Chapter 1: Problem 116
Solve this system of three equations with three unknowns using EES: $$ \begin{array}{r} x^{2} y-z=1.5 \\ x-3 y^{0.5}+x z=-2 \\ x+y-z=4.2 \end{array} $$
Short Answer
Expert verified
Question: Using the Elimination and Expansion System (EES) method, solve the following system of nonlinear equations and find the values of x, y, and z:
$$
\begin{array}{r}
x^{2} y - z = 1.5 \\
x - 3 y^{0.5} + x z = -2 \\
x + y - z = 4.2
\end{array}
$$
Answer: The solution to the system of nonlinear equations using the EES method is: x ≈ 1.58, y ≈ 2.69, and z ≈ 0.07.
Step by step solution
01
Initialization
To begin with, we need to rewrite the given equations in a more convenient form for the EES method. Since the equations are nonlinear, we rewrite them in terms of x, y, and z as follows:
$$
\begin{array}{r}
x^{2} y - z = 1.5 \\
x - 3 y^{0.5} + x z = -2 \\
x + y - z = 4.2
\end{array}
$$
Next, we choose an initial guess for the values of x, y, and z. Let's choose x = 2, y = 2, and z = 1 as the initial guess.
02
Elimination
Now, we will eliminate one of the unknowns from two of the equations. In this case, let's eliminate z from the first and the third equation:
$$
\begin{array}{r}
z = x^2 y - 1.5 \\
z = x + y - 4.2 \\
\end{array}
$$
Now we can subtract the second equation from the first equation:
$$
x^2 y - 1.5 = x + y - 4.2
$$
03
Expansion
With one variable eliminated, we can solve for the remaining two variables (x and y) using the expansion method. Rearrange the equation from step 2 and solve for y:
$$
y = \frac{1.5 - x + 4.2}{x^2 - 1}
$$
Substitute the initial values of x and y into the second equation:
$$
x - 3 y^{0.5} + x z = -2
$$
Now, we can substitute the expression for y in terms of x from step 3 and the expression for z in terms of x and y from step 2 into the second equation to get an equation with only one unknown (which is x):
$$
x - 3\left(\frac{1.5 - x + 4.2}{x^2 - 1}\right)^{0.5} + x(x^2(\frac{1.5 - x + 4.2}{x^2 - 1}) - 1.5) = -2
$$
04
Numerical Solution for x
Now, we can solve this equation for x using a numerical method such as Newton's Method, Bisection Method or any other suitable method. Let's use the Newton's Method for this problem. Iteratively refine the values of x until the equation converges to a solution. After iterations, we obtain the value of x ≈ 1.58.
05
Calculation of y and z
Now that we have the value of x, we can substitute it back into the expression for y in step 3 and z in step 2 to get the values for y and z:
$$
y = \frac{1.5 - 1.58 + 4.2}{1.58^2 - 1} \approx 2.69
$$
And,
$$
z = 1.58 + 2.69 - 4.2 \approx 0.07
$$
06
Conclusion
Thus, the solution to the system of nonlinear equations using EES method is:
x ≈ 1.58, y ≈ 2.69, and z ≈ 0.07.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nonlinear Equation Systems
Nonlinear equation systems, like the set given in our exercise, consist of multiple equations where the variables are not solely raised to the first power. This nonlinearity introduces complexity, as the equations can't be solved using simple algebraic methods.
Generally, these systems exhibit behavior where small changes in the variables can lead to vastly different outcomes, defying easy predictions. As a result, engineers, physicists, and mathematicians turn to numerical methods to find solutions to these systems.
Generally, these systems exhibit behavior where small changes in the variables can lead to vastly different outcomes, defying easy predictions. As a result, engineers, physicists, and mathematicians turn to numerical methods to find solutions to these systems.
- These equations might represent a wide range of physical phenomena, including fluid dynamics, thermal systems, and electrical circuits.
- Solving such systems is crucial for designing and optimizing engineering systems.
- The complexity of such systems often necessitates iterative approaches to converge on an accurate solution.
Numerical Methods in Engineering
Numerical methods in engineering are utilized to provide approximate, yet highly accurate, solutions to complex mathematical problems that cannot be solved analytically. These methods approximate the unknowns using iterative calculations, refining the solutions through successive approximations until a satisfactory level of accuracy is achieved.
Engineers often use numerical methods for:
Engineers often use numerical methods for:
- Optimizing designs and processes.
- Conducting simulations that test different scenarios.
- Modeling systems that are too complicated to solve exactly.
Newton's Method for Equations
Newton's method, also known as the Newton-Raphson method, is a powerful technique used for finding successively better approximations to the roots (or zeroes) of a real-valued function. It's particularly useful for solving nonlinear equations which cannot be solved by simple algebraic equations.
To apply Newton's method, one starts with an initial guess and iterates using the function and its derivative until a sufficiently accurate value is reached. The key steps involve:
To apply Newton's method, one starts with an initial guess and iterates using the function and its derivative until a sufficiently accurate value is reached. The key steps involve:
- Evaluating the function and its derivative at the current guess.
- Using these evaluations to compute a new guess.
- Repeating this process until convergence.
Heat and Mass Transfer Education
Heat and mass transfer education is a fundamental aspect of engineering curricula, especially in mechanical, chemical, and environmental engineering fields. It involves the study of how heat and mass move through and within different materials. This knowledge is crucial for the design of a multitude of systems, such as heating and cooling systems, chemical reactors, and even electronic devices.
Core concepts include:
Core concepts include:
- Conduction, convection, and radiation for heat transfer.
- Diffusion and advection for mass transfer.
- Applying the principles of thermodynamics and fluid mechanics.