Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider a person who is resting or doing light work. Is it fair to say that roughly one-third of the metabolic heat generated in the body is dissipated to the environment by convection, one-third by evaporation, and the remaining onethird by radiation?

Short Answer

Expert verified
Answer: As a rough estimate, it is fair to say that in a person resting or doing light work, the metabolic heat generated in the body can be dissipated one-third by each mode: convection, evaporation, and radiation. However, factors such as humidity, air temperature, air movement, and the individual's metabolic rate can influence the proportions of heat dissipation by each mode, and in certain conditions, one mode may become more effective than the others, resulting in a deviation from the one-third proportion for each mode.

Step by step solution

01

Understand the modes of heat transfer in the human body

There are three main methods through which heat can be transferred in the human body: conduction, convection, and radiation. Conduction is the transfer of heat between objects that are in direct contact with each other. In the human body, heat conduction occurs between various tissues and fluids, such as blood, skin, and organs. However, conduction is not the primary mode of heat transfer to the environment in this case. Convection is the transfer of heat by the movement of air or water around the skin. In the human body, convection primarily occurs when warmer blood near the skin's surface warms the surrounding air, creating a "boundary layer" that dissipates heat to the environment. Evaporation is the change of state from a liquid to a gas, and it occurs in the human body mainly due to sweating. When sweat evaporates, it takes some heat away from the body, cooling it down. Finally, radiation is the transfer of heat between objects that are not in direct contact with each other through electromagnetic waves. The human body emits infrared radiation, which can transfer heat to the environment.
02

Investigate the proportions of heat dissipation

To determine if it is fair to say that one-third of the metabolic heat generated in the body is dissipated by each mode, we must consider the factors that impact the efficiency of each mode of heat transfer. 1. Convection: The efficiency of convective heat transfer depends on factors like the surrounding air temperature, air movement, and skin surface temperature. The effectiveness of convection can increase due to increased airflow (e.g., wind), higher skin temperatures, or cooler surrounding temperatures. 2. Evaporation: The efficiency of evaporative heat transfer depends mainly on the humidity level and temperature. In high humidity conditions, the rate of evaporation decreases, making it less effective in dissipating heat. Conversely, in low humidity or high air movement conditions, evaporation becomes more effective. 3. Radiation: The efficiency of heat transfer through radiation depends on the temperature difference between the body surface and the surrounding environment. When both temperatures are similar, the effectiveness of radiation decreases.
03

Conclusion

It is fair to say that for a person resting or doing light work, about one-third of the metabolic heat generated in the body is dissipated to the environment by convection, one-third by evaporation, and the remaining one-third by radiation as a rough estimate. However, factors such as humidity, air temperature, air movement, and the individual's metabolic rate play a role in the proportions of heat dissipation by each mode. In certain conditions, one mode could become more effective than the others, and the proportions may not be exactly one-third for each mode.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metabolic Heat Dissipation
Metabolic heat dissipation refers to the process by which the human body releases the heat generated during metabolism to maintain a stable internal temperature. The body needs to rid itself of excess heat to prevent overheating, which is crucial for normal physiological functions. This heat dissipation happens through various mechanisms that work continuously to keep the body's temperature regulated.

In a resting or lightly active state, the body works to dissipate the metabolic heat through convection, evaporation, and radiation. Each of these modes contributes to maintaining thermal equilibrium under normal conditions. The idea that each mode accounts for roughly one-third of the total heat dissipation provides a simple breakdown, although the exact proportions may vary based on environmental conditions. Understanding these processes helps illustrate how the body adapts to different environments and how activities influence heat management.
Convection in Humans
Convection is the process by which heat is transferred through the movement of fluids or gases. In the context of human heat dissipation, convection occurs when blood circulates near the skin's surface and heats the surrounding air. This warmer air then rises, creating a cycle that draws cooler air across the skin to maintain temperature balance.

Several factors can affect the effectiveness of convective heat transfer, such as:
  • Airflow: Increased air movement (such as wind or a fan) enhances convection by speeding up the removal of the warm air from the body.
  • Temperature gradients: A greater difference between body and air temperature can increase the rate of heat loss.
  • Surface area: Larger skin exposure can allow more heat to dissipate by convection.
Thus, while convection is typically considered to account for about one-third of heat dissipation, it can be more dominant in cooler, breezy environments.
Evaporation of Sweat
Sweat evaporation is a crucial mechanism for heat dissipation, especially in warmer conditions. When the body heats up, sweat glands produce sweat on the skin's surface. As sweat evaporates, it absorbs heat energy from the body, effectively cooling it down.

The efficiency of evaporative heat loss is heavily influenced by:
  • Humidity: High humidity levels make evaporation less effective since the air is already saturated with moisture.
  • Air movement: In conditions with good airflow, evaporation rates increase as sweat is removed more rapidly from the skin's surface.
  • Temperature: Warmer temperatures can aid evaporation, making it a powerful heat dissipation method in hot climates.
Overall, evaporation can also account roughly for a third of heat dissipation, particularly in hot, dry conditions where sweating is a primary cooling mechanism.
Radiation from Human Body
Radiation is the process by which the body emits heat in the form of infrared energy. Unlike conduction or convection, radiation does not require any medium or contact for heat transfer. The human body radiates heat to cooler surroundings without the need for direct interaction.

This mode of heat transfer is primarily dependent on:
  • Temperature differential: Greater temperature differences between the body and the surrounding environment enhance radiative heat loss.
  • Surface exposure: More exposed skin surfaces enable higher heat radiation.
  • Environmental temperatures: Cooler surroundings make radiation more effective in dispersing body heat.
In many situations, radiation accounts for about a third of the body's heat dissipation, especially in cooler environments where the temperature differential between the body and surroundings is significant.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two very large parallel plates are maintained at uniform temperatures of \(T_{1}=1000 \mathrm{~K}\) and \(T_{2}=800 \mathrm{~K}\) and have emissivities of \(\varepsilon_{1}=\varepsilon_{2}=0.5\), respectively. It is desired to reduce the net rate of radiation heat transfer between the two plates to one-fifth by placing thin aluminum sheets with an emissivity of \(0.1\) on both sides between the plates. Determine the number of sheets that need to be inserted.

Two very long concentric cylinders of diameters \(D_{1}=\) \(0.35 \mathrm{~m}\) and \(D_{2}=0.5 \mathrm{~m}\) are maintained at uniform temperatures of \(T_{1}=950 \mathrm{~K}\) and \(T_{2}=500 \mathrm{~K}\) and have emissivities \(\varepsilon_{1}=1\) and \(\varepsilon_{2}=0.55\), respectively. Determine the net rate of radiation heat transfer between the two cylinders per unit length of the cylinders.

A dryer is shaped like a long semicylindrical duct of diameter \(1.5 \mathrm{~m}\). The base of the dryer is occupied with water soaked materials to be dried, and maintained at a temperature of \(370 \mathrm{~K}\) and emissivity of \(0.5\). The dome of the dryer is maintained at \(1000 \mathrm{~K}\) with emissivity of \(0.8\). Determine the drying rate per unit length experienced by the wet materials.

Consider a cylindrical enclosure with \(A_{1}, A_{2}\), and \(A_{3}\) representing the internal base, top, and side surfaces, respectively. Using the length to diameter ratio, \(K=L D\), determine \((a)\) the expression for the view factor between the base and the side surface \(F_{13}\) in terms of \(K\) and \((b)\) the value of the view factor \(F_{13}\) for \(L=D\).

Consider an equimolar mixture of \(\mathrm{CO}_{2}\) and \(\mathrm{O}_{2}\) gases at \(800 \mathrm{~K}\) and a total pressure of \(0.5\) atm. For a path length of \(1.2 \mathrm{~m}\), determine the emissivity of the gas.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free