Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The speed of yellow Light (from a sodium lamp) in a certain liquid is measured to be1.92×108ms . What is the index of refraction of this liquid for the Light?

Short Answer

Expert verified

The index of refraction of the liquid is1.56

Step by step solution

01

Definition of Light

Light is an electromagnetic wave that, when it falls on an object, comes visible to the human eye, light transmits spatial and temporal information used in the optics field.

02

Determination of the index of refraction of the liquid

The formula for calculating the refractive index are:

n=cv

Here, c is the speed of Light in a vacuum, and v is the speed of Light in the given medium.

Therefore, the refractive index of the liquid is:

n=3×108ms1.92×108ms=1.56

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Fig. 35-34, a light ray is an incident at angle θ1=50°on a series of five transparent layers with parallel boundaries. For layers 1 and 3 , L1=20μm , L2=25μm, n1=1.6and n3=1.45. (a) At what angle does the light emerge back into air at the right? (b) How much time does the light take to travel through layer 3?

The figure shows the design of a Texas arcade game, Four laser pistols are pointed toward the center of an array of plastic layers where a clay armadillo is the target. The indexes of refraction of the layers are n1=1.55,n2=1.70,n3=1.45,n4=1.60,n5=1.45,n6=1.61,n7=1.59,n8=1.70and n9=1.60. The layer thicknesses are either 2.00 mm or 4.00 mm, as drawn. What is the travel time through the layers for the laser burst from (a) pistol 1, (b) pistol 2, (c) pistol 3, and (d) pistol 4? (e) If the pistols are fired simultaneously, which laser burst hits the target first?

In Fig. 35-31, a light wave along ray r1reflects once from a mirror and a light wave along ray r2reflects twice from that same mirror and once from a tiny mirror at distance Lfrom the bigger mirror. (Neglect the slight tilt of the rays.) The waves have wavelength 620 nm and are initially in phase. (a) What is the smallest value of Lthat puts the final light waves exactly out of phase? (b) With the tiny mirror initially at that value of L, how far must it be moved away from the bigger mirror to again put the final waves out of phase?

Figure 35-40 shows two isotropic point sources of light (S1and S2) that emit in phase at wavelength 400 nm and at the same amplitude. A detection point P is shown on an x-axis that extends through source S1. The phase difference ϕbetween the light arriving at point P from the two sources is to be measured as P is moved along the x axis from x=0 out to x=+.The results out to xs=10×10-7m are given in Fig. 35-41. On the way out to + , what is the greatest value of x at which the light arriving at from S1is exactly out of phase with the light arriving at P from S2?

Figure 35-24a gives intensity lversus position x on the viewing screen for the central portion of a two-slit interference pattern. The other parts of the figure give phasor diagrams for the electric field components of the waves arriving at the screen from the two slits (as in Fig. 35-13a).Which numbered points on the screen bestcorrespond to which phasor diagram?

(a) Figure 1

(b) Figure 2

(c) Figure 3

(d) Figure 4

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free