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What is the physical mechanism of heat conduction in a solid, a liquid, and a gas?

Short Answer

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Question: Explain the physical mechanisms of heat conduction in solids, liquids, and gases. Answer: In solids, heat conduction occurs mainly through the vibration of atoms and molecules in the lattice structure, as well as through the movement of free electrons in metals. In liquids, heat conduction takes place through the movement of energetic particles over short distances, transferring energy through frequent collisions with neighboring particles. In gases, the mechanism is similar to liquids, with energy transfer occurring mainly through collisions between individual particles in random motion due to larger intermolecular distances.

Step by step solution

01

Heat Conduction in Solids

In solids, heat conduction occurs mainly through the vibration of atoms and molecules in the lattice structure. When one atom or molecule gains energy, it starts vibrating at a higher amplitude, eventually passing this energy to its neighbouring atoms. This process is called phonon-mediated heat conduction. In metals, heat conduction also occurs through the movement of free electrons. These electrons move from areas of high temperature to low temperature regions, transferring their kinetic energy and resulting in heat transfer.
02

Heat Conduction in Liquids

In liquids, heat conduction takes place mostly through the movement of energetic particles (atoms or molecules) over short distances. The particles in a liquid are less organized than in a solid, which means their vibrational energy is absorbed and re-emitted through frequent collisions with neighbouring particles. The energy is transferred in the form of microscopic random motion, as particles with higher kinetic energy collide and transfer it to neighbouring ones. This process of continuous collision and energy redistribution results in heat conduction.
03

Heat Conduction in Gases

In gases, the mechanism of heat conduction is quite similar to that in liquids. The key difference is that the particles in a gas are much farther apart than in liquids. Due to the large intermolecular distances, the transfer of energy occurs mainly through collisions between individual particles (atoms or molecules) that are in random motion. Faster-moving particles collide with slower-moving ones, transferring their kinetic energy in the process. As energy is transferred from one particle to another, we observe heat conduction in the gaseous medium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phonon-Mediated Heat Conduction
Understanding phonon-mediated heat conduction is essential to comprehend how heat travels through solids. Phonons are quanta of energy associated with the collective vibrations of atoms within a crystal lattice. Imagine a crowded stadium where a wave of motion passes from one person to the next; similarly, in solids, phonons transport thermal energy across the material.

When a segment of the solid lattice vibrates due to thermal energy, it triggers neighboring atoms to vibrate as well. This wave-like transfer of energy through the vibrations is the essence of phonon-mediated heat conduction. It's particularly significant in non-metallic solids, where free electrons are not available to transport heat. Faster vibrations mean higher temperatures, so when one end of a solid is heated, these vibrations (phonons) propagate towards the cooler end, distributing the thermal energy.
Heat Transfer in Solids
Heat transfer in solids not only involves phonon-mediated mechanisms but also, in the case of metals, involves free electrons. Metals have a sea of freely moving electrons that can carry energy across the material quickly and efficiently. This is why metals are known as good conductors of heat.

In a metal rod, for instance, heating one end will cause these free electrons to gain kinetic energy. They then zip through the solid, colliding with other electrons and atoms, passing along the thermal energy. This dual heat transfer mechanism, involving both lattice vibrations and free electrons, explains why metals have high thermal conductivity, allowing for swift and effective heat transmission from one point to another within the solid.
Thermal Conductivity in Liquids
When examining thermal conductivity in liquids, the situation changes as the organization of molecules within a liquid is less rigid compared to that in solids. The heat transfer mechanism in liquids relies on the movement and interaction of particles in a relatively disorganized environment. These particles have more freedom of movement than those in a solid, but are still close enough to significantly influence each other's motion.

As a liquid particle with higher energy collides with a neighbor, it shares part of its energy, making energetic particles less so and the less energetic ones more so. This redistribution of kinetic energy from one particle to another in a domino effect facilitates heat conduction through the liquid. While this is less efficient than heat conduction in solids, it's notably quicker than the heat conduction in gases due to the closer proximity of the liquid particles.
Heat Conduction in Gases
Moving on to heat conduction in gases, the process bears resemblance to that in liquids but operates over much larger intermolecular distances. Gases have particles that are much further apart compared to those in solids or liquids, resulting in less frequent but more dynamic particle collisions.

In a gas, a particle moving with high kinetic energy due to heat will occasionally collide with a slower particle. During this collision, energy is transferred to the slower particle, which, in turn, might collide with another, facilitating a chain of energy transfers. While this form of heat conduction is less efficient due to the sparsity of collisions, it still plays a critical role in the way gases heat and cool. Understanding this concept is particularly relevant for applications involving the heating and cooling of air and other gaseous substances.

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Most popular questions from this chapter

Conduct this experiment to determine the combined heat transfer coefficient between an incandescent lightbulb and the surrounding air and surfaces using a \(60-\mathrm{W}\) lightbulb. You will need a thermometer, which can be purchased in a hardware store, and a metal glue. You will also need a piece of string and a ruler to calculate the surface area of the lightbulb. First, measure the air temperature in the room, and then glue the tip of the thermocouple wire of the thermometer to the glass of the lightbulb. Turn the light on and wait until the temperature reading stabilizes. The temperature reading will give the surface temperature of the lightbulb. Assuming 10 percent of the rated power of the bulb is converted to light and is transmitted by the glass, calculate the heat transfer coefficient from Newton's law of cooling.

Write an essay on how microwave ovens work, and explain how they cook much faster than conventional ovens. Discuss whether conventional electric or microwave ovens consume more electricity for the same task.

While driving down a highway early in the evening, the air flow over an automobile establishes an overall heat transfer coefficient of \(18 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The passenger cabin of this automobile exposes \(9 \mathrm{~m}^{2}\) of surface to the moving ambient air. On a day when the ambient temperature is \(33^{\circ} \mathrm{C}\), how much cooling must the air conditioning system supply to maintain a temperature of \(20^{\circ} \mathrm{C}\) in the passenger cabin? (a) \(670 \mathrm{~W}\) (b) \(1284 \mathrm{~W}\) (c) \(2106 \mathrm{~W}\) (d) \(2565 \mathrm{~W}\) (e) \(3210 \mathrm{~W}\)

What is stratification? Is it likely to occur at places with low or high ceilings? How does it cause thermal discomfort for a room's occupants? How can stratification be prevented?

The north wall of an electrically heated home is 20 \(\mathrm{ft}\) long, \(10 \mathrm{ft}\) high, and \(1 \mathrm{ft}\) thick, and is made of brick whose thermal conductivity is \(k=0.42 \mathrm{Btu} / \mathrm{h} \cdot \mathrm{ft}{ }^{\circ} \mathrm{F}\). On a certain winter night, the temperatures of the inner and the outer surfaces of the wall are measured to be at about \(62^{\circ} \mathrm{F}\) and \(25^{\circ} \mathrm{F}\), respectively, for a period of \(8 \mathrm{~h}\). Determine \((a)\) the rate of heat loss through the wall that night and \((b)\) the cost of that heat loss to the home owner if the cost of electricity is \(\$ 0.07 / \mathrm{kWh}\).

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