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A sinusoidal transverse wave traveling in the negative direction of anaxis has amplitude of 1.00 cm, a frequency of 550 Hz, and a speed of 330 m/s. If the wave equation is of the formy(x,t)=ymsin(kx±ωt), What are (a)ym, (b)ω, (c)k, and (d) the correct choice of sign in front ofω?

Short Answer

Expert verified
  1. Value of ymis 1.00 cm
  2. Value of ωis3.46×103rad/sec
  3. Value ofkis10.5rad/m
  4. Sign of ω is plus.

Step by step solution

01

Given data 

Amplitude of the wave,ym=1.00cm

Frequency of the wave,f=550Hz

Speed of the wave,v=330m/s

02

Understanding the concept of transverse wave

We have to compare the given values with the general equation of the wave.

Formula:

The general equation of wave, yx,t=ymsinkx-ωt........1

The angular frequency of the wave, ω=2πf.........2

The wavenumber of the wave, k=ωv........3

03

Step 3(a): Calculation of ym

Comparing with the wave equation (1), it can be seen that hereymis amplitude of the wave.

So value of ymis1.00cm

04

Step 4(b): Calculation of ω

The frequency is given, so the angular frequency using equation (2) is given as follows:

ω=2×π×550=3.46×103rad/sec

Hence, the value ofω is3.46×103rad/sec

05

Step 5(c): Calculation of k

The velocity of a wave is given and hence, using equation (3), we get the wavenumber as follows:

k=3.46×103330=10.5rad/m

Hence, the value ofk is10.5rad/m

06

Step 6(d): Finding the correct sign of ω

Comparing with general equation (1), it can be seen that the sign to angular frequency must be plus since the wave is travelling in the negative direction.

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