Question

From tables 44-3 and 44-5, determine the identity of the baryon formed from quarks (a),$\mathit{d}\mathit{d}\mathit{u}$(b),$\mathit{u}\mathit{u}\mathit{s}$and (c)$\mathit{s}\mathit{s}\mathit{d}$.Check your answers against the baryon octet shown in Fig 44-3a.

Short answer

(a) The Baryon formed from the quark$uus$ is proton.$\left(p\right)$

(b) The Baryon formed from the quark $uus$is proton.$\left(p\right)$

(c) The Baryon formed from the quark$ssd$ is.${?}^{-}$

Step-by-step solution

(a) Determine the identity of the baryon formed from quarks ddu.

The quark bundle

The total charge is calculated as,

$\begin{array}{c}Q=(-\frac{1}{3})+(-\frac{1}{3})+\left(\frac{2}{3}\right)\\ =0\end{array}$

Total strangeness; $S=0$

Here charge and strangeness coincides with the neutron.

Hence, the Baryon formed from the quark$ddu$ as neutron .$\left(n\right)$

(b) Determine the identity of the baryon formed from quarks uus.

The quark bundle

The total charge is calculated as,

$\begin{array}{c}Q=\left(\frac{2}{3}\right)+\left(\frac{2}{3}\right)+(-\frac{1}{3})\\ =1\end{array}$

Total strangeness;

$\begin{array}{c}S=0+0-1\\ =-1\end{array}$

Here charge and strangeness coincides with the ${\sum }^{+}$particle.

Hence, the Baryon formed from the quark$uus$ is proton .$\left(p\right)$

(c) The identity of the baryon formed from quarks ssd.

The quark bundle $ssd$

The total charge is calculated as,

$\begin{array}{c}Q=(-\frac{1}{3})+(-\frac{1}{3})+(-\frac{1}{3})\\ =-1\end{array}$

Total strangeness;

$\begin{array}{c}S=-1+(-1)+0\\ =-2\end{array}$

Here charge and strangeness coincides with the${\sum }^{+}$ particle.

Hence, the Baryon formed from the quark$ssd$ is.${?}^{-}$