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In Fig. 29-40, two semicircular arcs have radii R2=7.80cmand R1=3.15cmcarry current i=0.281A and have the same center of curvature C. What are the (a) magnitude and (b) direction (into or out of the page) of the net magnetic field at C?

Short Answer

Expert verified
  1. The value of the magnetic field is B=1.67×10-6T.
  2. The direction of the magnetic field is into the page.

Step by step solution

01

Given

  1. Radius isR2=7.80cm
  2. Radius isR1=3.15cm
  3. Current isi=0.281A
  4. Figure 29-40 is two semi-circular arcs.
02

Determine the concept

Use the concept of magnetic field at the center of circular arc. Using the equation, find the magnetic field at the given point. Using right hand rule determine the direction of the magnetic field.

Formulae:
B=μ04πR

03

(a) Calculate the magnitude of the net magnetic field at C

The magnitude of the magnetic field at point C:

The magnetic fields due to both arcs are opposite due to opposite direction of currents.

The total magnetic field will be the vector addition of both. So,

μ0iϕ4πR1-μ0iϕ4πR2

Substitute the values and solve further as:

B=μ0iϕ4π1R1-1R2

The angle isϕ=π

B=4π×10-7iπ4π1R1-1R2B=iπ×10-71R1-1R2

.

Substitute the values and solve:

role="math" localid="1663096149133" B=0.281A3.14×10-710.0315m-10.0780mB=1.67×10-6T

Hence the magnetic field is, 1.67×10-6T.

04

(b) Calculate the direction (into or out of the page) of the net magnetic field at C

Direction of the magnetic field at point C:

By using the right hand rule, we can get the direction of the magnetic field which is into the page.

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