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Question: In Fig 29-55, two long straight wires (shown in cross section) carry currentsi1=30.0mAandi1=40.0mAdirectly out of the page. They are equal distances from the origin, where they set up a magnetic field. To what value must current i1be changed in order to rotate20.0°clockwise?

Short Answer

Expert verified

The value of current i1 is i1=61.3mA.

Step by step solution

01

Given

i) Currents flowing through the two long straight wires are i1=30.0mAand i2=40.0mA

ii) The rotation of net magnetic field Bisθ=20.0°.

02

Determine the formula for the magnetic field as:

Use the concept of the magnetic force due to current in straight wires and trigonometry.

Formulae:

Bstraight=μ0i4πR

tanθ=ByBx

03

Calculate the value to which current i1 must be changed in order to rotate 20.0° clockwise

The value of current i1:

The magnetic field due to a current in straight wire is

Bstraight=μ0i4πR

The distances of the B1and B2are the same; hence they are directly proportional localid="1663143974221" i1and i2respectively.

B1αi1and

B2αi2

According to the right hand rule,is going to the y axis andis going along x axis.

The angle of the net field is

tanθ=ByBx

tanθ=B2B1

θ=tan-1i2i1

Substitute the values and solve as:

θ=tan-140.0mA30.0mA

θ=53.13°

In the problem, the net field rotation is

θ'=θ-20.0°

θ'=53.13°-20.0°

θ'=33.13°

The final value of the current is:

tanθ'=i2i1

i1=i2tanθ'

Substitute the values and solve as:

i1=40.0mAtan33.13°

i1=61.3mA

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