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For a surface, how is irradiation defined? For diffusely incident radiation, how is irradiation on a surface related to the intensity of incident radiation?

Short Answer

Expert verified
Answer: The relationship between the irradiation (G) and the intensity of diffusely incident radiation (I) on a surface can be described by Lambert's cosine law, which states that G(θ) = I_0 * cos(θ), where θ is the angle between the normal to the surface and the direction of the incident radiation, and I_0 is the intensity of the incident radiation when it is perpendicular to the surface (θ = 0°). Irradiation decreases with increasing angle, reaching a maximum when the angle is 0° and falling to zero when the angle is 90°.

Step by step solution

01

Define Irradiation

Irradiation is defined as the amount of radiant energy received per unit area of a surface per unit time. It is expressed in units of Watts per square meter (W/m^2). It is essentially a measure of how much radiant energy is incident on a particular surface.
02

Explain Diffusely Incident Radiation

Diffusely incident radiation refers to the situation where the radiation is incident on a surface from all possible directions. This means that the radiation is not focused, but rather scattered uniformly over the entire surface. This usually occurs in the case of diffuse reflection or scattering, where the incident radiation gets scattered off a rough surface, or in situations where the source of radiation is large and distant, like the sun.
03

Relate Irradiation to Intensity of Incident Radiation

For diffusely incident radiation, the irradiation (G) on a surface is related to the intensity of the incident radiation (I) by the Lambert's cosine law. This law states that the irradiation received on a surface is proportional to the cosine of the angle (\theta) between the normal to the surface and the direction of the incident radiation. Mathematically, it can be written as: G(\theta) = I_0 \cdot \cos{\theta} where I_0 is the intensity of the incident radiation when it is perpendicular to the surface (angle \theta = 0°) and G(\theta) is the irradiation received on the surface at an angle \theta.
04

Explain Lambert's Cosine Law Conceptually

Lambert's cosine law relates irradiation and the incident intensity in the case of diffusely incident radiation because as the angle between the normal to the surface and the direction of the incident radiation increases, the effective area of the surface exposed to the radiation decreases. This causes a reduction in the amount of energy received on the surface per unit time, leading to a decrease in the irradiation. With the cosine function, the irradiation becomes maximum when the angle is 0° (i.e., radiation is perpendicular to the surface) and falls to zero when the angle is 90° (i.e., radiation is parallel to the surface).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
The process of heat transfer involves the movement of energy from one place to another due to temperature difference. In our daily lives, we witness the effects of heat transfer when a hot cup of coffee cools down or when the sun warms our skin. There are three main modes of heat transfer: conduction, convection, and radiation.

Conduction occurs through direct contact, where heat energy passes from one molecule to another. On the other hand, convection happens in fluids (liquids and gases) when warmer parts of the fluid rise and cooler parts sink, creating a cycle and causing heat transfer. Finally, radiation is the transfer of energy through space by electromagnetic waves, like the warmth we feel from sunlight, which is the focus of our topic on irradiation.

Understanding these fundamental principles of heat transfer is crucial for solving problems related to thermal energy exchanges, such as calculating the cooling rate of an object or designing insulation for buildings.
Lambert's Cosine Law
Lambert's cosine law is pivotal in understanding how light interacts with surfaces. This principle is instrumental when dealing with radiant energy and its distribution on various surfaces. What Lambert's law tells us is that the intensity of illumination or irradiation on a surface is directly proportional to the cosine of the angle (\theta) between the direction of the incident radiation and the normal (perpendicular) to the surface.

The law can be expressed mathematically as:\[ G(\theta) = I_0 \cdot \cos{\theta} \]where \( I_0 \) is the radiant intensity when the radiation is perpendicular to the surface. The importance of Lambert's cosine law lies in various scientific fields, including photography, astronomy, and computer graphics, where it helps to create realistic rendering of how light and shadow interact with objects.
Radiant Energy
Radiant energy is a form of energy that travels in waves and can move through the vacuum of space. It is part of the electromagnetic spectrum, which includes visible light, infrared radiation, ultraviolet radiation, X-rays, and more. When we talk about irradiation in the context of heat transfer, we are referring to the radiant energy received by a surface.

This energy can come from various sources, such as the sun, which emits solar radiation, or artificial sources like light bulbs. Understanding radiant energy is fundamental in many technologies, including solar panels, which convert radiant energy from the sun into electrical energy. Moreover, in terms of heat transfer, radiant energy does not require a medium to travel through, making it unique compared to conduction and convection.
Intensity of Incident Radiation
The intensity of incident radiation is a measure of the power of radiation received per unit area, commonly expressed in watts per square meter (W/m^2). In terms of irradiation, this intensity can vary based on several factors, such as the distance from the source, the angle of incidence, and the type of medium the radiation travels through before reaching the surface.

Intensity is a critical variable when calculating the amount of radiant energy a surface will absorb or reflect. To further illustrate, when the sun is at its zenith, the intensity of its radiation on a perpendicular surface on Earth is at a maximum. As the sun moves away from the perpendicular, the intensity on that surface decreases, which is precisely outlined by Lambert's cosine law. For practical applications, predicting and maximizing the intensity of incident radiation can have significant implications, such as in the design and placement of solar panels to achieve optimal energy capture.

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Most popular questions from this chapter

Consider an opaque horizontal plate that is well insulated on the edges and the lower surface. The plate is uniformly irradiated from above while air at \(T_{\infty}=300 \mathrm{~K}\) flows over the surface providing a uniform convection heat transfer coefficient of \(40 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Under steady state conditions the surface has a radiosity of \(4000 \mathrm{~W} / \mathrm{m}^{2}\), and the plate temperature is maintained uniformly at \(350 \mathrm{~K}\). If the total absorptivity of the plate is \(0.40\), determine \((a)\) the irradiation on the plate, \((b)\) the total reflectivity of the plate, \((c)\) the emissive power of the plate, and \((d)\) the total emissivity of the plate.

The reflectivity of aluminum coated with lead sulfate is \(0.35\) for radiation at wavelengths less than \(3 \mu \mathrm{m}\) and \(0.95\) for radiation greater than \(3 \mu \mathrm{m}\). Determine the average reflectivity of this surface for solar radiation \((T \approx 5800 \mathrm{~K})\) and radiation coming from surfaces at room temperature \((T \approx 300 \mathrm{~K})\). Also, determine the emissivity and absorptivity of this surface at both temperatures. Do you think this material is suitable for use in solar collectors?

Consider an opaque plate that is well insulated on the edges and it is heated at the bottom with an electric heater. The plate has an emissivity of \(0.67\), and is situated in an ambient surrounding temperature of \(7^{\circ} \mathrm{C}\) where the natural convection heat transfer coefficient is \(7 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). To maintain a surface temperature of \(80^{\circ} \mathrm{C}\), the electric heater supplies \(1000 \mathrm{~W} / \mathrm{m}^{2}\) of uniform heat flux to the plate. Determine the radiosity of the plate under these conditions.

What is the cause of color? Why do some objects appear blue to the eye while others appear red? Is the color of a surface at room temperature related to the radiation it emits?

Consider a building located near \(40^{\circ} \mathrm{N}\) latitude that has equal window areas on all four sides. The building owner is considering coating the south-facing windows with reflective film to reduce the solar heat gain and thus the cooling load. But someone suggests that the owner will reduce the cooling load even more if she coats the west-facing windows instead. What do you think?

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