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A magnetic flux of7.0mWb is directed outward through the flat bottom face of the closed surface shown in Fig. 32-40. Along the flat top face (which has a radius of4.2cm ) there is a 0.40Tmagnetic field directed perpendicular to the face. What are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface?

Short Answer

Expert verified
  1. The magnitude of the magnetic flux is 9.2×10-3Wb.
  2. The direction of the flux is inward.

Step by step solution

01

Listing the given quantities

Magnetic field is0.40T

Radius of top face is

r=4.2cm=4.2×10-2m

02

Understanding the concepts of magnetic field

Here, we have to use the formula for the magnetic flux in terms of the magnetic field and area. As the total flux passing inward for any closed surface is equal to the total flux going out. we can find the flux through the curved surface.

Formula:

A=πr2

ϕ=BA

03

(a) Calculations of the magnitude of the magnetic flux.

The magnitude of the magnetic flux.

The area of the top face is as follow:

A=πr2=π(4.2×102)2

So, the flux passing through the top surface is

ϕtop=BA=0.4×π×(4.2×102)2=2.125×10-3Wb

So, the net flux inside the surface is

ϕ=ϕbottom+ϕtop=7.0×103+2.125×103=9.21×10-3Wb

Now, the total inward flux is equal to the total outward flux

ϕin=ϕout

Hence, the magnitude of the magnetic flux through the curved surface is

ϕ=9.21×10-3Wb

04

(b) Explanation of the direction of the flux

The direction of the flux.

As the flux is going out through both the top and the bottom flat surfaces, the direction of the flux through the curved surface must be inward.

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