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The ceiling of a single-family dwelling in a cold climate should have an R-value of30.To give such insulation, (a) how thick would a layer of polyurethane foam and (b) how thick would a layer of silver have to be?

Short Answer

Expert verified
  1. The layer of polyurethane foam is0.13m
  2. The layer of silver have to be2.3×103m

Step by step solution

01

The given data

  1. R value of the ceilingR=30
  2. Thermal conductivity of polyurethane foamkp=0.024 W/m.K
  3. Thermal conductivity of silverks=428 W/m.K
02

Understanding the concept of thermal radiation

Thermal radiation is the process of transferring heat through electromagnetic radiation that is produced by the thermal motion of matter particles. We use the concept of thermal resistance to conduction. The lower the thermal conductivity of the material; then the higher is the R-value. So, something that has a higher R-value is a poor thermal conductor and thus a good thermal insulator.

Formula:

The thickness of the layer, L=kR …(i)

03

(a) Calculation of the thickness of layer of polyurethane foam

The thickness of the layer of polyurethane foam using equation (i) is given as:

Lp=(0.024 W/m.K)(30 ft2.F°.h/Btu)(1 m/3.281 ft)2(3600s/h)(5°C/9)(1 Btu/1055J)=0.13m

Hence, the thickness of the layer of polyurethane is0.13m

04

(b) Calculation of the thickness of layer of silver

Using equation (i), the thickness of the silver layer with respect to the polyurethane foam is given as:

Ls=ksRskpRp.Lp=428 W/m.K×300.024 W/m.K×30×0.13 m=2.3×103m

Hence, the thickness of the layer is2.3×103m

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