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Figure 29-81 shows a wire segment of length Δs=3cm, centered at the origin, carrying current i=2A in the positive ydirection (as part of some complete circuit). To calculate the magnitude of the magnetic field produced by the segment at a point several meters from the origin, we can use B=μ04πiΔs×r^r2 as the Biot–Savart law. This is because r and u are essentially constant over the segment. Calculate (in unit-vector notation) at the(x,y,z)coordinates (a)localid="1663057128028" (0,0,5m)(b)localid="1663057196663" (0,6m,0)(c) localid="1663057223833" (7m,7m,0)and (d)(-3m,-4m,0)

Short Answer

Expert verified
  1. The magnetic field at the point (0,0,5m)is2.4×10-10Ti^.
  2. The magnetic field at the point (0,6m,0)islocalid="1663057848212" 0
  3. The magnetic field at the point (7m,7m,0)is localid="1663061887434" -4.3×101Tk^
  4. The magnetic field at the point (-3m,-4m,0)is1.44×10-10Tk^.

Step by step solution

01

Identification of given data

  1. Length segments=3cm
  2. Current i=2A
02

Understanding the concept of Biot-Savart law

An equation known as the Biot-Savart Law describes the magnetic field produced by a steady electric current. It connects the electric current's strength, direction, length, and proximity to the magnetic field.

Formula:

B=μ04πiS×rr3

03

Calculate (in unit-vector notation) at the (x,y,z)   coordinates (a) (0, 0, 5 m)

In the figure, the co-ordinate axis is the center of the cylinder. By symmetry, we will get the same value of magnetic field if we take the cross-sectional area of the left or right side of the cylinder. We take the right side cross-sectional area of the cylinder.

Biot- Savart law can be written as-

B=μ04πiΔs×r^r2=μ04πiΔs×rr3

Δs=Δsj^

r=xi^+yj^+zk^

Δs×r=Δsj^×xi^+yj^+zk^

i^×j^=k^,j^×i^=-k^,j^×k^=i^,j^×j^=0

Δs×r=Δszi^-xk^

B=μ04πiΔszi^-xk^(x2+y2+z2)32

04

(a) Determining the magnetic field in the vector notation at (0, 0, 5 m) coordinates.

The magnetic field at the point: 0,0,5m

Herex=0,y=0,z=5m

Substituting in 1) we get,

B=4π×10-7T.m/A2A3×10-2m5i^-0k^m4π(02+02+5m2)32B=2.4×10-10Ti^

05

(b) Determining the magnetic field in the vector notation at (0, 6 m, 0) coordinates

The magnetic field at the point: 0,6m,0

Here x=0,y=6m,z=0

B=4π×10-7T.m/A2A3×10-2m0i^-0k^m4π(02+62+02)32m3B=0

06

(c) Determining the magnetic field in the vector notation at (7 m, 7 m, 0) coordinates.

The magnetic field at the point 7m,7m,0:

Herelocalid="1663061755332" x=7m,y=7m,z=0

localid="1663060711200" B=4π×10-7T.m/A2A3×10-2m0i^-7k^m4π(72+72+02)32m3B=-4.3×10-11Tk^

07

(d) Determining the magnetic field in the vector notation at  coordinates  (-3 m, -4 m, 0 ). 

The magnetic field at the point -3m,-4m,0:

Here , x=-3m,y=-4m,z=0

B=4π×10-7T.m/A2A3×10-2m0i^+3k^m4π[-32+-42+02)]32m3B=1.44×10-10Tk^

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