Question

A small ball rolls horizontally off the edge of a tabletop that is${}^{\mathbf{1}\mathbf{.}\mathbf{20}\mathbf{}\mathbf{m}}$ high. It strikes the floor at a point${}^{\mathbf{1}\mathbf{.}\mathbf{52}\mathbf{}\mathbf{m}}$ horizontally from the table edge. (a)How long is the ball in the air? (b)What is its speed at the instant it leaves the table?

Short answer

(a) Time of flight of the ball is${}^{0.495s}$

(b) Speed of the ball at the instant it leaves the table is${}^{3.07m/s}$

Step-by-step solution

Given information

The height of the table top is${}^{y=1.20m}$and the distance between the table edge and floor is${}^{x=1.52m}$

To understand the concept of kinematic equation

This problem is based on kinematic equations that describe the motion of an object with constant acceleration. Using these kinematic equations, the range of the object and the time for which object is in the air can be found.

Formula:

The displacement in kinematic equation can be written as,

(a) to find the time of the flight

Vertical height of the table top is givenby

Therefore, time of flight of the ball is${}^{\mathbf{0}\mathbf{.}\mathbf{495}\mathbf{}\mathbf{s}}$

(b) to find the distance between the table edge and floor

It is given that,