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Saturated steam at 100C condenses on a 2-m ×2m plate that is tilted 40 from the vertical. The plate is maintained at 80C by cooling it from the other side. Determine (a) the average heat transfer coefficient over the entire plate and (b) the rate at which the condensate drips off the plate at the bottom. Assume wavy-laminar flow. Is this a good assumption?

Short Answer

Expert verified
(b) What is the determined rate at which the condensate drips off the plate per unit width, and is the wavy-laminar flow assumption reasonable? (a) The calculated average heat transfer coefficient is approximately 5651 W/(m²⋅K). (b) The determined rate at which the condensate drips off the plate per unit width is approximately 0.0054 m³/s, and the wavy-laminar flow assumption is reasonable.

Step by step solution

01

Find the properties of the saturated steam

At 100C, find the properties of saturated steam using a steam table or online resources. With this information, we can obtain the density (ρ), dynamic viscosity (μ), thermal conductivity (k), and latent heat of vaporization (L). For saturated steam at 100C, ρ=958 kg/m3 μ=2.82×104 kg/(ms) k=0.679 W/(mK) L=2.257×106 J/kg
02

Utilize the Nusselt equation for condensation on an inclined surface

To find the average heat transfer coefficient, we need to use the Nusselt equation for condensation on an inclined surface: Nu=hLk=(0.943)(gρ(ρρv)k3LμΔTsinθ)14 Where: h - average heat transfer coefficient Nu - Nusselt number L - plate length (in this case, 2 m) g - acceleration due to gravity, 9.81 m/s2 ρv- vapor density (obtained from the steam table at 100C, 0.6 kg/m3) ΔT - temperature difference between the saturated steam and the plate (100C80C=20C) θ - angle with the vertical, 40
03

Calculate the average heat transfer coefficient

By substituting our values into the Nusselt equation, we can now calculate h: h=0.679(0.943)(9.81958(9580.6)0.67932.257×1062.82×10420sin40)142 h5651 W/(m2K)
04

Calculate the flow rate of the condensate

Using Reynolds analogy, we can compute the flow rate of the condensate per unit width: RewL=ρ(ρρv)VwL2sinθ/μ Where: Rew - Reynolds number for wavy-laminar flow (from literature, Rew=1600) Vw - flow rate per unit width. Now we can solve for Vw: Vw=1600×2.82×104(958)(9580.6)(22)(sin40) Vw0.0054 m3/s The condensate drips off the plate at a rate of approximately 0.0054 m3/s per unit width.
05

Assess the wavy-laminar flow assumption

To check if the wavy-laminar flow assumption is reasonable, we need to compare the determined flow rate of the condensate (Vw) with the values from the literature regarding laminar and turbulent flow regimes. The given values for laminar flow are less than 30 cm/s, and turbulent flow is higher than 2 m/s. In this case, Vw5.4 cm/s, which lies within the laminar flow regime, indicating that the wavy-laminar flow assumption is reasonable. In conclusion: (a) The average heat transfer coefficient over the entire plate is approximately 5651 W/(m2K). (b) The rate at which the condensate drips off the plate is approximately 0.0054 m3/s per unit width, and the wavy-laminar flow assumption is reasonable.

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