Question

A positively charged pion decays by Eq. 44-7 : ${\mathit{\pi }}^{\mathbf{+}}\mathbf{\to }{\mathit{\mu }}^{\mathbf{+}}\mathbf{+}\mathit{\nu }$

What must be the decay scheme of the negatively charged pion?

(Hint:The $\mathit{\pi }$ is the antiparticle of the ${\mathit{\pi }}^{\mathbf{+}}$)

Short answer

The decay schemeof the negatively charged pion is.

${\pi }^{-}\to {\mu }^{-}+\nu$

Step-by-step solution

Conservation of charge

Conservation of Charge

According to the conservation of charge, the net electric charge or total charge of any isolated system is always conserved.

Finding which conservation law would be violated.

The decay scheme of pion is given as.

${\pi }^{+}\to {\mu }^{+}+\nu$

From the conservation of charge, we know that by reversing the sign of the pion means we must reverse the sign of the muon.

Since we are replacing the charged particles with their antiparticles so the decay schemeof the negatively charged pion is

${\pi }^{-}\to {\mu }^{-}+\nu$