, 25^{\circ} \mathrm{C}\), and 50 percent relative humidity, and the average temperature of the surrounding surfaces is \(15^{\circ} \mathrm{C}\), determine (a) the amount of heat and water removed by the bottles themselves per second, \((b)\) the rate of heat loss from the top surface of the water bath by radiation, natural convection, and evaporation, \((c)\) the rate of heat loss from the side surfaces by natural convection and radiation, and \((d)\) the rate at which heat and water must be supplied to maintain steady operating conditions. Disregard heat loss through the bottom surface of the bath and take the emissivities of sheet metal and water to be \(0.61\) and \(0.95\), respectively.

In an experiment, a sphere of crystalline sodium chloride \((\mathrm{NaCl})\) was suspended in a stirred tank filled with water at \(20^{\circ} \mathrm{C}\). Its initial mass was \(100 \mathrm{~g}\). In 10 minutes, the mass of sphere was found to have decreased by 10 percent. The density of \(\mathrm{NaCl}\) is \(2160 \mathrm{~kg} / \mathrm{m}^{3}\). Its solubility in water at \(20^{\circ} \mathrm{C}\) is \(320 \mathrm{~kg} / \mathrm{m}^{3}\). Use these results to obatin an average value for the mass transfer coefficient.

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