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Can the temperature of the hot fluid drop below the inlet temperature of the cold fluid at any location in a heat exchanger? Explain.

Short Answer

Expert verified
Answer: No, the temperature of the hot fluid cannot drop below the inlet temperature of the cold fluid in a heat exchanger setup, as it would violate the principles of energy conservation governed by the first law of thermodynamics. The lowest temperature the hot fluid can reach is equal to the inlet temperature of the cold fluid.

Step by step solution

01

Understanding the Heat Exchanger

A heat exchanger is a device used to transfer heat from one fluid to another. It consists of an inlet and outlet for both fluids (hot and cold). The hot fluid loses heat, whereas the cold fluid gains heat without any actual mixing of fluids.
02

First Law of Thermodynamics in Heat Exchangers

According to the first law of thermodynamics, energy cannot be created or destroyed but can only change forms. Thus, within the heat exchanger, heat energy lost by the hot fluid must be equal to the heat energy gained by the cold fluid. Mathematically, we can represent this as: Q_h = Q_c Where Q_h is the heat energy lost by the hot fluid, and Q_c is the heat energy gained by the cold fluid.
03

Inlet Temperature and Heat Transfer

The inlet temperature of the cold fluid (T_in_cold) is the minimum temperature that the hot fluid (T_hot) can reach, because of the limitations imposed by energy conservation. If the hot fluid were to reach a lower temperature than the inlet temperature of the cold fluid, it would mean that the cold fluid would have gained more energy than the hot fluid had lost, which would violate the first law of thermodynamics.
04

Conclusion

It is not possible for the temperature of the hot fluid to drop below the inlet temperature of the cold fluid at any location in a heat exchanger, as it would contradict the principles of energy conservation governed by the first law of thermodynamics. The lowest temperature the hot fluid can reach is equal to the inlet temperature of the cold fluid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Law of Thermodynamics
The First Law of Thermodynamics is a crucial principle in understanding how heat exchangers operate. Think of it as the law of energy conservation. According to this law, energy can neither be created nor destroyed; it can only change from one form to another or be transferred.

In a heat exchanger, this translates to the heat energy lost by the hot fluid being equal to the heat energy gained by the cold fluid. Using the equation \( Q_h = Q_c \), where \( Q_h \) represents the heat lost by the hot fluid, and \( Q_c \) is the heat gained by the cold fluid, we can see that the total energy remains constant.

This ensures that both fluids can exchange heat without violating the principle of energy conservation. It also helps to understand why the performance of the heat exchanger is predictable and aligned with the laws of physics.
Temperature Limits in Heat Exchangers
In a heat exchanger, temperature limits are governed by the need to maintain energy conservation. When the hot fluid passes through a heat exchanger, its temperature decreases as it loses heat energy. However, a critical limit exists relating to the temperature of the cold fluid.

At no point in the heat exchanger can the temperature of the hot fluid drop below the inlet temperature of the cold fluid. This is because such a scenario would imply that the cold fluid is gaining more heat than the hot fluid is losing, which would contradict the First Law of Thermodynamics. Simply put, the lowest temperature the hot fluid can reach is the temperature at which the cold fluid enters the exchanger.

This fundamental constraint ensures the heat exchanger operates correctly and efficiently, making it predictable in its performance and ensuring that its capacity isn't overestimated.
Heat Transfer Mechanisms
Heat exchangers rely on certain mechanisms to transfer heat from the hot fluid to the cold fluid without directly mixing the two. The heat transfer process primarily involves two phenomena - conduction and convection.

**Conduction:** This occurs when heat flows through a solid wall, like the metal that often separates the hot and cold fluids in a heat exchanger. It's the process where heat is transferred from the hot fluid through the solid barrier to the colder fluid on the other side.

**Convection:** This mechanism takes over once heat reaches the fluid on the opposite side of the barrier. The heat causes the cooler fluid to become hotter through the movement of the fluid itself, distributing energy uniformly throughout the fluid.

Together, these mechanisms ensure efficient heat transfer without the fluids mixing, uphold the principle of energy conservation, and prevent temperature dips of the hot fluid below the cold fluid's inlet temperature.

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Most popular questions from this chapter

Saturated water vapor at \(40^{\circ} \mathrm{C}\) is to be condensed as it flows through the tubes of an air-cooled condenser at a rate of \(0.2 \mathrm{~kg} / \mathrm{s}\). The condensate leaves the tubes as a saturated liquid at \(40^{\circ} \mathrm{C}\). The rate of heat transfer to air is (a) \(34 \mathrm{~kJ} / \mathrm{s}\) (b) \(268 \mathrm{~kJ} / \mathrm{s}\) (c) \(453 \mathrm{~kJ} / \mathrm{s}\) (d) \(481 \mathrm{~kJ} / \mathrm{s}\) (e) \(515 \mathrm{~kJ} / \mathrm{s}\)

An air-cooled condenser is used to condense isobutane in a binary geothermal power plant. The isobutane is condensed at \(85^{\circ} \mathrm{C}\) by air \(\left(c_{p}=1.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) that enters at \(22^{\circ} \mathrm{C}\) at a rate of \(18 \mathrm{~kg} / \mathrm{s}\). The overall heat transfer coefficient and the surface area for this heat exchanger are \(2.4 \mathrm{~kW} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(1.25 \mathrm{~m}^{2}\), respectively. The outlet temperature of air is (a) \(45.4^{\circ} \mathrm{C}\) (b) \(40.9^{\circ} \mathrm{C}\) (c) \(37.5^{\circ} \mathrm{C}\) (d) \(34.2^{\circ} \mathrm{C}\) (e) \(31.7^{\circ} \mathrm{C}\)

A 1-shell-pass and 8-tube-passes heat exchanger is used to heat glycerin \(\left(c_{p}=0.60 \mathrm{Btu} / \mathrm{lbm} \cdot{ }^{\circ} \mathrm{F}\right)\) from \(65^{\circ} \mathrm{F}\) to \(140^{\circ} \mathrm{F}\) by hot water \(\left(c_{p}=1.0 \mathrm{Btu} / \mathrm{lbm} \cdot{ }^{\circ} \mathrm{F}\right)\) that enters the thinwalled \(0.5\)-in-diameter tubes at \(175^{\circ} \mathrm{F}\) and leaves at \(120^{\circ} \mathrm{F}\). The total length of the tubes in the heat exchanger is \(500 \mathrm{ft}\). The convection heat transfer coefficient is \(4 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2} \cdot{ }^{\circ} \mathrm{F}\) on the glycerin (shell) side and \(50 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}^{2} \cdot{ }^{\circ} \mathrm{F}\) on the water (tube) side. Determine the rate of heat transfer in the heat exchanger \((a)\) before any fouling occurs and \((b)\) after fouling with a fouling factor of \(0.002 \mathrm{~h} \cdot \mathrm{ft}^{2} \cdot{ }^{\circ} \mathrm{F} /\) Btu on the outer surfaces of the tubes.

A company owns a refrigeration system whose refrigeration capacity is 200 tons ( 1 ton of refrigeration = \(211 \mathrm{~kJ} / \mathrm{min}\) ), and you are to design a forced-air cooling system for fruits whose diameters do not exceed \(7 \mathrm{~cm}\) under the following conditions: The fruits are to be cooled from \(28^{\circ} \mathrm{C}\) to an average temperature of \(8^{\circ} \mathrm{C}\). The air temperature is to remain above \(-2^{\circ} \mathrm{C}\) and below \(10^{\circ} \mathrm{C}\) at all times, and the velocity of air approaching the fruits must remain under \(2 \mathrm{~m} / \mathrm{s}\). The cooling section can be as wide as \(3.5 \mathrm{~m}\) and as high as \(2 \mathrm{~m}\). Assuming reasonable values for the average fruit density, specific heat, and porosity (the fraction of air volume in a box), recommend reasonable values for the quantities related to the thermal aspects of the forced-air cooling, including (a) how long the fruits need to remain in the cooling section, \((b)\) the length of the cooling section, \((c)\) the air velocity approaching the cooling section, \((d)\) the product cooling capacity of the system, in \(\mathrm{kg}\) fruit/h, \((e)\) the volume flow rate of air, and \((f)\) the type of heat exchanger for the evaporator and the surface area on the air side.

In a textile manufacturing plant, the waste dyeing water \(\left(c_{p}=4295 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) at \(75^{\circ} \mathrm{C}\) is to be used to preheat fresh water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) at \(15^{\circ} \mathrm{C}\) at the same flow rate in a double-pipe counter-flow heat exchanger. The heat transfer surface area of the heat exchanger is \(1.65 \mathrm{~m}^{2}\) and the overall heat transfer coefficient is \(625 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). If the rate of heat transfer in the heat exchanger is \(35 \mathrm{~kW}\), determine the outlet temperature and the mass flow rate of each fluid stream.

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