Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The radiator in an automobile is a cross-flow heat exchanger \(\left(U A_{s}=10 \mathrm{~kW} / \mathrm{K}\right)\) that uses air \(\left(c_{p}=1.00 \mathrm{~kJ} /\right.\) \(\mathrm{kg} \cdot \mathrm{K})\) to \(\mathrm{cool}\) the engine coolant fluid \(\left(c_{p}=4.00 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\). The engine fan draws \(30^{\circ} \mathrm{C}\) air through this radiator at a rate of \(10 \mathrm{~kg} / \mathrm{s}\) while the coolant pump circulates the engine coolant at a rate of \(5 \mathrm{~kg} / \mathrm{s}\). The coolant enters this radiator at \(80^{\circ} \mathrm{C}\). Under these conditions, what is the number of transfer units (NTU) of this radiator? (a) 1 (b) 2 (c) 3 (d) 4 (e) 5

Short Answer

Expert verified
Answer: (a) 1

Step by step solution

01

Calculate the heat capacity for both streams

First, we'll calculate the heat capacity for both the hot (engine coolant) and cold (air) streams by multiplying the specific heat capacity (cp) with the mass flow rate (m_dot). For hot stream (engine coolant): \(C_h = m_{h} \times c_{p_h} = 5 \frac{kg}{s} \times 4 \frac{kW}{kg \cdot K} = 20 \frac{kW}{K}\) For the cold stream (air): \(C_c = m_{c} \times c_{p_c} = 10 \frac{kg}{s} \times 1 \frac{kW}{kg \cdot K} = 10 \frac{kW}{K}\)
02

Calculate the temperature difference

Next, we'll calculate the difference in temperature between the coolant at the entry of the radiator and the temperature of the incoming air: \(\Delta T = T_{h, in} - T_{c, in} = 80 ^\circ C - 30^\circ C = 50 K\)
03

Determine the minimum heat capacity rate (Cmin)

We need to find which stream has the lower heat capacity product to use it in the NTU formula: \(C_{min} = min(C_h, C_c) = min(20 \frac{kW}{K}, 10 \frac{kW}{K}) = 10 \frac{kW}{K}\)
04

Calculate the NTU

Now we can find the NTU using the overall heat transfer coefficient and surface area (UA), and the minimum heat capacity rate (Cmin). The formula for the NTU is: \(NTU = \frac{UA}{C_{min}}\) Substitute the values: \(NTU = \frac{10 \frac{kW}{K}}{10 \frac{kW}{K}} = 1\) So the answer is (a) 1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-Flow Heat Exchanger
A cross-flow heat exchanger is a system where two fluids at different temperatures pass perpendicularly to each other. Imagine a radiator in a car: hot coolant from the engine flows in one direction while cooler air is drawn through the radiator fins in a perpendicular direction. This arrangement allows for efficient heat transfer as the cooler air absorbs heat from the hot coolant.

In our exercise scenario, the automobile radiator effectively dissipates heat from the engine coolant, using the air as the secondary fluid. This type of heat exchanger is often preferred in cases where the two fluids are at vastly different temperatures and flow rates, as it allows for a compact design and effective heat transfer despite the mismatch.

Understanding the dynamics of cross-flow heat exchangers is crucial for optimizing their performance and ensuring efficient cooling, particularly in automotive applications. The effectiveness of such heat exchangers is often evaluated using the Number of Transfer Units (NTU) method, which is a dimensionless number representing the heat exchanger's capacity to alter a fluid's temperature.
Heat Capacity Rate
The heat capacity rate is a key concept in thermal engineering that represents the ability of a fluid to absorb or release heat. It is calculated by multiplying the fluid's mass flow rate by its specific heat capacity, a measure of how much energy is needed to raise the temperature of one kilogram of the substance by one degree Kelvin.

In the exercise, calculations for the heat capacity rate of both the air (cold stream) and the engine coolant (hot stream) were necessary to compare their respective abilities to retain or transfer heat. The lower heat capacity rate between the two, often denoted as \(C_{min}\), is crucial as it limits the maximum possible heat transfer in a heat exchanger. This value is then used in determining the NTU, which gives us insight into how efficiently the heat exchanger is operating.

The simplicity of this calculation makes it an essential step in solving various heat transfer problems and optimizing thermal systems, providing a straightforward way to gauge a fluid’s role in heat exchange processes.
Overall Heat Transfer Coefficient
The overall heat transfer coefficient, often signified by the symbol \(U\), is an indicator of a heat exchanger's ability to conduct heat between two fluids separated by a solid barrier. It encompasses all the resistance to heat flow, including the conductive resistance of the exchanger material and the convective resistances on both the hot and cold sides.

In the given problem, the radiator’s overall heat transfer coefficient and its surface area are bundled into a single term \(UA\), which represents the product of the coefficient \(U\) and the heat exchanger's surface area \(A_s\). The larger the \(UA\) value, the more efficient the heat exchanger is at transferring heat.

The exercise demonstrates the use of \(UA\) in calculating the NTU, as it directly influences the heat exchanger’s effectiveness. Understanding how the overall heat transfer coefficient interacts with other elements, such as the heat capacity rates of the fluids involved, is critical for designing and evaluating the performance of heat exchangers across a variety of applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There are two heat exchangers that can meet the heat transfer requirements of a facility. One is smaller and cheaper but requires a larger pump, while the other is larger and more expensive but has a smaller pressure drop and thus requires a smaller pump. Both heat exchangers have the same life expectancy and meet all other requirements. Explain which heat exchanger you would choose and under what conditions.

The condenser of a room air conditioner is designed to reject heat at a rate of \(15,000 \mathrm{~kJ} / \mathrm{h}\) from refrigerant-134a as the refrigerant is condensed at a temperature of \(40^{\circ} \mathrm{C}\). Air \(\left(c_{p}=1005 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) flows across the finned condenser coils, entering at \(25^{\circ} \mathrm{C}\) and leaving at \(35^{\circ} \mathrm{C}\). If the overall heat transfer coefficient based on the refrigerant side is \(150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the heat transfer area on the refrigerant side.

An air handler is a large unmixed heat exchanger used for comfort control in large buildings. In one such application, chilled water \(\left(c_{p}=4.2 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters an air handler at \(5^{\circ} \mathrm{C}\) and leaves at \(12^{\circ} \mathrm{C}\) with a flow rate of \(1000 \mathrm{~kg} / \mathrm{h}\). This cold water cools air \(\left(c_{p}=1.0 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\right)\) from \(25^{\circ} \mathrm{C}\) to \(15^{\circ} \mathrm{C}\). The rate of heat transfer between the two streams is (a) \(8.2 \mathrm{~kW}\) (b) \(23.7 \mathrm{~kW}\) (c) \(33.8 \mathrm{~kW}\) (d) \(44.8 \mathrm{~kW}\) (e) \(52.8 \mathrm{~kW}\)

Water \(\left(c_{p}=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right)\) enters the \(2.5\)-cm-internaldiameter tube of a double-pipe counter-flow heat exchanger at \(17^{\circ} \mathrm{C}\) at a rate of \(1.8 \mathrm{~kg} / \mathrm{s}\). Water is heated by steam condensing at \(120^{\circ} \mathrm{C}\left(h_{f g}=2203 \mathrm{~kJ} / \mathrm{kg}\right)\) in the shell. If the overall heat transfer coefficient of the heat exchanger is \(700 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), determine the length of the tube required in order to heat the water to \(80^{\circ} \mathrm{C}\) using ( \(a\) ) the LMTD method and \((b)\) the \(\varepsilon-\mathrm{NTU}\) method.

How is the NTU of a heat exchanger defined? What does it represent? Is a heat exchanger with a very large NTU \((\) say, 10\()\) necessarily a good one to buy?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free