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Monochromatic green light, of wavelength 500 nm, illuminates two parallel narrow slits 7.70 mm apart. Calculate the angular deviation ( θin Fig. 35-10) of the third-order (m=3)bright fringe (a) in radians and (b) in degrees.

Short Answer

Expert verified

a. The angular separation in radian is 0.214rad.

b. The angular separation in degrees is 12.28°.

Step by step solution

01

Write the given data from the question

The wavelength, λ=550nm.

The order of the bright fringe, m=3.

The distance between the slits, d=7.7μm.

02

Determine the formulas to calculate the angular separation in the degrees and radian

Young's double-slit experiment. When monochromatic light passing through two narrow slits illuminates a distant screen, a characteristic pattern of bright and dark stripes is observed. This interference pattern is caused by the superposition of overlapping light waves originating from the two slits.

The condition for the maxima in Young’s experiment is given as follows.

dsinθ=mλ …… (1)

Here, d is the distance between the slits, λ is the wavelength, m is the order and θis the angular separation.

The expression to calculate the angular separation in degrees is given as follows.

θdeg=180π×θ …… (2)

03

Calculate the angular separation in radian:

a.

For the small angle, sinθθ.

Calculate the angular separation.

Substitute 7.7μm for d, 3 for m, 550 nm for λ, and θfor sinθinto equation (1).

7.7×10-6×θ=3×550×10-9

θ=3×550×10-97.7×10-6=1650×10-37.7=0.214rad

Hence, the angular separation in radian is 0.214rad.

04

Calculate the angular separation in degrees

Calculate the angular separation.

Substitute 0.214radfor θinto equation (2).

θdeg=180π×0.214=38.52π=12.28°

Hence,the angular separation in degrees is 12.28°.

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Most popular questions from this chapter

In Fig. 35-45, two microscope slides touch at one end and are separated at the other end. When light of wavelength 500 nm shines vertically down on the slides, an overhead observer sees an interference pattern on the slides with the dark fringes separated by 1.2 mm. What is the angle between the slides?

Transmission through thin layers. In Fig. 35-43, light is incident perpendicularly on a thin layer of material 2 that lies between (thicker) materials 1 and 3. (The rays are tilted only for clarity.) Part of the light ends up in material 3 as ray r3(the light does not reflect inside material 2) and r4(the light reflects twice inside material 2). The waves of r3and r4interfere, and here we consider the type of interference to be either maximum (max) or minimum (min). For this situation, each problem in Table 35-3 refers to the indexes of refraction n1,n2and n3, the type of interference, the thin-layer thickness L in nanometers, and the wavelength in nanometers of the light as measured in air. Where λis missing, give the wavelength that is in the visible range. Where Lis missing, give the second least thickness or the third least thickness as indicated.

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Does the spacing between fringes in a two-slit interference pattern increase, decrease, or stay the same if

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