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The amplitudes and phase differences for four pairs of waves of equal wavelengths are (a) 2 mm, 6 mm, and πrad, (b) 3 mm, 5 mm, andrad (c) 7 mm, 9 mm, and (d) 2 mm, 2 mm, and 0 rad. Each pair travels in the same direction along the same string. Without written calculation, rank the four pairs according to the amplitude of their resultant wave, greatest first.

(Hint:Construct phasor diagrams.)

Short Answer

Expert verified

The four pairs can be ranked according to the amplitude of their resultant wave, taking the greatest first as,ya=yd>yb=yc

Step by step solution

01

Given

2 mm, 6mm and ττrad

3 mm, 5mm and ττrad

2 mm, 2mm and 0rad

Hint: Construct a phasor diagram.

02

Determining the concept

Use the concept of phasors and draw the circuit diagram.

Formulae are as follow:

ym=ym1+ym2

Where, y is vector.

03

Determining the rank the four pairs according to the amplitude of their resultant wave, taking the greatest first.

a) The amplitude of their resultant wave:

ym1=2mm,ym2=6mmand=ττrad

Draw the phasor diagram for the given amplitudes by using a vector diagram.

b) The amplitude of their resultant wave:

ym1=3mm,ym2=5mmand=ττrad

Draw the phasor diagram for the given amplitudes by using a vector diagram.

c) The amplitude of their resultant wave:

ym1=7mm,ym2=9mmand=ττrad

Draw the phasor diagram for the given amplitudes by using a vector diagram.

d) The amplitude of their resultant wave:

Draw the phasor diagram for the given amplitudes, by using a vector diagram.

Therefore, from the phasor diagram, rank of the four pairs according to the amplitude of their resultant wave, taking the greatest first is,

ya=yd>yb=yc

Therefore construct the phasor diagram by using the vector diagram concept. find their resultant wave by using vector addition law and rank them, taking the greatest first.

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