Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Question:A car moves uphill at 40 km/hand then back downhill at 60 km/h. What is the average speed for the round trip?

Short Answer

Expert verified

Answer

The average speed for the round trip is 48 km/h

Step by step solution

01

Given data

Speed of the car when moving uphill,s1 =40 km/h

Speed of the car when moving downhill, s2=60 km/h

02

Understanding the average speed

Average speed can be found by dividing the total distance traveled by the total time taken.

The expression for the average speed is as follows:

savg=totaldistancetotaltime

03

Determination of the average speed

Let the distance covered uphill be x, and the distance covered downhill be x.

The total time taken for the round trip is calculated as follows:

t=xs1+xs2

The total distance covered for the round tripis as follows:

Total distance = x+x =2x

The average speed of the car is calculated as follows:

Savg=Totaldistancet=2xxs1+xs2=2xxs1+s2s1s2=2s1s2s1+s2

Substitute the values in the above expression.

SAvg=2×40km/h×60km/h40km/h+60km/h=48km/h

Therefore, the average speed of the car for the round trip is 48 km/h.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A salamander of the genus Hydromantes captures prey by launching its tongue as a projectile. The skeletal part of the tongue is shot forward, unfolding the rest of the tongue, until the outer portion lands on the prey, sticking to it. Figure 2-39 shows the acceleration magnitude a versus time t for the acceleration phase of the launch in a typical situation. The indicated accelerations are a2=400m/s2anda1=100m/s2. What is the outward speed of the tongue at the end of the acceleration phase?

A ball is thrown down vertically with an initial speed of from a height of . (a) What is its speed just before it strikes the ground? (b) How long does the ball take to reach the ground? What would be the answers to (c) part a and (d) part b if the ball were thrown upward from the same height and with the same initial speed? Before solving any equations, decide whether the answers to (c) and (d) should be greater than, less than, or the same as in (a) and (b).

Question: A proton moves along theaxis according to the equation x = 50t + 10t2 , where xis in meters and tis in seconds. Calculate (a) the average velocity of the proton during the first 3.0 sof its motion, (b) the instantaneous velocity of the proton at t = 3.0 s, and (c) the instantaneous acceleration of the proton at t = 3.0 s . (d) Graph xversus tand indicate how the answer to (a) can be obtained from the plot. (e) Indicate the answer to (b) on the graph. (f) Plotvversus tand indicate on it the answer to (c).

Question: If a baseball pitcher throws a fastball at a horizontal speed of 160 Km/hr,how long does the ball take to reach homeplate 18.4 maway?

As a runaway scientific balloon ascends at 19.6 m/s, one of its instrument packages breaks free of a harness and free falls. Figure 2-34 gives the vertical velocity of the package versus time, from before it breaks free to when it reaches the ground. (a) What maximum height above the breakpoint does it rise? (b) How high is the break-free point above the ground?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free