Question

It is possible to melt ice by rubbing one block of it against another. How much work, in joules, would you have to do to get$\mathbf{1}\mathbf{.00}\mathbf{}\mathbf{\text{g}}$of ice to melt?

Short answer

The work to be done to melt $1.0\text{g}$of ice is$333\text{J}$.

Step-by-step solution

Identification of given data

a) Mass of the ice,$m=1.0\text{g}$

b) Latent heat of fusion,.$L=333\frac{\text{KJ}}{\text{kg}}\text{or}333\frac{\text{J}}{\text{g}}$

Understanding the concept of work 

The work done on the ice by rubbing is given by the amount of heat released by the body due to the melting of the ice, Thus, the heat is defined by the latent heat of the ice with the amount of ice melting. Using the equation for the latent heat of fusion, we can find the work required to melt ice.

Formula:

Heat transferred by the body due to thermal expansion,$Q=L_{f}m$…(i)

where$L_f$ is the latent heat of fusion and$m$ is the mass of the substance.

Determining the work to melt ice

Using equation (i), we can get the required work in the form of heat to melt the given amount of ice as

$\begin{array}{c}Q=333\text{J/g}\times 1.0\text{g}\\ =333\text{J}\end{array}$

Hence, the value of the required work is $333\text{J}$.