Question

Which hadron in Tables 44-3 and 44-4 corresponds to the quark bundles (a) ssu and (b) the dds?

Short answer

(a) The quark bundle of $ssu$is${\Omega }^o$ (omega) hadrons.

(b) The quarks bundle $dds$is in Sigma hadrons.

Step-by-step solution

(a) Hadron corresponds to the quark bundles ssu. 

The quark bundle .$ssu$

The total charge is calculated as,

$\begin{array}{c}Q=(-\frac{1}{3})+(-\frac{1}{3})+\left(\frac{2}{3}\right)\\ =0\end{array}$

Total strangeness

$\begin{array}{c}s=(-1)+(-1)+0\\ =-2\end{array}$

Here the charge and strangeness coincides with the $E^o$baryon.

Hence the quark bundle of$ssu$ is ${\Omega }^o$(omega) hadrons.

(b) Hadron corresponds to the quark bundles dds. 

The given quark$dds$ is of Baryons families. As the baryons made of an odd number of quarks i.e, usually three quarks.

The quarks bundle$dds$ is Sigma.

Hence, the quarks bundle$dds$ is in Sigma hadrons.