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Heat dissipated from an engine in operation can cause hot spots on its surface. If the outer surface of an engine is situated in a place where oil leakage is possible, then when the leaked oil comes in contact with hot spots above the oil's autoignition temperature, it can ignite spontaneously. Consider an engine outer surface that can be approximated as a blackbody. To prevent fire hazard in the event of oil leak on the engine surface, the surface temperature of the engine should be kept below \(180^{\circ} \mathrm{C}\). A radiometer is placed normal to and at a distance of \(1 \mathrm{~m}\) from the engine surface to monitor the surface temperature. The radiometer receives radiation from a target area of \(1 \mathrm{~cm}^{2}\) of the engine surface. If the radiometer detects an irradiation of \(0.1 \mathrm{~W} / \mathrm{m}^{2}\), would there be any risk of fire hazard?

Short Answer

Expert verified
Answer: No, there is no risk of fire hazard in this case, as the calculated surface temperature of the engine is 100.52°C, which is below the threshold of 180°C.

Step by step solution

01

Compute the irradiation from the engine surface

Using the inverse square law, we can calculate the irradiation emitted by the engine's surface: \(I = \frac{I_R \cdot D^2}{A} = \frac{0.1 \frac{W}{m^2} \cdot (1 m)^2}{1 \times 10^{-4} m^2} = 1000 \frac{W}{m^2}\)
02

Compute the surface temperature

Using the Stefan-Boltzmann law, we can now find the temperature of the engine's surface: \(I = \sigma T^4 \Rightarrow T = \sqrt[4]{\frac{I}{\sigma}} = \sqrt[4]{\frac{1000 \frac{W}{m^2}}{5.670 \times 10^{-8} \frac{W}{m^2 \cdot K^4}}} = 373.67 K\)
03

Convert temperature to Celsius

To compare the calculated temperature with the given threshold of 180°C, we need to convert the temperature from Kelvin to Celsius: \(T_{Celsius} = T_{Kelvin} - 273.15 = 373.67 K - 273.15 = 100.52°C\)
04

Determine if there is a risk of fire hazard

The calculated surface temperature of the engine is 100.52°C, which is below the threshold of 180°C. Therefore, there wouldn't be any risk of fire hazard in this case.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Blackbody Radiation
Blackbody radiation is a type of thermal radiation emitted by an object due to its temperature. The concept of a blackbody refers to an idealized physical body that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence. Blackbodies are perfect emitters of radiation, meaning they have a characteristic spectrum of emitted radiation that depends solely on their temperature.

In practical terms, blackbody radiation is significant for understanding how objects emit heat. For example, the engine in the exercise is treated as a blackbody. This approximation helps in accurately predicting how much heat the engine's surface will radiate based on its temperature. The emitted radiation helps us determine the temperature of the engine's surface – a critical factor when assessing fire hazards in the context of oil leakage.
Stefan-Boltzmann Law
The Stefan-Boltzmann Law is a fundamental principle in thermal physics that describes the power radiated from a blackbody in terms of its temperature. It is given by the equation: \[ I = \sigma T^4 \] Here, \( I \) is the total energy radiated per unit surface area, \( \sigma \) is the Stefan-Boltzmann constant \( (5.670 \times 10^{-8} \frac{W}{m^2 K^4}) \), and \( T \) is the absolute temperature in Kelvin.

In the original exercise, this law is used to calculate the temperature of the engine's surface based on the radiation measurement detected. By rearranging the formula, you can solve for \( T \), the temperature of the surface:
\[ T = \sqrt[4]{\frac{I}{\sigma}} \]
This calculation is essential for assessing whether the surface temperature is safe and below the oil's autoignition temperature, ensuring fire hazard prevention.
Fire Hazard Prevention
Preventing fire hazards is crucial, especially in engineering applications like engines that operate under high temperatures. The primary goal is to keep the surface temperature of potentially flammable surroundings, such as oil, below its autoignition temperature. This is the lowest temperature at which it can spontaneously ignite without an external flame or spark.

In the exercise scenario, the oil must not reach 180°C in contact with the heated engine surface. Regular monitoring using radiation measurement techniques, as depicted in the exercise, ensures that the surface temperature stays safe, thereby preventing potential fire hazards. Understanding and controlling heat transfer in this manner is a practical application of blackbody and Stefan-Boltzmann principles.
Radiation Measurement
Radiation measurement is a powerful technique used to gauge the temperature of objects remotely by examining the radiation they emit. This process is integral to applications where direct temperature measurement is impractical or unsafe. The radiometer, a device for measuring radiation, plays a vital role here.

In the original exercise, a radiometer is used to monitor the surface temperature of the engine from a safe distance of 1 meter. The measurement of irradiation received helps in calculating the actual surface temperature using laws of thermal radiation, such as the Stefan-Boltzmann law. By knowing the local temperature, engineers can ensure that the machinery operates safely and is within controlled thermal limits to prevent overheating and fire hazards.

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Most popular questions from this chapter

A flame from a match may be approximated as a blackbody at the effective surface temperature of \(1700 \mathrm{~K}\), while moonlight may be approximated as a blackbody at the effective surface temperature of \(4000 \mathrm{~K}\), respectively. Determine the peak spectral blackbody emissive power for both lighting sources (match flame and moonlight).

A small surface of area \(A=3 \mathrm{~cm}^{2}\) emits radiation with an intensity of radiation that can be expressed as \(I_{e}(\theta, \phi)=100 \phi \cos \theta\), where \(I_{e}\) has the units of \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{sr}\). Determine the emissive power from the surface into the hemisphere surrounding it, and the rate of radiation emission from the surface.

What is a shading device? Is an internal or external shading device more effective in reducing the solar heat gain through a window? How does the color of the surface of a shading device facing outside affect the solar heat gain?

A surface is exposed to solar radiation. The direct and diffuse components of solar radiation are 350 and \(250 \mathrm{~W} / \mathrm{m}^{2}\), and the direct radiation makes a \(35^{\circ}\) angle with the normal of the surface. The solar absorptivity and the emissivity of the surface are \(0.24\) and \(0.41\), respectively. If the surface is observed to be at \(315 \mathrm{~K}\) and the effective sky temperature is \(256 \mathrm{~K}\), the net rate of radiation heat transfer to the surface is (a) \(-129 \mathrm{~W} / \mathrm{m}^{2}\) (b) \(-44 \mathrm{~W} / \mathrm{m}^{2}\) (c) \(0 \mathrm{~W} / \mathrm{m}^{2}\) (d) \(129 \mathrm{~W} / \mathrm{m}^{2}\) (e) \(537 \mathrm{~W} / \mathrm{m}^{2}\)

A horizontal opaque flat plate is well insulated on the edges and the lower surface. The top surface has an area of \(5 \mathrm{~m}^{2}\), and it experiences uniform irradiation at a rate of \(5000 \mathrm{~W}\). The plate absorbs \(4000 \mathrm{~W}\) of the irradiation, and the surface is losing heat at a rate of \(500 \mathrm{~W}\) by convection. If the plate maintains a uniform temperature of \(350 \mathrm{~K}\), determine the absorptivity, reflectivity, and emissivity of the plate.

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