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Solve this system of three equations with three unknowns using EES: 2xy+z=53x2+2y=z+2xy+2z=8

Short Answer

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Question: Using the Elimination by Substitution method, solve the following system of equations: 1. 2x - y + z = 5 2. 3x^2 + 2y = z + 2 3. xy + 2z = 8 Please provide your solution in terms of x, y, and z.

Step by step solution

01

Isolate a variable from one of the equations

We will choose the first equation because it is the simplest. We can isolate 'x' by adding 'y' and subtracting 'z', then dividing by 2: x=yz+52
02

Substitute the isolated variable into the other two equations

Substitute the expression for x in equations 2 and 3: 3(yz+52)2+2y=z+2 (yz+52)y+2z=8
03

Solve the system of two equations with two unknowns

We have the following system of equations: 3(yz+52)2+2y=z+2(yz+52)y+2z=8 After solving this system, we find that: y=1z=3
04

Back-substitute and find the value of the third variable

Now that we have the values of y and z, we can substitute them back into the expression we found for x in Step 1: x=yz+52=13+52=32 So, x=32
05

Verify that the solution satisfies all three equations

We can now check that the solutions we found, x=32,y=1, and z=3, satisfy all three original equations: 2(32)1+3=53(32)2+2(1)=3+2(1)(32)+2(3)=8 All three equations are satisfied, which confirms that our solution is valid: x=32,y=1,z=3

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equation Solving
Solving an equation involves finding the values of variables that make an equation true. In a system of equations like the one given, we not only have to solve one equation but multiple equations together. Each equation shares some or all of the variables, and they must all be satisfied simultaneously. This is why we call it a 'system of equations.' Moreover, solutions to these systems can be approached using various methods including graphical methods, substitution methods, or elimination methods. The key is finding the intersection, or the common solution, that satisfies all the given equations.

The process requires systematic steps to ensure consistency in finding the correct values for each unknown. Each method employed has its own set of techniques that focus on logical manipulation to isolate and determine the values of variables.
Isolating Variables
Isolating a variable means expressing that variable in terms of other variables and constant numbers, ideally making it the subject of an equation. In our exercise, we see this in the first step. By starting with the simplest equation, the task was to isolate 'x.' By rearranging the equation to express 'x' on one side, it helps simplify the process of solving, especially when using methods like substitution.

This technique is crucial because it allows us to manipulate the equation to facilitate easier substitution into other equations in the system. Think of it like turning a locked door key: once the key fits or the variable is isolated, it opens up the way to solving the rest of the equations.
Substitution Method
The substitution method is a strategic approach to solving systems of equations. Once one variable is isolated, it can be substituted back into the other equations in the system, simplifying them further. From our exercise, by isolating 'x,' we substitute the expression of 'x' into the remaining equations to form new equations solely with the other variables.

This method is particularly useful when dealing with non-linear or complex systems because it allows reduction in the number of variables in each equation, hence making them simpler to solve. Moreover, substitution is a step-by-step process, ensuring each equation's variable count is reduced incrementally until they can be solved with basic algebra.
Algebraic Manipulation
Algebraic manipulation is the backbone of solving systems of equations. This involves applying mathematical operations such as addition, subtraction, multiplication, division, and squaring, as necessary, to simplify equations and solve for variables. In our exercise, we engage in manipulation through expanding expressions, simplifying fractions, and transforming equations to fit our needs during substitution and solving.

These manipulations reveal relationships between variables and help break down a complex system into more manageable parts. Mastering algebraic manipulation is essential because it encompasses more than just numbers and can transform an equation's form without destroying its fundamental integrity. It's like painting a picture: the outlining, shading, and detailing that bring clarity to a confusing canvas.

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Most popular questions from this chapter

Conduct this experiment to determine the combined heat transfer coefficient between an incandescent lightbulb and the surrounding air and surfaces using a 60W lightbulb. You will need a thermometer, which can be purchased in a hardware store, and a metal glue. You will also need a piece of string and a ruler to calculate the surface area of the lightbulb. First, measure the air temperature in the room, and then glue the tip of the thermocouple wire of the thermometer to the glass of the lightbulb. Turn the light on and wait until the temperature reading stabilizes. The temperature reading will give the surface temperature of the lightbulb. Assuming 10 percent of the rated power of the bulb is converted to light and is transmitted by the glass, calculate the heat transfer coefficient from Newton's law of cooling.

A 2-kW electric resistance heater submerged in 30-kg water is turned on and kept on for 10 min. During the process, 500 kJ of heat is lost from the water. The temperature rise of water is (a) 5.6C (b) 9.6C (c) 13.6C (d) 23.3C (e) 42.5C

Can a medium involve (a) conduction and convection, (b) conduction and radiation, or (c) convection and radiation simultaneously? Give examples for the "yes" answers.

How does forced convection differ from natural convection?

A series of experiments were conducted by passing 40C air over a long 25 mm diameter cylinder with an embedded electrical heater. The objective of these experiments was to determine the power per unit length required (W˙/L) to maintain the surface temperature of the cylinder at 300C for different air velocities (V). The results of these experiments are given in the following table: V( m/s)124812W˙/L( W/m)45065898315071963 (a) Assuming a uniform temperature over the cylinder, negligible radiation between the cylinder surface and surroundings, and steady state conditions, determine the convection heat transfer coefficient (h) for each velocity (V). Plot the results in terms of h( W/m2K) vs. V( m/s). Provide a computer generated graph for the display of your results and tabulate the data used for the graph. (b) Assume that the heat transfer coefficient and velocity can be expressed in the form of h=CVm. Determine the values of the constants C and n from the results of part (a) by plotting h vs. V on log-log coordinates and choosing a C value that assures a match at V=1 m/s and then varying n to get the best fit.

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