Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the effect of a low-e coating on the inner surface of a window glass on the \((a)\) heat loss in winter and (b) heat gain in summer through the window?

Short Answer

Expert verified
Answer: Low-e coating on the inner surface of a window glass helps in reducing heat loss in winter by reflecting radiant heat back into the room, making the room warmer and reducing the energy required to maintain the desired temperature. In summer, the low-e coating helps in reducing heat gain by reflecting incident solar radiation back outside, making the room cooler and reducing air conditioning requirements. This leads to energy-efficient windows and significant energy savings.

Step by step solution

01

Understanding Low-E Coating

Low-emissivity (low-e) coating is a thin metallic layer applied to the surface of a window glass to reduce the amount of radiant heat transfer through the glass. It is designed to minimize the amount of infrared rays that pass through the glass while allowing visible light to transmit through.
02

Effect on Heat Loss in Winter (a)

In winter, low-e coating on the inner surface of a window glass helps to minimize heat loss from inside the room to the outside environment. It does so by reflecting the radiant heat back into the room. Let's break down its effect on heat loss in winter: Step 1: Radiant heat (infrared rays) from inside the room strikes the low-e coated surface of the window glass. Step 2: The low-e coating reflects a majority of the radiant heat back into the room, thus reducing the amount of heat that would otherwise escape through the glass to the outside environment. Step 3: As a result, the room remains warmer, lesser energy is required to maintain the desired indoor temperature, and heat loss through the window is reduced.
03

Effect on Heat Gain in Summer (b)

In summer, the low-e coating on the inner surface of a window glass helps to reduce the unwanted heat gain from the outside environment. It does so by reflecting the incident solar radiation back outside. Let's break down its effect on heat gain in summer: Step 1: Solar radiation, composed of visible light, ultraviolet, and infrared rays, strikes the outer surface of the window glass. Step 2: The window glass absorbs a portion of the solar radiation, while some of it passes directly through the glass. The low-insulated glass covered with low-e coating inner surface performs better in reduction of heat gain during summers. Step 3: The low-e coating on the inner surface of the glass reflects a significant amount of the incident solar radiation (especially infrared rays), thus reducing the amount of heat that enters the room. Step 4: As a result, the room remains cooler, air conditioning requirements are reduced, and unwanted heat gain through the window is minimized. In summary, a low-e coating on the inner surface of a window glass effectively reduces (a) heat loss in winter and (b) heat gain in summer, resulting in energy-efficient windows and significant energy savings.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is the movement of thermal energy from one object or material to another. This can occur in several ways:
  • Conduction: Transfer of heat through direct contact between materials.
  • Convection: Transfer of heat through fluids (liquids and gases) due to the movement of the fluid itself.
  • Radiation: Transfer of heat in the form of electromagnetic waves, such as infrared radiation.
When it comes to windows, heat transfer plays a crucial role in determining the temperature inside a building. Windows can lose or gain heat and thereby affect the overall energy efficiency of a building.
Understanding how heat moves can help in designing more efficient windows, especially with the use of low-emissivity coatings that specifically target radiation.
Infrared Radiation
Infrared radiation is a type of electromagnetic radiation that is not visible to the human eye but is felt as heat. It plays a significant role in heat transfer processes.
Low-emissivity (low-e) coatings on windows are specifically designed to manage infrared radiation. The coatings are thin layers of metal used to reflect infrared rays.
  • In winter, they reflect the infrared radiation (heat) back into the room, helping to keep interiors warm.
  • In summer, they prevent infrared radiation from entering, thus keeping interiors cool.
This management of infrared radiation is key to making windows more energy efficient, as it minimizes unwanted heat loss or gain.
Energy Efficiency
Energy efficiency refers to using less energy to provide the same service. For windows, being energy efficient means reducing the heat loss in the winter and minimizing the heat gain in the summer.
Low-e coatings contribute significantly to a window's energy efficiency. By controlling the flow of infrared radiation:
  • In the winter, they keep heat inside the building, reducing the need for heating appliances.
  • In the summer, they prevent excess heat from entering, reducing the need for air conditioning.
Using windows with low-e coatings can therefore lead to lower energy bills and a smaller environmental footprint.
Window Insulation
Window insulation is essential for a comfortable indoor environment and to reduce energy consumption. Properly insulated windows minimize the transfer of heat, keeping spaces warm in winter and cool in summer.
Low-e coatings enhance window insulation by:
  • Increasing the reflective properties of the glass to handle infrared radiation effectively.
  • Maintaining interior temperatures by reducing heat flow.
These coatings act as an added insulation layer, allowing windows to perform better in extreme weather conditions. Improved insulation not only ensures comfort but also contributes to significant energy savings each year.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A radiometer is employed to monitor the temperature of manufactured parts \(\left(A_{1}=10 \mathrm{~cm}^{2}\right)\) on a conveyor. The radiometer is placed at a distance of \(1 \mathrm{~m}\) from and normal to the manufactured parts. When a part moves to the position normal to the radiometer, the sensor measures the radiation emitted from the part. In order to prevent thermal burn on people handling the manufactured parts at the end of the conveyor, the temperature of the parts should be below \(45^{\circ} \mathrm{C}\). An array of spray heads is programmed to discharge mist to cool the parts when the radiometer detects a temperature of \(45^{\circ} \mathrm{C}\) or higher on a part. If the manufactured parts can be approximated as blackbody, determine the irradiation on the radiometer that should trigger the spray heads to release cooling mist when the temperature is not below \(45^{\circ} \mathrm{C}\).

A microwave oven is designed to operate at a frequency of \(2.2 \times 10^{9} \mathrm{~Hz}\). Determine the wavelength of these microwaves and the energy of each microwave.

A horizontal plate is experiencing uniform irradiation on the both upper and lower surfaces. The ambient air temperature surrounding the plate is \(290 \mathrm{~K}\) with a convection heat transfer coefficient of \(30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Both upper and lower surfaces of the plate have a radiosity of \(4000 \mathrm{~W} / \mathrm{m}^{2}\), and the plate temperature is maintained uniformly at \(390 \mathrm{~K}\). If the plate is not opaque and has an absorptivity of \(0.527\), determine the irradiation and emissivity of the plate.

Daylight and incandescent light may be approximated as a blackbody at the effective surface temperatures of \(5800 \mathrm{~K}\) and \(2800 \mathrm{~K}\), respectively. Determine the wavelength at maximum emission of radiation for each of the lighting sources.

By what properties is an electromagnetic wave characterized? How are these properties related to each other?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free