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When the outlet temperatures of the fluids in a heat exchanger are not known, is it still practical to use the LMTD method? Explain.

Short Answer

Expert verified
Answer: Yes, the LMTD method can be practically applied to heat exchangers when the outlet temperatures are unknown, as long as additional information, such as the desired heat transfer rate (Q) or the overall heat transfer coefficient (U), is available. An iterative process is used to estimate the outlet temperatures and calculate the LMTD.

Step by step solution

01

The LMTD Method

The Log Mean Temperature Difference (LMTD) method is an analytical technique used to determine the performance of heat exchangers. It is defined as the ratio of the overall temperature difference between the hot and cold fluids to the logarithmic mean of the individual temperature differences: LMTD = (ΔT1 - ΔT2) / ln(ΔT1/ΔT2), where ΔT1 and ΔT2 are the temperature differences between the hot and cold fluids at the inlet and outlet of the heat exchanger, respectively.
02

Purpose of the LMTD Method

The LMTD method's core purpose is to evaluate the heat transfer effectiveness of a heat exchanger. It takes into account the temperature differences between the hot and cold fluids at various points along the heat exchanger. By calculating the LMTD, we can then find the heat transfer rate (Q), heat transfer area (A), or the overall heat transfer coefficient (U), making it an essential tool for heat exchanger design.
03

LMTD and Unknown Outlet Temperatures

The LMTD method requires the knowledge of both inlet and outlet temperatures of the hot and cold fluids to make accurate calculations. However, since we are asked if it is still practical to use the LMTD method when the outlet temperatures of the fluids are unknown, we must consider how this affects the analysis. The LMTD method can still be applied if the outlet temperatures are unknown, provided that there is an additional piece of information available, such as the desired heat transfer rate (Q) or the overall heat transfer coefficient (U). In these cases, an iterative process can be used to estimate the outlet temperatures and then calculate the LMTD. This process involves making an initial guess for the unknown outlet temperatures, calculating the LMTD, then refining the temperature guesses based on other known parameters (e.g., Q or U) until a satisfactory level of convergence is achieved.
04

Conclusion

In conclusion, the LMTD method can theoretically still be used in heat exchanger analysis, even when the outlet temperatures of the fluids are unknown. However, it requires additional information such as the heat transfer rate or overall heat transfer coefficient and an iterative process to estimate the outlet temperatures. Therefore, the practicality of using the LMTD method in such cases depends on the availability of this extra information and the willingness to go through an iterative calculation process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Exchanger Performance
In the context of heat exchangers, performance primarily refers to the device's efficacy in transferring heat from one fluid to another. Key performance indicators include the heat transfer rate and the overall heat transfer coefficient. Achieving optimal performance involves designing the heat exchanger to maximize heat transfer while minimizing energy consumption and material costs.

The performance of a heat exchanger can be adjusted by manipulating variables such as the flow rate of fluids, the type of heat exchanger (e.g., shell and tube, plate), materials of construction, and the surface area available for heat transfer. Efficiency improves as more heat is transferred with a less pronounced temperature difference between the fluids.
Log Mean Temperature Difference
The Log Mean Temperature Difference (LMTD) is critical for analyzing the thermal efficiency of heat exchangers. It is defined as the driving force for heat transfer, representing the average temperature difference between the hot and cold fluids over the length of the heat exchanger. The formula given by
\[ LMTD = \frac{\Delta T1 - \Delta T2}{\ln(\Delta T1/\Delta T2)} \]
is used, where \( \Delta T1 \) and \( \Delta T2 \) are the temperature differences at the two ends of the exchanger. A higher LMTD signals a greater potential for heat transfer, allowing for the design of more compact and cost-effective heat exchangers.
Heat Transfer Rate
The heat transfer rate, represented by the symbol \( Q \), measures the amount of heat transferred between fluids in a heat exchanger over time, typically expressed in watts (W) or British thermal units per hour (BTU/hr). It's calculated using the equation
\[ Q = U \times A \times LMTD \]
where \( U \) is the overall heat transfer coefficient and \( A \) is the heat transfer area. The rate at which heat is transferred plays an integral role in sizing the heat exchanger and determining its efficiency and operational costs. A high heat transfer rate means more heat is being effectively moved from one fluid to another, indicating good performance.
Overall Heat Transfer Coefficient
The overall heat transfer coefficient, denoted by \( U \), quantifies the heat transfer capability of a heat exchanger, taking into account all modes of heat transfer (conduction, convection, and radiation) as well as resistance to heat flow. Its units are typically in \( W/(m^2K) \) or \( BTU/(hr\cdot ft^2\cdot °F) \). The value of \( U \) is influenced by the properties of the heat exchanger materials, the fluids' properties, and the flow arrangement.

A higher \( U \) value indicates that the heat exchanger is more effective at transferring heat. Engineering decisions regarding the choice and arrangement of materials, as well as fluid dynamics design, directly impact the overall heat transfer coefficient.
Iterative Calculation Process
When dealing with unknown outlet temperatures in a heat exchanger, an iterative calculation process is used to approximate these values. This technique involves making an initial guess of the outlet temperatures and subsequently refining the guess based on known variables such as the heat transfer rate or overall heat transfer coefficient.

The iterative process continues, updating the guess after each calculation, until the resulting values converge within an acceptable range of accuracy. This method, while more time-consuming, allows for the successful application of the LMTD method in predicting the performance of heat exchangers when certain inputs are unknown.

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Most popular questions from this chapter

Steam is to be condensed on the shell side of a 2-shell-passes and 8-tube- passes condenser, with 20 tubes in each pass. Cooling water enters the tubes a rate of \(2 \mathrm{~kg} / \mathrm{s}\). If the heat transfer area is \(14 \mathrm{~m}^{2}\) and the overall heat transfer coefficient is \(1800 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), the effectiveness of this condenser is (a) \(0.70\) (b) \(0.80\) (c) \(0.90\) (d) \(0.95\) (e) \(1.0\)

In a parallel-flow, liquid-to-liquid heat exchanger, the inlet and outlet temperatures of the hot fluid are \(150^{\circ} \mathrm{C}\) and \(90^{\circ} \mathrm{C}\) while that of the cold fluid are \(30^{\circ} \mathrm{C}\) and \(70^{\circ} \mathrm{C}\), respectively. For the same overall heat transfer coefficient, the percentage decrease in the surface area of the heat exchanger if counter-flow arrangement is used is (a) \(3.9 \%\) (b) \(9.7 \%\) (c) \(14.5 \%\) (d) \(19.7 \%\) (e) \(24.6 \%\)

Consider a shell-and-tube water-to-water heat exchanger with identical mass flow rates for both the hotand cold-water streams. Now the mass flow rate of the cold water is reduced by half. Will the effectiveness of this heat exchanger increase, decrease, or remain the same as a result of this modification? Explain. Assume the overall heat transfer coefficient and the inlet temperatures remain the same.

A shell-and-tube heat exchanger with 1-shell pass and 14-tube passes is used to heat water in the tubes with geothermal steam condensing at \(120^{\circ} \mathrm{C}\left(h_{f g}=2203 \mathrm{~kJ} / \mathrm{kg}\right)\) on the shell side. The tubes are thin-walled and have a diameter of \(2.4 \mathrm{~cm}\) and length of \(3.2 \mathrm{~m}\) per pass. Water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters the tubes at \(22^{\circ} \mathrm{C}\) at a rate of \(3.9 \mathrm{~kg} / \mathrm{s}\). If the temperature difference between the two fluids at the exit is \(46^{\circ} \mathrm{C}\), determine (a) the rate of heat transfer, \((b)\) the rate of condensation of steam, and \((c)\) the overall heat transfer coefficient.

Explain how you can evaluate the outlet temperatures of the cold and hot fluids in a heat exchanger after its effectiveness is determined.

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