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At a given temperature and pressure, do you think the mass diffusivity of copper in aluminum will be equal to the mass diffusivity of aluminum in copper? Explain.

Short Answer

Expert verified
Answer: No, the mass diffusivities of copper in aluminum and aluminum in copper are not equal under the same temperature and pressure conditions due to the differences in atomic radii and lattice structures. The mass diffusivity of copper in aluminum will most likely be lower than the mass diffusivity of aluminum in copper.

Step by step solution

01

Understanding Mass Diffusivity

Mass diffusivity, also known as diffusion coefficient, is a measure of how easily one substance can diffuse into another. It depends on factors like temperature, pressure, and the nature of the substances involved.
02

Comparing Diffusivities

In this case, we are looking at the diffusivities of copper in aluminum and aluminum in copper. These two processes involve the same two elements, so their diffusivities will depend on the arrangements of the elements and the specific conditions of temperature and pressure.
03

Considering Interdiffusion

In a system where two elements can freely diffuse into each other, the diffusion process is called interdiffusion. The mass diffusivity in this case depends on the structure of the metal lattice and the relative sizes of the atoms.
04

Factors Affecting Diffusivities

Both copper and aluminum have a face-centered cubic lattice structure, which makes it easier for the atoms to diffuse into each other. However, the atomic radius of copper (128 pm) is slightly larger than that of aluminum (125 pm), which means that the copper atoms will have to squeeze into smaller spaces in the aluminum lattice during diffusion. Similarly, aluminum atoms will have more room in the copper lattice during diffusion.
05

Conclusion

Based on the differences in atomic radii and lattice structures, we can conclude that the mass diffusivities of copper in aluminum and aluminum in copper are not equal, even under the same temperature and pressure conditions. The mass diffusivity of copper in aluminum will most likely be lower than the mass diffusivity of aluminum in copper due to the size difference between the copper and aluminum atoms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffusion Coefficient
The diffusion coefficient, also known as mass diffusivity, is crucial in understanding how substances intermingled. It represents how fast particles, atoms, or molecules spread out from an area of high concentration to one of low concentration due to random motion. The diffusion coefficient varies significantly with changes in temperature and pressure. For example:
  • At higher temperatures, particles have more kinetic energy, which often increases the diffusion coefficient.
  • Under high pressure, the diffusion rate can slow as particles are packed closely together, hindering their movement.
This coefficient becomes an essential parameter when considering processes like interdiffusion between different metals, such as copper and aluminum.
Interdiffusion
Interdiffusion is the process where atoms of two different metals diffuse into each other, creating a blend at their boundary. This process is vital in metallurgy, where creating alloys with specific properties requires precise knowledge of how these metals will interact. The ease of interdiffusion and the resulting material properties depend on several factors:
  • The atomic size and structure of the metals involved.
  • The lattice types of the metals, which affect how freely the atoms can move.
  • Temperature and pressure conditions.
In cases where metals like copper and aluminum interdiffuse, alloy formation is possible that combines desirable traits from both metals, such as increased strength and conductivity.
Atomic Radius
The atomic radius is the measure of the size of an atom, usually from the center of the nucleus to the boundary of the surrounding electron cloud. It plays a pivotal role in diffusion processes and material interactions. Differences in atomic radii can significantly affect how materials merge. For example:
  • Copper has an atomic radius of 128 pm, slightly larger than aluminum's 125 pm.
  • This slight difference implies that aluminum atoms may occupy less space, facilitating their movement through a copper lattice more easily.
  • Conversely, copper's larger atoms may experience difficulty fitting into the tighter spaces of aluminum's structure, reducing their diffusion rate in aluminum.
Therefore, understanding atomic radii helps predict and explain unequal diffusion rates in different metal combinations.
Lattice Structure
A material's lattice structure is the arrangement of atoms in its crystal form, significantly influencing properties like diffusion. Both aluminum and copper share a face-centered cubic (FCC) lattice structure, allowing relatively easy diffusion compared to other lattice forms. Here are some key points about FCC structures:
  • In an FCC lattice, atoms are located at each corner and the centers of all the cube's faces.
  • This arrangement facilitates higher atomic packing, providing paths through which atoms can move or "hop" more easily.
  • However, even in FCC structures, the size of the diffusing atoms plays a role. The difference in atomic radii between aluminum and copper affects their respective ease of diffusion in each other's lattices.
The lattice structure reinforces the impact that atomic size has on diffusion, providing another layer of complexity in material science.

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Most popular questions from this chapter

Consider a shallow body of water. Is it possible for this water to freeze during a cold and dry night even when the ambient air and surrounding surface temperatures never drop to \(0^{\circ} \mathrm{C}\) ? Explain.

Under what conditions will the normalized velocity, thermal, and concentration boundary layers coincide during flow over a flat plate?

For the absorption of a gas (like carbon dioxide) into a liquid (like water) Henry's law states that partial pressure of the gas is proportional to the mole fraction of the gas in the liquid-gas solution with the constant of proportionality being Henry's constant. A bottle of soda pop \(\left(\mathrm{CO}_{2}-\mathrm{H}_{2} \mathrm{O}\right)\) at room temperature has a Henry's constant of \(17,100 \mathrm{kPa}\). If the pressure in this bottle is \(120 \mathrm{kPa}\) and the partial pressure of the water vapor in the gas volume at the top of the bottle is neglected, the concentration of the \(\mathrm{CO}_{2}\) in the liquid \(\mathrm{H}_{2} \mathrm{O}\) is (a) \(0.003 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (b) \(0.007 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (c) \(0.013 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (d) \(0.022 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\) (e) \(0.047 \mathrm{~mol}-\mathrm{CO}_{2} / \mathrm{mol}\)

A recent attempt to circumnavigate the world in a balloon used a helium-filled balloon whose volume was \(7240 \mathrm{~m}^{3}\) and surface area was \(1800 \mathrm{~m}^{2}\). The skin of this balloon is \(2 \mathrm{~mm}\) thick and is made of a material whose helium diffusion coefficient is \(1 \times 10^{-9} \mathrm{~m}^{2} / \mathrm{s}\). The molar concentration of the helium at the inner surface of the balloon skin is \(0.2 \mathrm{kmol} / \mathrm{m}^{3}\) and the molar concentration at the outer surface is extremely small. The rate at which helium is lost from this balloon is (a) \(0.26 \mathrm{~kg} / \mathrm{h}\) (b) \(1.5 \mathrm{~kg} / \mathrm{h}\) (c) \(2.6 \mathrm{~kg} / \mathrm{h}\) (d) \(3.8 \mathrm{~kg} / \mathrm{h}\) (e) \(5.2 \mathrm{~kg} / \mathrm{h}\)

Write down the relations for steady one-dimensional heat conduction and mass diffusion through a plane wall, and identify the quantities in the two equations that correspond to each other.

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